Ecology

227 questions

Question 101Question

Arrange the following microbial and biochemical transformations of nitrogen in sequential order, beginning with the fixation of atmospheric dinitrogen (N2N_2) gas by symbiotic root nodule bacteria and ending with the release of gaseous dinitrogen back into the atmosphere.

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Answer

The correct sequence of transformations is: (1) Reduction of atmospheric dinitrogen gas (N2N_2) by symbiotic *Rhizobium* inside root nodules, followed by (2) Decomposition of organic nitrogen wastes into ammonium ions (NH4+NH_4^+) by ammonifying saprophytes, then (3) Oxidation of ammonium ions (NH4+NH_4^+) to nitrite (NO2NO_2^-) by *Nitrosomonas*, followed by (4) Oxidation of nitrite (NO2NO_2^-) to nitrate (NO3NO_3^-) by *Nitrobacter*, and finally (5) Reduction of soil nitrates (NO3NO_3^-) to dinitrogen gas (N2N_2) by *Pseudomonas* under anaerobic conditions.
The biological nitrogen cycle begins with nitrogen fixation by *Rhizobium*, which converts inert atmospheric dinitrogen (N2N_2) into organic amino acids and proteins in legumes. Upon plant death or excretion, ammonifying decomposers convert organic nitrogen into ammonium ions (NH4+NH_4^+). Two-step nitrification follows: first, *Nitrosomonas* oxidizes ammonium to nitrite (NO2NO_2^-), and second, *Nitrobacter* oxidizes nitrite to nitrate (NO3NO_3^-). Finally, anaerobic *Pseudomonas* carries out denitrification, reducing nitrates back to atmospheric dinitrogen gas (N2N_2), completing the cycle.

Step-by-Step Solution

1
Identify the initial process fixing elemental nitrogen gas (N2N_2) into biological systems.
Symbiotic fixation by *Rhizobium* in root nodules converts gaseous N2N_2 into organic nitrogen compounds.
Atmospheric nitrogen cannot be directly utilized by plants without biological fixation by specialized prokaryotes.
2
Trace the movement of organic nitrogen through biological consumption and excretion to ammonification.
Saprophytic bacteria and fungi break down organic nitrogen compounds into inorganic ammonium ions (NH4+NH_4^+).
Ammonification is necessary to release bound organic nitrogen from dead tissues and excretions back into soil ionic forms.
3
Determine the first step of nitrification.
Chemoautotrophic *Nitrosomonas* bacteria oxidize ammonium ions (NH4+NH_4^+) to nitrite ions (NO2NO_2^-).
Nitrification proceeds in two distinct obligate stages, starting with ammonium oxidation.
4
Determine the second step of nitrification.
*Nitrobacter* bacteria oxidize toxic nitrite ions (NO2NO_2^-) into bioavailable nitrate ions (NO3NO_3^-).
Nitrate is the chief chemical form of nitrogen absorbed and assimilated by terrestrial plants.
5
Identify the closing pathway of the cycle returning nitrogen to the gaseous state.
Anaerobic denitrifying bacteria such as *Pseudomonas* reduce nitrates (NO3NO_3^-) back into atmospheric dinitrogen gas (N2N_2).
Denitrification prevents complete accumulation of soil nitrates and restores atmospheric dinitrogen balance.

Key Concept

Biogeochemical Nitrogen Cycle Transformation Pathway
Estimated Time:1m 30s
Question 102Question

Match each ecological pyramid structural characteristic or anomaly on the left with its correct ecological or thermodynamic explanation on the right.

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Items

Inverted biomass pyramid in open-ocean marine ecosystems
Strictly upright energy pyramid across all natural ecosystems
Inverted pyramid of numbers in a temperate forest tree habitat
Upright biomass pyramid in a climax grassland ecosystem

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Answer

Inverted marine biomass pyramid pairs with rapid turnover of phytoplankton; strictly upright energy pyramid pairs with second law of thermodynamics energy dissipation; inverted forest tree numbers pyramid pairs with a single large producer supporting many smaller organisms; and upright grassland biomass pyramid pairs with high standing crop biomass.
Each ecological pyramid structural phenomenon directly reflects how standing crop measurements, turnover rates, or thermodynamic energy dissipation shape the trophic structure of ecosystems.

