All practice questions

13931 questions

Question 12381Question

Although irrigated paddy rice and sugarcane yield abundant harvests in the river floodplains (fadama) of Sokoto and Niger states, commercial perennial tree crops like cocoa and rubber cannot be successfully cultivated in these regions. Which environmental constraint primarily accounts for this agricultural boundary?

Show answer & explanation

Answer: The prolonged dry season and low atmospheric humidity in northern river basins exceed the ecological tolerance of rain forest tree crops.

Answer

The prolonged dry season and low atmospheric humidity in northern river basins exceed the ecological tolerance of rain forest tree crops.
Perennial tree crops like cocoa, oil palm, and rubber are strictly adapted to the tropical rainforest belt of southern Nigeria, requiring high annual rainfall exceeding 1,500 mm1,500\text{ mm} and high relative humidity throughout the year. While irrigation in northern floodplains (fadama lands) provides sufficient moisture for annual grain and vegetable crops like rice and sugarcane during their growing cycle, it cannot alter the prevailing low atmospheric humidity and extended dry season of the savanna belts, which inhibit tree crop development.

Step-by-Step Solution

1
Analyze the agricultural requirements of the crops mentioned in the scenario.
Paddy rice and sugarcane are annual or semi-perennial crops that can flourish in northern floodplains (fadama) if supplemental water is supplied via seasonal flooding or irrigation. Cocoa and rubber are permanent tree crops requiring persistent humid forest climates.
Understanding crop ecological limits distinguishes irrigated annual cropping from rain-fed tree crop belts.
2
Evaluate the climatic envelope of northern Nigeria (Sudan and Northern Guinea Savanna).
The region features a short wet season (35 months3\text{--}5\text{ months}), long dry season (79 months7\text{--}9\text{ months}), low relative humidity under the Influence of dry Harmattan winds, and annual rainfall well below 1,000 mm1,000\text{ mm}.
Climatic controls dictate the spatial limits of commercial tree crop belts across Nigerian ecological zones.
3
Identify why irrigation overcomes limits for grains/vegetables but not tree crops in northern zones.
Irrigation solves root water availability in river floodplains, but cannot compensate for low atmospheric humidity and extreme vapor pressure deficits that disrupt tree transpiration and physiological growth in cocoa and rubber.
This confirms atmospheric drought as the primary ecological barrier for rain forest tree crops in northern Nigeria.

Key Concept

Ecological controls on Nigerian crop belts and fadama agricultural systems
Estimated Time:2m 0s
Question 12382Question

Arrange the stages of barchan dune formation in an arid environment in sequential order from initial sand accumulation to the fully developed landform.

Drag items to arrange them in the correct order

Show answer & explanation

Answer

The correct sequence begins with sand encountering an obstacle and depositing, followed by the formation of a sand mound with a leeward slip face, the extension of lateral horns downwind by wind eddies, and finally the migration of a mature crescent-shaped barchan dune.
The correct sequence follows the physical progression of aeolian deposition: wind-blown sand first accumulates around an obstacle, forms an asymmetrical sand mound with a leeward slip face, develops two downwind-pointing horns as marginal sand moves faster than the center, and ultimately becomes a mobile crescent barchan dune.

Step-by-Step Solution

1
Identify the initial trigger for wind deposition.
Sand carried by saltation is trapped by an obstacle on the desert surface.
Aeolian deposition requires a physical barrier or reduction in wind energy.
2
Determine the initial structural dune development.
Sand accumulates into an asymmetrical mound with a gentle windward side and steep leeward slip face.
Sand accumulates on the windward slope and avalanches down the leeward side when it exceeds the angle of repose.
3
Trace the development of characteristic lateral features.
Lighter sand loads at the lateral margins move faster downwind, forming two pointed horns.
Eddy currents and lower resistance at the edges push the sides forward faster than the thick central core.
4
Identify the final landform state.
A fully formed crescent-shaped barchan dune migrates in the direction of the prevailing wind.
Ongoing wind action continually recycles sand over the crest, causing the entire dune to advance.

Key Concept

Barchan Dune Formation and Aeolian Deposition Processes
Question 12383Question

A cross-section is constructed from a topographic map drawn at a horizontal scale of 1:500001 : 50\,000. If the vertical scale of the cross-section is set such that 1 cm1\text{ cm} represents 100 m100\text{ m} of elevation, what is the vertical exaggeration of the cross-section?