Step-by-Step Solution

1
Analyze the inverted biomass pyramid in marine environments
Phytoplankton reproduce and are consumed rapidly, resulting in low standing crop biomass at any instant but high productivity, creating an inverted biomass pyramid.
Measures of standing crop biomass at a single moment differ from total energy production over time.
2
Analyze why energy pyramids are strictly upright
Energy transfer between trophic levels is inefficient (typically around 10%), as heat energy is lost via respiration (Second Law of Thermodynamics).
Energy cannot be recycled or inverted because total usable energy strictly decreases at each successive trophic level.
3
Analyze inverted numbers pyramid in a tree habitat
Physical size of individual organisms dictates the count; one massive oak tree supports thousands of caterpillars or birds.
Pyramids of numbers count individual organisms rather than biomass or energy content.
4
Analyze upright terrestrial biomass pyramid
Grasses and plants accumulate substantial structural plant matter, yielding a high standing crop biomass compared to herbivores.
Terrestrial producers have longer lifespans and lower turnover rates compared to aquatic phytoplankton.

Key Concept

Thermodynamics and Trophic Structure of Ecological Pyramids
Question 103Question

Match each ecosystem component or ecological factor on the left with its correct description on the right.

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Items

Biotic Factor
Abiotic Factor
Primary Producer
Decomposer

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Answer

Biotic Factor matches living organism that affects an ecosystem; Abiotic Factor matches non-living physical or chemical element; Primary Producer matches autotrophic organism capable of manufacturing organic food; Decomposer matches saprophytic organism that breaks down dead organic matter.
Each ecological concept is matched directly to its definition: Biotic Factor describes living components; Abiotic Factor describes non-living environmental elements; Primary Producer describes autotrophic organisms synthesizing organic food; and Decomposer describes saprophytic organisms recycling organic waste.

Step-by-Step Solution

1
Identify the definition of living vs non-living ecosystem factors.
Biotic refers to living components (plants, animals, microbes), while Abiotic refers to non-living physical components (light, temperature, soil pH).
Ecosystem structure is broadly split into biotic (living) and abiotic (non-living) parts.
2
Determine the role of food-producing organisms.
Primary producers generate organic nutrients via autotrophic processes like photosynthesis.
Producers convert solar energy into chemical energy stored in organic molecules.
3
Determine the role of organisms responsible for nutrient recycling.
Decomposers break down dead tissue and return simple nutrients back into the ecosystem.
Saprophytic action prevents organic matter build-up and closes the biogeochemical cycle.

Key Concept

Components and Structural Organization of an Ecosystem
Question 104Question

Match each ecological structural term on the left with its corresponding definition on the right.

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Items

Ecotone
Microhabitat
Saprotroph
Ecological Guild

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Answer

Ecotone matches the transitional boundary zone between distinct biological communities; Microhabitat matches the localized small-scale physical area with distinct microclimate; Saprotroph matches the heterotrophic organism absorbing nutrients from dead organic substrate; Ecological Guild matches the group of species exploiting the same resources in a similar manner.
Each ecological term correctly pairs with its definitive structural role or spatial unit in ecosystem organization: Ecotone is the transition zone, Microhabitat is the localized physical area, Saprotroph is the decomposer organism absorbing dissolved decay products, and Ecological Guild describes species sharing a resource utilization strategy.

Step-by-Step Solution

1
Analyze the term 'Ecotone'
Identify that 'ecotone' refers to boundary zones where two ecosystems meet and overlap.
The term describes transitional gradient areas between distinct plant and animal communities.
2
Analyze the term 'Microhabitat'
Connect 'microhabitat' to small-scale physical locations with specific microclimatic features.
Sub-environments like crevices in rocks or leaf litter are classic examples of microhabitats.
3
Analyze the term 'Saprotroph'
Associate saprotrophic nutrition with extracellular digestion of decaying organic matter.
Saprotrophs break down dead organic matter and absorb soluble nutrients directly.
4
Analyze the term 'Ecological Guild'
Match 'guild' with species occupying overlapping functional roles or resource utilization tactics.
Guild members share functional niches within a community regardless of phylogenetic distance.

Key Concept

Ecosystem Structure and Ecological Terminology
Question 105Question

Match each ecological pyramid concept on the left with its correct biological or structural feature on the right.

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Items

Pyramid of Energy
Aquatic Pyramid of Biomass
Parasitic Pyramid of Numbers
Ten Percent Law

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Answer

Pyramid of Energy matches with 'Always remains upright across all natural ecosystems because energy dissipates as heat at each successive trophic step.' Aquatic Pyramid of Biomass matches with 'Features an inverted structure where the producer level has a smaller standing crop than primary consumers due to rapid turnover.' Parasitic Pyramid of Numbers matches with 'Exhibits an inverted shape starting from a single host supporting numerous individuals at progressively higher trophic levels.' Ten Percent Law matches with 'Quantifies the average proportion of energy converted into biomass and transferred to the next higher trophic level.'
Each ecological concept correctly matches its underlying biological rule: the pyramid of energy is universally upright due to metabolic heat loss; the aquatic biomass pyramid can invert due to rapid producer turnover; parasitic numerical pyramids invert due to host-parasite population ratios; and the ten percent law defines ecological energy transfer efficiency.

Step-by-Step Solution

1
Analyze the thermodynamic properties of energy flow.
Energy transfer is unidirectional and governed by thermodynamic loss, meaning a pyramid of energy can never be inverted and is always upright.
Identify the fundamental physical law governing energy flow.
2
Examine ecosystem-specific biomass dynamics.
Open-water aquatic systems exhibit inverted biomass pyramids due to high photosynthetic turnover rates of microscopic producers.
Distinguish standing crop biomass from energy productivity.
3
Evaluate trophic structure in parasitic food chains.
A single host organism harbouring hundreds of ecto- or endoparasites creates an inverted pyramid of numbers.
Recognize numerical population distributions across specialized trophic roles.
4
Associate numerical transfer efficiency rules with ecological principles.
The ten percent law specifically defines ecological efficiency between trophic tiers.
Match numerical energetic transfer definitions with their scientific names.

Key Concept

Trophic dynamics, energetic decay, and structural variations in ecological pyramids
Question 106Question

An ecologist set up a standard rain gauge to record precipitation in a tropical grassland ecosystem over a one-month period. Which of the following procedural precautions is essential to obtain accurate rainfall measurements?

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Answer: Positioning the instrument in an open site clear of tall trees and overhead structures

Answer

Positioning the instrument in an open site clear of tall trees and overhead structures is essential to obtain accurate rainfall measurements.
Positioning the rain gauge in an open area away from tall vegetation and buildings ensures that the funnel collects only direct atmospheric precipitation without interception by leaves or splash-in from surrounding structures.

Step-by-Step Solution

1
Identify the ecological factor and instrument described in the scenario
The instrument is a rain gauge used to measure rainfall (a key climatic factor).
Rainfall volume is expressed in millimeters of depth collected over a specified surface area.
2
Evaluate potential sources of error in rain gauge placement
Overhanging vegetation intercepts rain, while ground-level placement allows splash-in of surface water.
Accurate precipitation measurements require collecting only direct vertical rainfall without obstruction or extraneous runoff.
3
Select the correct precaution that minimizes sampling error
Elevating the funnel above ground level in an open area ensures direct catch of rainfall.
This standardized positioning prevents both canopy interception errors and ground splash contamination.

Key Concept

Operating Principles and Precautions for Ecological Measuring Instruments
Question 107Question

Match each type of ecological succession or community stage in List I with its correct environmental context or characteristic in List II.

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Items

Hydrosere
Xerosere
Secondary succession
Climax community

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Answer

Hydrosere pairs with succession starting in an aquatic habitat; Xerosere pairs with succession originating on dry bare rock; Secondary succession pairs with succession developing on pre-existing soil after a disturbance; Climax community pairs with the final stable and self-sustaining stage.
Hydrosere represents succession starting in aquatic habitats, Xerosere represents succession starting on dry bare rock, Secondary succession occurs on pre-existing soil after a disturbance, and Climax community represents the final stable stage of ecological succession.

Step-by-Step Solution

1
Identify the environmental medium indicated by the terms hydrosere and xerosere.
Hydrosere originates in water (aquatic body), while xerosere originates on dry substrate (bare rock).
The prefix 'hydro-' denotes water habitats and 'xero-' denotes dry or arid conditions.
2
Distinguish secondary succession from primary succession types.
Secondary succession is paired with pre-existing soil after a disturbance.
Unlike primary successions (hydrosere/xerosere) that start on bare substrates, secondary succession relies on soil that remains intact after disturbance.
3
Identify the characteristic of a climax community.
Climax community matches the final stable and self-sustaining stage.
Succession reaches dynamic equilibrium when the climax community comes into balance with regional climate.

Key Concept

Classification and environmental contexts of ecological succession stages (hydrosere, xerosere, secondary succession, climax community)
Question 108Question

A biological study of a freshwater lake ecosystem recorded the trophic interactions among several species. Arrange the following organisms in sequence from the HIGHEST available energy content to the LOWEST available energy content.

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Answer

The correct sequence from highest to lowest available energy is Phytoplankton, followed by Zooplankton, Small Fish (Tilapia), and finally the Fish Eagle.
Primary producers (phytoplankton) capture solar radiation directly to generate biomass, making them the largest energy reservoir in the food web. At each subsequent trophic transfer—from primary consumers (zooplankton) to secondary consumers (small fish) and tertiary consumers (fish eagle)—approximately 90% of the energy is lost to metabolic processes, respiration, and heat. Consequently, total energy availability decreases sequentially from the lowest trophic level to the highest.