Show answer & explanation

Answer: 5

Answer

The vertical exaggeration of the cross-section is 5.
To find the vertical exaggeration, both scales must be in representative fraction format. The horizontal scale is 1:500001 : 50\,000. The vertical scale (1 cm1\text{ cm} to 100 m100\text{ m}) equals 1:100001 : 10\,000. Dividing the horizontal denominator (5000050\,000) by the vertical denominator (1000010\,000) gives a vertical exaggeration of 5.

Step-by-Step Solution

1
Convert the vertical scale to representative fraction form
Vertical Scale = 1 : 10,000
Both scales must be expressed as dimensionless ratios (RF) in matching units to determine vertical enlargement.
2
Divide the horizontal scale denominator by the vertical scale denominator
VE = 50,000 / 10,000 = 5
Vertical exaggeration quantifies how many times larger the vertical scale is compared to the horizontal scale.

Key Concept

Vertical Exaggeration in Topographic Profiles
Question 12384Question

Arrange the following climatic zones of West Africa in sequential order based on the duration of their wet season, starting from the zone with the longest rainy season to the zone with the shortest rainy season:

Drag items to arrange them in the correct order

Show answer & explanation

Answer

The correct order from longest wet season duration to shortest is: Equatorial Coastal Belt, Guinea Savanna Belt, Sudan Savanna Belt, and Sahelian Semi-Arid Belt.
The correct sequence orders the climate belts from southern coastal West Africa to northern inland regions. The Equatorial Coastal Belt receives rain for 9 to 12 months due to persistent Maritime Tropical air. Moving north, the Guinea Savanna has a 7 to 9 month wet season, the Sudan Savanna experiences 4 to 6 months of rain, and the Sahelian Semi-Arid Belt receives only 2 to 3 months of brief seasonal rainfall.

Step-by-Step Solution

1
Examine the atmospheric driving force controlling West African rainfall
Rainfall duration across West Africa is determined by the seasonal latitude position of the Inter-Tropical Convergence Zone (ITCZ), which separates humid Maritime Tropical (mT) winds from dry Continental Tropical (cT) winds.
Locations closer to the coast remain under moist mT air longer, whereas inland locations spend most of the year under dry cT winds.
2
Determine the length of the rainy season for each climate zone moving inland
The Equatorial Coastal Belt has 9–12 rainy months; Guinea Savanna has 7–9 rainy months; Sudan Savanna has 4–6 rainy months; Sahelian Semi-Arid Belt has 2–3 rainy months.
The duration of mT air dominance decreases progressively as distance from the Atlantic coastline increases northward.
3
Sequence the items from longest rainy season to shortest rainy season
Equatorial Coastal Belt → Guinea Savanna Belt → Sudan Savanna Belt → Sahelian Semi-Arid Belt.
This establishes a clear environmental gradient from equatorial hyper-humid conditions at the coast to semi-arid conditions near the Sahara.

Key Concept

Latitudinal gradient of wet season duration and air mass dominance in West Africa
Question 12385Question

On a topographical map with a scale of 1:50,0001 : 50,000, two hilltops are located at elevations of 750 m750\text{ m} and 450 m450\text{ m} respectively. If the straight-line distance separating the two hilltops on the map is 6 cm6\text{ cm}, what is the average gradient between them?

Show answer & explanation

Answer: 1 in 101\text{ in }10

Answer

The average gradient between the two hilltops is 1 in 101\text{ in }10.
The vertical interval (VI) is the difference in elevation: 750 m450 m=300 m750\text{ m} - 450\text{ m} = 300\text{ m}. The horizontal equivalent (HE) is the ground distance: 6 cm×50,000=300,000 cm=3,000 m6\text{ cm} \times 50,000 = 300,000\text{ cm} = 3,000\text{ m}. The gradient is VIHE=3003,000=110\frac{\text{VI}}{\text{HE}} = \frac{300}{3,000} = \frac{1}{10}, expressed as 1 in 101\text{ in }10.

Step-by-Step Solution

1
Calculate the Vertical Interval (VI)
VI=750 m450 m=300 m\text{VI} = 750\text{ m} - 450\text{ m} = 300\text{ m}
Gradient requires the difference in elevation between the two specified points.
2
Calculate the Horizontal Equivalent (HE) on the ground in meters
HE=6 cm×50,000=300,000 cm=3,000 m\text{HE} = 6\text{ cm} \times 50,000 = 300,000\text{ cm} = 3,000\text{ m}
Map distance must be converted to actual ground distance using the representative fraction scale.
3
Calculate the gradient using the formula Gradient=VIHE\text{Gradient} = \frac{\text{VI}}{\text{HE}}
Gradient=300 m3,000 m=110\text{Gradient} = \frac{300\text{ m}}{3,000\text{ m}} = \frac{1}{10} or 1 in 101\text{ in }10
Dividing the vertical interval by the horizontal equivalent in identical units yields the ratio slope.

Key Concept

Topographic gradient calculation from map scale and elevation differences
Estimated Time:1m 30s
Question 12386Question

The Central African Copperbelt is recognized globally as one of the richest copper deposits in the world. Which two neighboring African nations span this major mineral mining belt?

Show answer & explanation

Answer: Zambia and the Democratic Republic of Congo

Answer

Zambia and the Democratic Republic of Congo
The Central African Copperbelt is a famous mineralized zone located along the border area between northern Zambia and the southern Democratic Republic of Congo (formerly Katanga Province). These two nations hold vast reserves of high-grade copper and cobalt.

Step-by-Step Solution

1
Identify the geographical region of the Central African Copperbelt.
The Copperbelt is situated in Central-Southern Africa.
Geological formations containing rich copper and cobalt deposits cross the boundary between Zambia and the Katanga province of the DRC.
2
Match the mineral belt with the correct producing countries.
Zambia and the Democratic Republic of Congo are the primary host nations for this major mineral zone.
This region makes both Zambia and the DRC leading copper and cobalt exporters in Africa.

Key Concept

Spatial distribution of major mineral resources and mining belts in Africa
Question 12387Question

In transport network analysis, topological connectivity for planar graphs can be evaluated using the Gamma index (γ\gamma), which compares the actual number of edges (ee) to the maximum possible number of edges (3(v2)3(v - 2)) for a given number of vertices (vv). If a regional highway network connecting 55 urban centers consists of 77 direct road links, what is the Gamma index of connectivity for this network?

Show answer & explanation

Answer: 79\frac{7}{9} (or approximately 0.780.78)

Answer

The Gamma index of connectivity is 79\frac{7}{9} (or approximately 0.780.78).
The Gamma index (γ\gamma) measures the degree of connectivity of a planar network on a scale from 00 to 11 (or 0%0\% to 100%100\%). For a planar graph with 55 vertices, the maximum possible number of direct edges without route intersection outside vertices is 3(52)=93(5 - 2) = 9. Given 77 actual edges, the ratio is 790.78\frac{7}{9} \approx 0.78.

Step-by-Step Solution

1
Identify the given network parameters
Number of vertices v=5v = 5 (urban centers) and number of edges e=7e = 7 (road links).
Topological network indices depend on counting nodes and direct links.
2
Calculate the maximum theoretical number of edges (emaxe_{\max}) for a planar graph
emax=3(v2)=3(52)=3×3=9e_{\max} = 3(v - 2) = 3(5 - 2) = 3 \times 3 = 9.
In planar transport network graphs (where routes cross only at nodes), the upper bound of edges is constrained by 3(v2)3(v - 2).
3
Compute the Gamma index (γ\gamma)
γ=eemax=790.78\gamma = \frac{e}{e_{\max}} = \frac{7}{9} \approx 0.78 (or 77.8%77.8\%).
The Gamma index is defined as the ratio of actual edges to maximum theoretical edges.

Key Concept

Gamma Index of Network Connectivity
Estimated Time:2m 0s
Question 12388Question

Which of the following landforms is formed in the upper course of a river primarily by active vertical erosion?

Show answer & explanation

Answer: V-shaped valley

Answer

V-shaped valley
In the upper course of a river, steep slopes cause rapid streamflow that drives energetic vertical erosion. As the river deepens its bed, weathering and mass wasting loosen materials along the sides, producing a steep-sided V-shaped valley profile.

Step-by-Step Solution

1
Identify the dominant river process and course stage
The upper course stage features steep gradients, fast flow velocity, and downward channel incision (vertical erosion).
River kinetic energy in the upper course is mainly directed toward deepening the valley bed.
2
Determine the resulting morphological feature
Deepening of the stream bed combined with weathering of upper valley sides produces a narrow V-shaped valley.
Vertical hydraulic action and corrasion cut downward while mass movement slumps the valley slopes inward.

Key Concept

Upper river course erosion and landform development
Question 12389Question

Match each natural resource listed on the left with its corresponding availability and replenishment characteristic on the right.

Click a left item, then click its matching right item

Items

Solar Radiation
Natural Gas Deposits
Forest Timber
Iron Ore Deposits

Matches

Show answer & explanation

Answer

Solar Radiation matches continuous flow resource replenishment; Natural Gas Deposits matches non-renewable organic fossil fuel; Forest Timber matches potentially renewable biological resource; Iron Ore Deposits matches non-renewable inorganic metallic mineral.
Solar energy is continuous and inexhaustible. Natural gas is a finite fossil fuel formed over millions of years. Forest timber is biological and renewable if harvested sustainably within its growth capacity. Iron ore is a fixed metallic mineral stock that can be recycled to prolong usability.