Step-by-Step Solution

1
Determine the trophic level for each organism in the lake ecosystem.
Phytoplankton are primary producers (Trophic Level 1), zooplankton are primary consumers (Trophic Level 2), small fish are secondary consumers (Trophic Level 3), and fish eagles are tertiary consumers (Trophic Level 4).
Energy enters an ecosystem at the producer level and flows unidirectionally up consumer levels.
2
Apply the second law of thermodynamics / 10% energy transfer rule across trophic levels.
Only approximately 10% of stored chemical energy is transferred from one trophic level to the next, while about 90% is dissipated as metabolic heat and unconsumed waste.
Energy availability decreases progressively as energy is lost at each metabolic transfer step.
3
Order the organisms from maximum available energy to minimum available energy.
Phytoplankton → Zooplankton → Small Fish (Tilapia) → Fish Eagle.
Lower trophic levels always store significantly more energy than higher trophic levels.

Key Concept

Unidirectional energy flow and thermodynamic energy dissipation across trophic levels
Question 109Question

Match each fundamental ecological concept on the left with its precise structural or functional definition in ecosystem dynamics on the right.

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Items

Realized Niche
Ecotone
Standing Crop
Biome

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Answer

Realized Niche matches the restricted range of environmental conditions utilized under biological constraints; Ecotone matches the transitional boundary zone between distinct communities exhibiting edge effects; Standing Crop matches the total living biomass present at a specific point in time; Biome matches the major continental-scale ecological unit characterized by uniform climate and dominant vegetation.
Each ecological concept is matched to its precise definition: Realized Niche accounts for biotic limitations on resource use; Ecotone describes dynamic ecosystem transition boundaries; Standing Crop quantifies present living organic mass; Biome categorizes macro-regional climate-vegetation complexes.

Step-by-Step Solution

1
Analyze Realized Niche
Realized Niche describes the actual position and resource set utilized by a species when biotic factors (competition, predation) restrict its theoretical potential.
Differentiates fundamental niche (potential without competition) from realized niche (actual with competition).
2
Analyze Ecotone
Ecotone represents a transition zone between ecosystems (e.g., marsh between land and lake) showcasing high biodiversity due to edge effect.
Identifies boundary dynamics and ecological transition zones.
3
Analyze Standing Crop
Standing crop measures instantaneous biomass, unlike primary productivity which measures rate of organic matter synthesis over time.
Distinguishes static biomass measurement from dynamic rate of energy fixation.
4
Analyze Biome
Biome is the largest regional terrestrial unit defined by macroclimate and dominant climax growth form.
Maps spatial ecological hierarchy from local ecosystem to global biome.

Key Concept

Ecological Terminology and Ecosystem Structural Units
Question 110Question

During ecological succession, predictable structural and functional changes occur as an early pioneer stage progresses toward a mature climax ecosystem. Which of the following statements accurately characterizes the trends in community bioenergetics, biomass accumulation, and species interactions during this succession?

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Answer: Total ecosystem biomass accumulates while net community productivity approaches zero as gross primary productivity becomes balanced by community respiration.

Answer

Total ecosystem biomass accumulates while net community productivity approaches zero as gross primary productivity becomes balanced by community respiration.
As an ecosystem matures toward a climax community, species richness and total biomass increase. Energy expenditure for maintenance (community respiration) rises until total gross primary productivity equals total respiration. Consequently, net community productivity drops toward zero while biomass-to-energy-flow ratios reach maximum stability.

Step-by-Step Solution

1
Analyze energy ratio shifts across seral stages.
In early succession, gross primary productivity (PP) exceeds respiration (RR), so P/R>1P/R > 1 and net community production (PRP - R) is high.
Early pioneer communities invest energy primarily into rapid growth and biomass generation.
2
Evaluate ecosystem equilibrium at the climax community stage.
As community complexity increases, total respiration (RR) increases to maintain large standing biomass until P/R=1P/R = 1.
At steady-state climax, all gross primary production is consumed by maintenance metabolism, driving net community productivity down to near zero.

Key Concept

Bioenergetics and System Dynamics of Ecological Succession
Question 111Question

An ecologist studying abiotic factors in a lotic freshwater habitat estimated the surface water velocity by timing a float that travelled a distance of 60 m60\text{ m} downstream in 24 s24\text{ s}. To record a precise, depth-specific measurement of this ecological factor across different river strata, which calculated velocity and instrument choice are correct?

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Answer: 2.50 m s12.50\text{ m s}^{-1} measured using a water current meter

Answer

The stream velocity is 2.50 m s12.50\text{ m s}^{-1} and the appropriate instrument for depth-specific measurement is a water current meter.
Dividing the distance of 60 m60\text{ m} by the time of 24 s24\text{ s} yields a velocity of 2.50 m s12.50\text{ m s}^{-1}. A water current meter (flow meter) is the standard ecological instrument for measuring water velocity at different depths in lotic habitats.

Step-by-Step Solution

1
Calculate the water current velocity using the formula Velocity=DistanceTime\text{Velocity} = \frac{\text{Distance}}{\text{Time}}.
Velocity=60 m24 s=2.50 m s1\text{Velocity} = \frac{60\text{ m}}{24\text{ s}} = 2.50\text{ m s}^{-1}.
Velocity represents the rate of movement of water per unit time.
2
Identify the proper ecological instrument for measuring water current velocity at specific depths.
A water current meter (or flow meter) is designed to record current speed across various aquatic depths.
Surface floats only measure surface speed, whereas current meters submerged at defined depths give precise strata measurements.

Key Concept

Measurement of Aquatic Ecological Factors
Estimated Time:2m 0s
Question 112Question

An ecologist conducted a survey in an abandoned oil palm plantation in Edo State to determine the density of Siam weed (*Chromolaena odorata*). Using a 1 m×1 m1\text{ m} \times 1\text{ m} quadrat frame thrown randomly 20 times across the field, a total of 160 Siam weed plants were counted. What is the estimated population density of Siam weed in this plantation?

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Answer: 8 plants/m28\text{ plants/m}^2

Answer

The estimated population density of Siam weed is 8 plants/m28\text{ plants/m}^2.
Population density is defined as the number of individuals of a species per unit area. To calculate this accurately using quadrats, the total number of organisms counted (160 plants) must be divided by the total area sampled. Since 20 quadrats of 1 m21\text{ m}^2 each were sampled, the total sampled area is 20 m220\text{ m}^2. Thus, 16020=8 plants/m2\frac{160}{20} = 8\text{ plants/m}^2.

Step-by-Step Solution

1
Calculate the area of a single quadrat frame
Area of 1 quadrat=1 m×1 m=1 m2\text{Area of 1 quadrat} = 1\text{ m} \times 1\text{ m} = 1\text{ m}^2
Determines the sampling area covered by one throw of the frame.
2
Calculate the total area sampled across all quadat throws
Total sampled area=20×1 m2=20 m2\text{Total sampled area} = 20 \times 1\text{ m}^2 = 20\text{ m}^2
Finds the combined area evaluated in the 20 random quadrat throws.
3
Calculate the population density per square metre
Population Density=Total number of individualsTotal sampled area=160 plants20 m2=8 plants/m2\text{Population Density} = \frac{\text{Total number of individuals}}{\text{Total sampled area}} = \frac{160\text{ plants}}{20\text{ m}^2} = 8\text{ plants/m}^2
Applies the standard ecological formula for population density using quadrat data.

Key Concept

Population Density Calculation using Quadrats
Estimated Time:1m 0s
Question 113Question

Match each ecological succession process or stage in List I with its corresponding characteristic bioenergetic, structural, or environmental mechanism in List II.

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Items

Hydrosere reed-swamp stage
Autogenic facilitation mechanism
Allogenic successional driving force
Mature climax ecosystem energetics

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Answer

Hydrosere reed-swamp stage matches organic mud accumulation shallowing water for emergent vegetation; Autogenic facilitation matches resident organisms modifying microclimate/soil to favor successor species; Allogenic successional force matches external abiotic forces like volcanic ash deposition driving community change; Mature climax ecosystem energetics matches P/RP/R ratio equal to 1.0 with maximum community respiration balancing gross photosynthesis.
Each ecological succession stage and mechanism is paired with its exact physiological or environmental signature: the hydrosere reed-swamp stage builds up organic sediment to shallow water bodies; autogenic facilitation describes biotic modification of the microhabitat that favors succeeding species; allogenic forces refer to non-biological physical perturbations driving community shifts; and climax communities reach metabolic steady-state where total gross photosynthesis equals total community respiration (P/R=1.0P/R = 1.0).

Step-by-Step Solution

1
Identify the defining structural progression of a hydrosere.
The reed-swamp stage represents the transition where submerged organic sediment builds up, reducing water depth so amphibious species can take root.
Hydrosere progression depends on sediment trapping by pioneer and submerged plant roots before terrestrial species can colonize.
2
Differentiate autogenic from allogenic drivers of ecological succession.
Autogenic changes originate from biogenic habitat modification (facilitation), whereas allogenic changes stem from external physical disturbances.
Living organisms themselves drive autogenic succession, while external geological or climatic events drive allogenic succession.
3
Analyze bioenergetic trends associated with community maturation.
Early pioneer stages have P/R>1P/R > 1, but mature climax communities reach steady-state equilibrium where gross photosynthesis equals total respiration (P/R=1P/R = 1).
Energy maintenance costs (respiration) rise with increased biomass complexity until Net Community Production approaches zero.