Step-by-Step Solution

1
Identify perpetual energy sources vs finite resources
Solar Radiation is classified as an inexhaustible, continuously available flow resource.
Sunlight availability is governed by solar flux, independent of human consumption rates.
2
Differentiate organic non-renewable resources from inorganic mineral reserves
Natural Gas is an organic fossil hydrocarbon formed over geological eras, while Iron Ore is a finite metallic mineral deposit.
Fossil fuels regenerate over millions of years, far beyond human management timescales.
3
Evaluate biological resource regeneration conditions
Forest Timber is renewable provided reforestation balances deforestation.
Living biological resources regenerate within human lifespans if managed under sustainable yield practices.

Key Concept

Classification of Natural Resources by Renewability and Rate of Replenishment
Question 12390Question

On Map X, drawn at a scale of 1:25,0001 : 25,000, a planned agricultural settlement occupies a square grid block measuring 4 cm4\text{ cm} by 4 cm4\text{ cm}. Map X is reduced to produce Map Y such that the same agricultural settlement occupies a reduced area of 1 cm21\text{ cm}^2. What is the Representative Fraction (R.F.) scale of Map Y?

Show answer & explanation

Answer: 1:100,0001 : 100,000

Answer

The Representative Fraction scale of Map Y is 1:100,0001 : 100,000.
The original grid block has an area of 16 cm216\text{ cm}^2 on Map X. Since the reduced area on Map Y is 1 cm21\text{ cm}^2, the area reduction factor is 1616. The linear reduction factor is the square root of the area factor, which is 16=4\sqrt{16} = 4. Reducing linear dimensions by a factor of 44 makes the map scale smaller by a factor of 44, increasing the scale denominator from 25,00025,000 to 100,000100,000. Thus, Map Y has a scale of 1:100,0001 : 100,000.

Step-by-Step Solution

1
Calculate the original area of the settlement on Map X.
Area on Map X=4 cm×4 cm=16 cm2\text{Area on Map X} = 4\text{ cm} \times 4\text{ cm} = 16\text{ cm}^2.
Map area for a rectangular or square feature is length multiplied by width.
2
Determine the area scale change ratio.
\text{Area Ratio} = \frac{\text{Area on Map Y}}{\text{Area on Map X}} = \frac{1\text{ cm}^2}{16\text{ cm}^2} = \frac{1}{16}.
Area scale ratio is the ratio of final map area to initial map area.
3
Determine the linear scale reduction factor.
\text{Linear Factor} = \sqrt{\frac{1}{16}} = \frac{1}{4}.
Linear scale factor is the square root of the area scale factor (n=n2n = \sqrt{n^2}).
4
Calculate the new Representative Fraction scale denominator for Map Y.
\text{New Scale Denominator} = 25,000 \times 4 = 100,000 \Rightarrow \text{Scale of Map Y} = 1 : 100,000.
When a map is reduced, its scale denominator increases proportionally by the reciprocal of the linear scale factor.

Key Concept

Relationship between linear scale factor and area scale factor in map reduction
Estimated Time:2m 0s
Question 12391Question

In Karst geomorphology, subterranean dissolution of limestone leads to distinct underground and surface landforms. Arrange the following stages of subterranean cavern and collapse feature evolution in their correct chronological order from earliest to latest.

Drag items to arrange them in the correct order

Show answer & explanation

Answer

The correct sequence begins with carbonated water percolating through joints, followed by fracture widening into conduit networks, horizontal cavern development at the water table, speleothem deposition and column growth, and culminates in roof collapse forming karst windows.
The sequence correctly reflects the geomorphological progression from microscopic chemical infiltration of carbonated water into limestone joints, through sub-surface conduit and cavern chamber dissolution at the water table, followed by speleothem dripstone growth inside aerated caverns, ending with cavern roof breakdown resulting in karst windows.

Step-by-Step Solution

1
Identify the initial chemical weathering action.
Rainwater absorbing carbon dioxide forms weak carbonic acid that infiltrates limestone bedding planes and vertical joints.
Chemical dissolution cannot occur underground without initial acidic water entry into rock fractures.
2
Trace the subterranean conduit formation.
Acidic groundwater widens joints and bedding planes into vertical shafts and narrow conduit networks.
Initial dissolution follows structural weaknesses before forming large subterranean chambers.
3
Determine cavern chamber creation at the water table.
Lateral water movement at the phreatic boundary dissolves massive subterranean chambers.
Horizontal flow at the water table concentrates dissolution laterally rather than vertically.
4
Sequence the secondary depositional speleothem features.
Degassing of carbon dioxide in subterranean air spaces deposits calcite stalactites, stalagmites, and coalescing columns.
Depositional dripstone features require air-filled cavern vaults created during water table lowering or vadose flow.
5
Identify the final structural collapse landform stage.
Cavern roof collapse exposes the subterranean river flow as a karst window or collapsed sinkhole gorge.
Extreme underground enlargement coupled with roof thinning causes mechanical instability and ceiling breakdown.

Key Concept

Subterranean cavern evolution and cave roof collapse dynamics in karst topography
Estimated Time:2m 0s
Question 12392Question

Match each river basin morphometric parameter with its corresponding quantitative definition and hydrological significance.

Click a left item, then click its matching right item

Items

Bifurcation Ratio (RbR_b)
Drainage Density (DdD_d)
Stream Frequency (FsF_s)
Form Factor (RfR_f)

Matches

Show answer & explanation

Answer

Bifurcation Ratio (RbR_b) pairs with the ratio of stream numbers between successive orders (Nu/Nu+1N_u / N_{u+1}). Drainage Density (DdD_d) pairs with the total stream length divided by basin area. Stream Frequency (FsF_s) pairs with the total number of stream segments per unit basin area. Form Factor (RfR_f) pairs with the ratio of basin area to the square of basin length.
Each morphometric parameter correctly maps to its distinct mathematical definition and hydrological role: Bifurcation Ratio relates channel counts across orders (Nu/Nu+1N_u / N_{u+1}); Drainage Density measures stream length per area (L/A\sum L / A); Stream Frequency measures individual stream counts per area (N/AN / A); and Form Factor evaluates areal shape (A/L2A / L^2).

Step-by-Step Solution

1
Identify the formula and definition for Bifurcation Ratio (RbR_b)
Bifurcation Ratio is defined as Rb=NuNu+1R_b = \frac{N_u}{N_{u+1}}, representing the ratio between stream segment counts of order uu and order u+1u+1.
This establishes the relationship between successive stream orders in Strahler's morphometric ordering.
2
Identify the formula and definition for Drainage Density (DdD_d)
Drainage Density is defined as Dd=LAD_d = \frac{\sum L}{A}, where L\sum L is the total channel length and AA is the total basin area.
It quantifies channel spacing and regional runoff dynamics per unit area.
3
Identify the formula and definition for Stream Frequency (FsF_s)
Stream Frequency is defined as Fs=NAF_s = \frac{N}{A}, counting the number of stream channels (NN) per unit area (AA).
It expresses channel density in terms of individual segment counts rather than channel length.
4
Identify the formula and definition for Form Factor (RfR_f)
Form Factor is calculated as Rf=AL2R_f = \frac{A}{L^2}, comparing basin area to the square of maximum basin length.
It measures circularity versus elongation of a river basin to predict flood hydrograph shapes.

Key Concept

Morphometric Analysis of River Basins
Question 12393Question

Geophysical and structural evaluations of the Earth distinguish between compositional layers (crust, mantle, core) and mechanical zones (lithosphere, asthenosphere). Which of the following statements accurately characterizes the compositional and structural relationships between the continental crust, oceanic crust, and the underlying mantle zones?

Show answer & explanation

Answer: The continental crust (sial) is predominantly granitic and lighter than the continuous basaltic layer (sima), which forms the oceanic floor and rests above the plastic asthenosphere.

Answer

The continental crust (sial) is predominantly granitic and lighter than the continuous basaltic layer (sima), which forms the oceanic floor and rests above the plastic asthenosphere.
The continental crust (sial) is rich in silica and aluminium, making it less dense and predominantly granitic. It sits upon the denser, continuous basaltic layer rich in silica and magnesium (sima), which underlies ocean basins and overlies the partially molten, ductile asthenosphere in the upper mantle.

Step-by-Step Solution

1
Analyze Earth's crustal composition
Sial (silica-aluminium, granitic) forms continental blocks with lower density (~2.7 g/cm³), while Sima (silica-magnesium, basaltic) forms oceanic crust and underlying basement with higher density (~3.0 g/cm³).
Establishing correct density and composition relationships between sial and sima.
2
Evaluate mantle mechanical zone relationship
The rigid lithosphere (crust + upper mantle) floats and moves over the ductile, semi-fluid asthenosphere.
Connecting compositional layers to mechanical behavior.
3
Eliminate options containing geological process misconceptions
Distractors confuse surface weathering with mass movement or igneous/metamorphic rock formation with sedimentary processes.
Validating the unique accuracy of the correct option.