Key Concept

Mechanisms and Energetics of Ecological Succession
Question 114Question

Match each ecological organization level on the left with its correct biological description on the right.

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Items

Population
Community
Ecosystem
Biosphere

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Answer

Population pairs with a group of individuals of the same species; Community pairs with all populations of different species interacting in a habitat; Ecosystem pairs with a biological community interacting with its abiotic environment; Biosphere pairs with the global sum of all ecosystems on Earth.
Each ecological organization term matches its precise hierarchical definition: population is restricted to a single species, community includes multiple interacting species, ecosystem adds abiotic environmental interactions, and biosphere represents global life zones.

Step-by-Step Solution

1
Identify the smallest single-species group level.
Population corresponds to a single species in a specific area.
Populations consist strictly of organisms of the same species.
2
Identify the multi-species biotic assemblage level.
Community corresponds to interacting populations of different species.
A community encompasses all biotic components in a habitat.
3
Identify the level integrating living and non-living components.
Ecosystem corresponds to the community interacting with abiotic factors.
An ecosystem requires both biotic organisms and physical abiotic environments.
4
Identify the planet-wide ecological level.
Biosphere corresponds to the global sum of all ecosystems.
The biosphere covers all parts of Earth where life exists.

Key Concept

Levels of Ecological Organization
Question 115Question

Match each nitrogen cycle microorganism on the left with its correct biological role on the right.

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Items

Azotobacter
Nitrosomonas
Nitrobacter
Pseudomonas

Matches

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Answer

Azotobacter matches Free-living nitrogen fixation in soil; Nitrosomonas matches Oxidation of ammonia into nitrite; Nitrobacter matches Oxidation of nitrite into nitrate; Pseudomonas matches Conversion of nitrate into atmospheric nitrogen.
Each microorganism has a distinct biochemical role in maintaining the balance of nitrogen compounds within ecosystems: Azotobacter fixes free atmospheric nitrogen into soil, Nitrosomonas oxidizes ammonia into nitrite, Nitrobacter oxidizes nitrite into nitrate, and Pseudomonas reduces nitrates back to nitrogen gas.

Step-by-Step Solution

1
Identify the metabolic role of Azotobacter
Free-living nitrogen fixation in soil
Azotobacter fixes nitrogen independently without forming symbiotic nodules on plant roots.
2
Identify the metabolic role of Nitrosomonas
Oxidation of ammonia into nitrite
Nitrosomonas converts ammonia compounds into nitrite as the first stage of nitrification.
3
Identify the metabolic role of Nitrobacter
Oxidation of nitrite into nitrate
Nitrobacter oxidizes the toxic intermediate nitrite into bioavailable nitrate.
4
Identify the metabolic role of Pseudomonas
Conversion of nitrate into atmospheric nitrogen
Pseudomonas participates in denitrification, returning nitrogen gas back to the atmosphere.

Key Concept

Microbial roles in the nitrogen cycle
Question 116Question

In a humid tropical forest ecosystem, the producers capture solar energy resulting in a Gross Primary Productivity (GPP) of 40000 kJ/m2/yr40{}000\text{ kJ/m}^2/\text{yr}. Autotrophic respiration accounts for 55%55\% of this captured energy. Primary consumers assimilate 10%10\% of the Net Primary Productivity (NPP) available to them, while spending 60%60\% of their assimilated energy on cellular respiration. What is the total energy available for secondary consumers at the third trophic level?

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Answer: 720 kJ/m2/yr720\text{ kJ/m}^2/\text{yr}

Answer

The total energy available for secondary consumers is 720 kJ/m2/yr720\text{ kJ/m}^2/\text{yr}.
The correct calculation yields 720 kJ/m2/yr720\text{ kJ/m}^2/\text{yr} by systematically subtracting autotrophic metabolic costs (55%55\% of GPP), taking the 10%10\% ecological assimilation rate into primary consumers, and subtracting herbivore metabolic maintenance (60%60\% of assimilated energy).