Key Concept

Earth's Internal Structure (Sial, Sima, Lithosphere, and Asthenosphere)
Estimated Time:1m 30s
Question 12394Question

Block disintegration is a mechanical weathering process prevalent in arid desert regions. What is the correct chronological sequence of steps in the breakdown of rocks by block disintegration?

Drag items to arrange them in the correct order

Show answer & explanation

Answer

The correct sequence begins with daytime thermal expansion of the rock, followed by nighttime thermal contraction, leading to repeated stress along joints, and culminating in the rock fracturing into angular blocks.
Block disintegration occurs due to large diurnal temperature variations in arid regions. Heating during the day leads to expansion, while cooling at night leads to contraction. Over time, these recurring cycles generate stresses along joint lines, eventually causing the rock to fragment into large rectangular or angular blocks in-situ.

Step-by-Step Solution

1
Identify the initial thermal trigger in desert weathering.
Intense solar radiation during the day causes the rock to absorb heat and expand.
Rocks are poor conductors of heat, so daytime heating affects the outer layers first, causing localized expansion.
2
Determine the atmospheric response during the night.
Clear skies in arid regions lead to rapid nocturnal cooling, causing the expanded rock to contract.
Desert environments experience high diurnal temperature ranges.
3
Analyze the long-term mechanical impact of these temperature fluctuations.
Alternating expansion and contraction create differential stress along joint planes.
Repeated mechanical stress weakens the structural integrity of the rock along existing joints.
4
Identify the final physical outcome of the process.
The rock mass completely separates into distinct angular blocks.
When stress exceeds the strength of the rock, complete disintegration occurs along the joints.

Key Concept

Thermal expansion and contraction (block disintegration) in physical weathering
Question 12395Question

In urban geography, classic land-use models like the Burgess Concentric Zone Model often fail to accurately reflect the spatial growth of rapidly growing cities in developing regions. Which of the following structural factors best explains why informal squatter settlements in developing metropolitan areas predominantly form on the urban periphery rather than within the inner-city transitional zone?

Show answer & explanation

Answer: Extremely high land values and commercial gentrification in the central core force low-income rural migrants onto unmonitored peripheral lands where land enforcement is weak.

Answer

Extremely high land values and commercial gentrification in the central core force low-income rural migrants onto unmonitored peripheral lands where land enforcement is weak.
The correct answer highlights that high commercial land prices in the urban center, combined with weak regulatory monitoring at the urban fringe, drive low-income migrants to establish informal settlements on inexpensive peripheral land.

Step-by-Step Solution

1
Analyze classic urban land-use assumptions versus developing world urban realities.
Burgess's model assumes inner-city zones of transition host cheap housing for new migrants, whereas modern developing cities feature high central business district (CBD) commercial land values and gentrification.
Understanding land market dynamics explains why migrants cannot afford central locations.
2
Evaluate peripheral land dynamics in rapidly expanding metropolitan areas.
Outer peripheral lands feature lower market values and weaker municipal zoning enforcement, making them vulnerable to spontaneous informal land occupation by low-income populations.
Explaining the spatial location of peripheral informal settlements.

Key Concept

Urban Land-Use Dynamics and Peripheral Informal Settlements
Question 12396Question

Different agricultural crops in Nigeria are adapted to distinct ecological zones based on their moisture requirements. Arrange the following crops in sequence based on their mean annual rainfall requirements, starting from the crop with the highest rainfall requirement to the crop with the lowest rainfall requirement.

Drag items to arrange them in the correct order

Show answer & explanation

Answer

The correct sequence from highest to lowest annual rainfall requirement is Oil Palm, Cocoa, Cotton, and Millet.
Oil palm requires the highest annual rainfall (over 2,000 mm) in the coastal/rainforest zone, followed by cocoa in the rainforest belt (1,250–1,800 mm), cotton in the Guinea/Sudan savanna (700–1,000 mm), and millet with the lowest requirement in the semi-arid northern savanna (400–700 mm).

Step-by-Step Solution

1
Identify the ecological zones and moisture requirements of each crop in Nigeria.
Oil Palm requires humid tropical conditions (>2,000 mm/year); Cocoa requires moist rainforest conditions (1,250-1,800 mm/year); Cotton requires sub-humid savanna conditions (700-1,000 mm/year); Millet requires semi-arid savanna conditions (400-700 mm/year).
Crop distribution in Nigeria is primarily governed by the south-to-north gradient of decreasing annual rainfall.
2
Order the crops starting from the highest rainfall requirement down to the lowest rainfall requirement.
Sequence: Oil Palm → Cocoa → Cotton → Millet.
This reflects the latitudinal shift in Nigerian agricultural systems from coastal rainforest cash crops to far northern savanna grain crops.

Key Concept

Latitudinal gradient of moisture requirements for Nigerian agricultural crops
Question 12397Question

Which vegetation zone occupies the largest geographical extent in Nigeria and is characterized by tall grasses interspersed with scattered, fire-resistant broad-leaved trees such as the shea butter tree and locust bean?

Show answer & explanation

Answer: Guinea Savanna

Answer

Guinea Savanna is the largest vegetation belt in Nigeria, characterized by tall grasses and fire-resistant trees.
The Guinea Savanna is Nigeria's most extensive vegetation zone, spanning the central states (Middle Belt). It is dominated by tall grasses (1.5 m3 m1.5\text{ m} - 3\text{ m}) interspaced with deciduous, fire-resistant trees such as *Vitellaria paradoxa* (shea butter) and *Parkia biglobosa* (locust bean).

Step-by-Step Solution

1
Identify spatial coverage and physical traits described in the stem.
The stem describes the largest vegetation belt in Nigeria with tall grasses and fire-resistant tree species like shea butter and locust bean.
Matching spatial extent and indicator species narrows down the specific vegetation belt.
2
Compare features across Nigerian vegetation belts.
The Guinea Savanna (consisting of Southern and Northern sub-zones) occupies nearly 50% of Nigeria's landmass across the Middle Belt region.
Guinea Savanna receives moderate annual rainfall (1000 mm1500 mm1000\text{ mm} - 1500\text{ mm}), creating ideal ecological conditions for tall grasses and thick-barked, fire-adapted trees.

Key Concept

Guinea Savanna characteristics and spatial distribution in Nigeria
Question 12398Question

A manufacturing plant requires 3 tonnes3\text{ tonnes} of localized raw material to produce 1 tonne1\text{ tonne} of finished product. The raw material deposit and the market are separated by a distance of 100 km100\text{ km}. Transport costs are $2.00 per tonne-km\$2.00\text{ per tonne-km} for raw materials and $3.00 per tonne-km\$3.00\text{ per tonne-km} for finished goods. An alternative production site, Location L, offers a labor cost savings of $400.00\$400.00 per tonne of finished product, but increases the transportation distance of raw materials by 30 km30\text{ km} and finished goods by 10 km10\text{ km} compared to the least-cost transport point. Based on Alfred Weber's location theory, what is the net financial gain or loss per tonne of finished product if the plant relocates to Location L?

Show answer & explanation

Answer: A net gain of $190.00\$190.00, indicating that Location L lies within the critical isodapane and is economically optimal.

Answer

A net gain of $190.00\$190.00 per tonne of finished product, placing Location L inside the critical isodapane.
According to Alfred Weber's Industrial Location Theory, the least-cost transport location for a weight-losing industry (MI=3>1MI = 3 > 1) is at the raw material origin, where moving input costs $6.00/km\$6.00/\text{km} versus $3.00/km\$3.00/\text{km} for output. Moving production to Location L adds $180.00\$180.00 in raw material transport (3 tonnes×$2.00×30 km3\text{ tonnes} \times \$2.00 \times 30\text{ km}) and $30.00\$30.00 in finished goods transport (1 tonne×$3.00×10 km1\text{ tonne} \times \$3.00 \times 10\text{ km}), totaling $210.00\$210.00 extra transport costs. Because the labor savings ($400.00\$400.00) exceeds the additional transport expense ($210.00\$210.00), Location L yields a net savings of $190.00\$190.00 per tonne and lies inside the critical isodapane.