Step-by-Step Solution

1
Calculate Net Primary Productivity (NPP) of the producers.
NPP=GPPRproducers=40000(0.55×40000)=18000 kJ/m2/yr\text{NPP} = \text{GPP} - R_{\text{producers}} = 40{}000 - (0.55 \times 40{}000) = 18{}000\text{ kJ/m}^2/\text{yr}.
Plant respiration consumes 55%55\% of GPP, leaving 45%45\% as biomass available to herbivores.
2
Determine energy assimilated by primary consumers.
Assimilated Energy=0.10×18000=1800 kJ/m2/yr\text{Assimilated Energy} = 0.10 \times 18{}000 = 1{}800\text{ kJ/m}^2/\text{yr}.
Primary consumers transfer 10%10\% of the available plant biomass (NPP) into their tissue assimilation pathway.
3
Deduct respiratory losses of primary consumers to find net secondary productivity available for the third trophic level.
Available Energy=1800×(10.60)=720 kJ/m2/yr\text{Available Energy} = 1{}800 \times (1 - 0.60) = 720\text{ kJ/m}^2/\text{yr}.
Herbivores expend 60%60\% of their assimilated energy on metabolic processes, leaving 40%40\% incorporated into new biomass accessible to secondary consumers.

Key Concept

Energy Transfer Efficiency and Productivity Calculations Across Trophic Levels
Question 117Question

In ecological systems, energy transformations and trophic interactions dictate the structure and dynamics of food webs. Match each ecological energy concept on the left with its corresponding defining feature or ecosystem attribute on the right.

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Items

Net Primary Productivity (NPP)
Inverted Pyramid of Biomass
Pyramid of Energy
Secondary Consumers

Matches

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Answer

Net Primary Productivity pairs with energy stored after respiratory loss; Inverted Pyramid of Biomass pairs with open-ocean aquatic ecosystems with rapid turnover; Pyramid of Energy pairs with the non-invertible energy flow representation; and Secondary Consumers pair with organisms at the third trophic level feeding on herbivores.
Each ecological concept correctly matches its fundamental structural or physiological property: NPP accounts for respiratory deductions from gross energy fixed, inverted biomass pyramids occur in pelagic aquatic systems with high producer turnover, energy pyramids strictly follow unidirectional thermodynamic decay and remain upright, and secondary consumers occupy the third trophic level by feeding on herbivores.

Step-by-Step Solution

1
Define Net Primary Productivity
NPP equals Gross Primary Productivity (GPP) minus respiration (RR). This matches the organic energy available to herbivores after autotroph metabolic consumption.
Understanding energy budget components of primary producers.
2
Analyze ecosystem conditions for biomass pyramid shapes
Terrestrial ecosystems typically have upright biomass pyramids, whereas open-ocean ecosystems display inverted biomass pyramids due to fast turnover rates of phytoplankton.
Distinguishing standing crop biomass from energy production rates.
3
Evaluate thermodynamic constraints on energy pyramids
Energy pyramids quantify energy throughput per unit time and must always be upright because energy is lost as metabolic heat during transfer across trophic levels.
Applying the second law of thermodynamics to ecological energy flow.
4
Identify trophic level positions
Primary producers form level 1, primary consumers (herbivores) form level 2, and secondary consumers (carnivores feeding on herbivores) form level 3.
Categorizing organisms based on energy acquisition strategies.

Key Concept

Trophic level dynamics and ecological energy transfer constraints
Question 118Question

Arrange the following organisms in a coastal estuarine food chain in sequence of DECREASING available energy per unit area per year (from the trophic level with the highest available energy to the trophic level with the lowest available energy).

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Answer

Microscopic estuarine phytoplankton → Filter-feeding bivalves (mussels and oysters) → Predatory demersal fish (snappers) → Piscivorous marine mammals (dolphins)
Energy flow through an ecosystem is unidirectional and governed by the laws of thermodynamics. Primary producers (phytoplankton) convert radiant solar energy into chemical energy, possessing the highest net available energy. Primary consumers (bivalves) feed on producers and assimilate only ~10% of that energy, with the remainder lost through cellular respiration and metabolic heat. Secondary consumers (predatory fish) and tertiary consumers (marine mammals) experience further successive ~90% energy losses at each transfer step. Consequently, available energy is highest at the base (producers) and lowest at the apex (tertiary consumers).

Step-by-Step Solution

1
Identify the trophic position of each organism in the estuarine food chain
Phytoplankton = Primary Producer (Trophic Level 1); Bivalves = Primary Consumer (Trophic Level 2); Demersal fish = Secondary Consumer (Trophic Level 3); Marine mammals = Tertiary Consumer (Trophic Level 4).
Energy availability depends strictly on the trophic position within an ecological energy pyramid.
2
Apply the thermodynamic principle of energy flow (10% law of energy transfer)
Energy decreases unidirectional by approximately 80-90% at each successive step from lower to higher trophic levels due to metabolic respiration, heat dissipation, and unassimilated waste.
Pyramids of energy are strictly upright and cannot be inverted.
3
Sequence the organisms from highest available energy to lowest available energy
Order: Microscopic estuarine phytoplankton > Filter-feeding bivalves > Predatory demersal fish > Piscivorous marine mammals.
Producers hold the maximum energy, while top predators at the highest trophic level receive the minimum available energy.

Key Concept

Thermodynamic energy attenuation and Lindeman's 10% law across ecological trophic levels
Estimated Time:1m 30s
Question 119Question

Match each nitrogen cycle process listed on the left with its correct biological transformation on the right.

Click a left item, then click its matching right item

Items

Nitrification
Denitrification
Ammonification
Nitrogen fixation

Matches

Show answer & explanation

Answer

Nitrification corresponds to the oxidation of ammonium ions to nitrites and nitrates; Denitrification corresponds to the reduction of soil nitrates to gaseous dinitrogen; Ammonification corresponds to the breakdown of organic nitrogenous waste into ammonia; Nitrogen fixation corresponds to the conversion of atmospheric dinitrogen into ammonia or ammonium ions.
Each process in the nitrogen cycle represents a distinct chemical transformation: Nitrification oxidizes ammonium to nitrite and nitrate; Denitrification reduces soil nitrate to nitrogen gas; Ammonification releases ammonia from decomposing organic nitrogen; Nitrogen fixation reduces atmospheric dinitrogen into ammonia.

Step-by-Step Solution

1
Determine the transformation involved in Nitrification.
Nitrification converts ammonium ions (NH4+NH_4^+) into nitrites (NO2NO_2^-) and then nitrates (NO3NO_3^-).
Nitrifying microorganisms derive energy by oxidizing nitrogen in aerobic soil environments.
2
Determine the transformation involved in Denitrification.
Denitrification reduces soil nitrates (NO3NO_3^-) back into nitrogen gas (N2N_2).
Denitrifying microbes use nitrate as an electron acceptor under anaerobic conditions, replenishing atmospheric nitrogen.
3
Determine the transformation involved in Ammonification.
Ammonification breaks down nitrogenous organic wastes into ammonia (NH3NH_3).
Decomposers hydrolyze organic polymers, releasing inorganic ammonia into the soil.
4
Determine the transformation involved in Nitrogen fixation.
Nitrogen fixation converts gaseous dinitrogen (N2N_2) into usable ammonia (NH3NH_3) or ammonium (NH4+NH_4^+).
Nitrogen-fixing bacteria possess the nitrogenase enzyme complex required to break the triple bond of N2N_2.

Key Concept

Nitrogen Cycle Transformations and Microbial Mechanisms
Question 120Question

In an experiment to investigate the water-retaining capacity of three different soil types, equal masses (100 g100\text{ g}) of dried soil samples PP, QQ, and RR were placed into separate filter-lined funnels. A volume of 100 cm3100\text{ cm}^3 of water was poured over each sample, and the volume of filtrate collected in the measuring cylinders beneath after 15 minutes15\text{ minutes} was recorded as follows:

- Sample P: 25 cm325\text{ cm}^3 of filtrate collected
- Sample Q: 55 cm355\text{ cm}^3 of filtrate collected
- Sample R: 85 cm385\text{ cm}^3 of filtrate collected

Which of the following correctly identifies Sample R and the primary edaphic factor responsible for its observed drainage rate?

Show answer & explanation

Answer: Sandy soil, due to large coarse particles and large pore spaces that promote rapid water percolation.

Answer

Sample R is sandy soil, because its large particle size and large pore spaces allow water to drain rapidly, resulting in the highest filtrate volume collected.
The sample that produces the highest volume of filtrate (85 cm385\text{ cm}^3) retains the smallest amount of water (15 cm315\text{ cm}^3). Sandy soil has large mineral particles and relatively large spaces between particles, which allows water to drain freely and rapidly under gravity.

Step-by-Step Solution

1
Calculate the volume of water retained by each soil sample.
Water retained = Initial water added (100 cm3100\text{ cm}^3) minus filtrate collected. Sample P retained 75 cm375\text{ cm}^3, Sample Q retained 45 cm345\text{ cm}^3, and Sample R retained 15 cm315\text{ cm}^3.
Determining the retained volume allows ranking the soils from highest to lowest water-holding capacity.
2
Analyze the physical properties of soil types relative to drainage.
Sample R retained the least water (15 cm315\text{ cm}^3) and drained the most (85 cm385\text{ cm}^3).
Sandy soils consist of large, coarse sand particles with large macropores between them, leading to poor water retention and high percolation rates.

Key Concept

Water-retaining capacity and percolation rates of edaphic soil types (sand, loam, clay)
Estimated Time:1m 30s
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