Step-by-Step Solution

1
Determine the least-cost transport location
Transport cost per km for raw material assembly = 3 tonnes×$2.00/tonne-km=$6.00/km3\text{ tonnes} \times \$2.00/\text{tonne-km} = \$6.00/\text{km}. Transport cost per km for finished goods distribution = 1 tonne×$3.00/tonne-km=$3.00/km1\text{ tonne} \times \$3.00/\text{tonne-km} = \$3.00/\text{km}. Since assembly cost per km exceeds distribution cost per km, the least-cost transport location is at the raw material deposit.
Weber's theory dictates that when the Material Index is greater than 1 (MI=3/1=3MI = 3/1 = 3), manufacturing is weight-losing and least-cost transport points favor raw material sites.
2
Calculate additional transportation costs incurred by moving to Location L
Additional raw material transport cost = 3 tonnes×$2.00/tonne-km×30 km=$180.003\text{ tonnes} \times \$2.00/\text{tonne-km} \times 30\text{ km} = \$180.00. Additional finished goods transport cost = 1 tonne×$3.00/tonne-km×10 km=$30.001\text{ tonne} \times \$3.00/\text{tonne-km} \times 10\text{ km} = \$30.00. Total additional transport cost = \180.00+$30.00=$210.00180.00 + \$30.00 = \$210.00.
Deviating from the optimal transport location increases movement costs for both input and output.
3
Compute net financial impact incorporating cheap labor savings
Net financial advantage = Labor cost savings - Total additional transport cost = \400.00$210.00=+$190.00 per tonne400.00 - \$210.00 = +\$190.00\text{ per tonne}.
If labor savings exceed the additional transport costs, the factory relocates to the labor site (Location L lies within the critical isodapane).

Key Concept

Weber's Least Cost Theory: Critical Isodapane and Labor Deviation
Question 12399Question

In many rapidly growing metropolitan areas in developing nations, severe morning traffic gridlock routinely occurs along major arterial roads leading into the city center. This phenomenon is largely caused by tidal commuting movements from distant residential suburbs to central commercial districts. Which of the following urban spatial planning issues is the primary structural driver of this daily traffic congestion?

Show answer & explanation

Answer: Functional segregation of urban land uses, which concentrates commercial employment in the central business district while residential developments expand peripherally.

Answer

Functional segregation of urban land uses, which concentrates commercial employment in the central business district while residential developments expand peripherally.
Functional segregation separates residential areas from commercial and industrial employment zones. When jobs are concentrated in the central business district and housing expands peripherally, workers must travel long distances along the same routes at the same times, resulting in severe tidal traffic congestion.

Step-by-Step Solution

1
Analyze the observed urban problem
Identified severe daily traffic gridlock caused by unidirectional peak-hour commuting (tidal commuting) from suburbs to the central core.
Understanding the spatio-temporal flow of urban commuters helps identify the spatial structure underlying the traffic problem.
2
Evaluate urban land-use principles
Recognized that when cities lack mixed land-use planning, commercial and employment functions remain centralized while housing moves to the periphery.
Functional segregation forces residents to travel long distances simultaneously to access employment nodes, overwhelming transit corridors.
3
Select the correct spatial driver
Concluded that functional land-use separation is the main structural cause of tidal commuting and traffic congestion.
Integrating land uses (mixed-use planning) reduces commuting distance and distributes traffic more evenly across urban space.

Key Concept

Functional Land-Use Segregation and Urban Traffic Congestion
Question 12400Question

Match each population theory or growth concept in Column A with its corresponding core demographic principle in Column B.

Click a left item, then click its matching right item

Items

Malthusian Population Theory
Optimum Population Concept
Neo-Malthusian Theory
Demographic Dividend

Matches

Show answer & explanation

Answer

Malthusian Population Theory matches the principle of exponential population growth versus linear food supply growth. Optimum Population Concept matches the state yielding maximum per capita output given available resources and technology. Neo-Malthusian Theory matches modern advocacy for contraception and resource sustainability. Demographic Dividend matches economic growth resulting from a shift toward a larger working-age population proportion.
Each population concept is matched with its accurate defining principle: Malthusian theory explains geometric population growth against arithmetic food expansion; Optimum population represents maximum per capita output; Neo-Malthusian theory advocates birth control and resource sustainability; and Demographic dividend represents economic benefit from a favorable working-age population structure.

Step-by-Step Solution

1
Identify the foundational tenet of Thomas Malthus's population essay.
Malthus posited that human population expands exponentially (geometrically) while food production increases linearly (arithmetically).
This establishes the classic imbalance between population growth rate and food supply capabilities.
2
Define the equilibrium target of optimum population.
Optimum population occurs when resource development and technological efficiency yield maximum per capita economic return.
It distinguishes underpopulation and overpopulation states relative to resource efficiency.
3
Examine the modern adaptation under Neo-Malthusian theory.
Neo-Malthusians adapt Malthusian concerns to contemporary environmental limits, promoting active family planning and resource management.
It highlights proactive human intervention rather than relying solely on positive checks like war or famine.
4
Analyze the demographic structure required for a demographic dividend.
A demographic dividend occurs when falling fertility lowers youth dependency, expanding the working-age population relative to non-working dependents.
It links age structure transition directly to economic growth opportunities.

Key Concept

Population Theories, Demographic Models, and Growth Dynamics
PreviousPage 620 / 697Next
All practice questions — JAMB UTME | Examkin