Physical Geography Practice Questions — JAMB UTME — Page 7

Question 121Question →

An ocean liner positioned at longitude $15^\circ\text{W}$ records its local solar time as 1:00 p.m. At the exact same moment, a cargo ship located at a different meridian records its local solar time as 5:00 p.m. What is the longitudinal position of the cargo ship?

45^\circ\text{E}

75^\circ\text{W}

60^\circ\text{E}

45^\circ\text{W}

Show answer & explanation

Answer: $45^\circ\text{E}$

Answer

The longitude of the cargo ship is

45^\circ\text{E}

.

Because the cargo ship's local time is 4 hours ahead of the ocean liner's time (5:00 p.m. vs 1:00 p.m.), it must be located east of the liner. Since Earth rotates

15^\circ

per hour, a 4-hour difference corresponds to an angular distance of

60^\circ

. Measuring

60^\circ

east from

15^\circ\text{W}

involves traveling

15^\circ

east to the Prime Meridian (

0^\circ

) and then another

45^\circ

east into the Eastern Hemisphere, placing the cargo ship at

45^\circ\text{E}

.

Step-by-Step Solution

1

Calculate the time difference between the two vessels.

Time difference =

\text{5:00 p.m.} - \text{1:00 p.m.} = 4\text{ hours}

.

Determining the time interval is necessary to find the total angular distance.

2

Convert the time difference into degrees of longitude.

Angular distance =

4\text{ hours} \times 15^\circ/\text{hour} = 60^\circ

.

Earth rotates

360^\circ

in 24 hours, which equals

15^\circ

per hour.

3

Determine the direction of movement and calculate the target longitude.

Since 5:00 p.m. is later than 1:00 p.m., the cargo ship is to the East. Starting at

15^\circ\text{W}

, moving

15^\circ

East reaches

0^\circ

(Greenwich Meridian), and moving the remaining

45^\circ

(

60^\circ - 15^\circ

) East reaches

45^\circ\text{E}

.

Locations with later local times are located further East.

Key Concept

Longitude and Local Time Calculations across Meridians

Estimated Time:1m 30s

Question 122Question →

A weather monitoring station located at longitude $35^\circ\text{E}$ records local solar noon ( $12:00\text{ p.m.}$ ) at the exact instant a UTC master clock displays $09:40\text{ a.m.}$ at the Greenwich Meridian ( $0^\circ$ ). At that identical moment, a remote research station records its local solar time as $06:20\text{ a.m.}$ on the same day. What is the longitudinal position of the remote research station?

50^\circ\text{W}

50^\circ\text{E}

85^\circ\text{W}

15^\circ\text{E}

Show answer & explanation

Answer: $50^\circ\text{W}$

Answer

50^\circ\text{W}

The remote research station's local solar time (

06:20\text{ a.m.}

) is 3 hours and 20 minutes (

200\text{ minutes}

) behind Greenwich Mean Time (

09:40\text{ a.m.}

). Since

1^\circ

of longitude equals 4 minutes of time, dividing 200 by 4 yields an angular difference of

50^\circ

. Because local time is behind Greenwich time, the station lies in the Western Hemisphere at

50^\circ\text{W}

.

Step-by-Step Solution

1

Determine the time difference between Greenwich (

0^\circ

) and the remote research station.

Greenwich Time =

09:40\text{ a.m.}

, Remote Station Time =

06:20\text{ a.m.}

. Time difference =

09:40 - 06:20 = 3\text{ hours } 20\text{ minutes} = 200\text{ minutes}

.

Longitude calculations must be referenced against Greenwich Mean Time (

0^\circ

Meridian) to determine absolute longitudinal position.

2

Convert the time difference into longitudinal degrees using the Earth's rate of rotation (

1^\circ = 4\text{ minutes}

).

\frac{200\text{ minutes}}{4\text{ minutes per degree}} = 50^\circ

.

The Earth rotates

360^\circ

in 24 hours, which corresponds to

15^\circ

per hour or

1^\circ

every 4 minutes.

3

Determine the longitudinal hemisphere (East or West).

Since

06:20\text{ a.m.}

is behind

09:40\text{ a.m.}

, the remote station is West of Greenwich. Therefore, the position is

50^\circ\text{W}

.

Places to the west of a given meridian experience local time earlier in the clock cycle (behind GMT), following the principle 'East gain, West lose'.

Key Concept

Longitude and Local Time Calculation across Meridians

Estimated Time:2m 0s

Question 123Question →

A cargo vessel positioned at longitude $45^\circ\text{W}$ reports a local solar time of $10:30\text{ AM}$ . At that precise moment, a coastal harbor records a local solar time of $03:30\text{ PM}$ . What is the longitude of the coastal harbor in degrees East ( $^\circ\text{E}$ )?

Show answer & explanation

Answer: 30

Answer

The longitude of the coastal harbor is 30 degrees East (30°E).

Because the harbor is experiencing a later local solar time (03:30 PM) than the vessel (10:30 AM), it must lie to the East of the vessel. The 5-hour time difference equates to an angular distance of 75°. Crossing from 45°W past the Greenwich Meridian (0°) leaves 30° in the Eastern Hemisphere, placing the harbor at 30°E.

Step-by-Step Solution

1

Calculate time difference

5 hours

The difference between 10:30 AM and 03:30 PM (15:30) is 5 hours.

2

Convert time difference to longitudinal angular distance

75 degrees

Earth rotates 15 degrees per hour, so 5 hours corresponds to 5 × 15° = 75°.

3

Calculate position relative to Prime Meridian

30 degrees East

Moving East from 45°W by 75° requires traversing 45° to reach 0° (Greenwich Meridian), and the remaining 30° extends into the Eastern Hemisphere.

Key Concept

Longitude and Time Calculations across Hemispheres

Question 124Question →

Geophysical investigations reveal distinct internal structural layers and seismic boundary zones within the Earth. What is the correct sequence of these internal layers and discontinuities when arranged in order of increasing depth from the Earth's surface to its center?

Drag items to arrange them in the correct order

Show answer & explanation

Answer

The correct order from Earth's surface to the center is: Conrad Discontinuity, Mohorovičić Discontinuity, Asthenosphere, Gutenberg Discontinuity, and Lehmann Discontinuity.

Arranged from the surface downward, the Earth's structural boundaries and zones progress from the Conrad Discontinuity (~10–20 km within continental crust), to the Mohorovičić Discontinuity (~35 km at the crust-mantle interface), followed by the Asthenosphere (~100–250 km in the upper mantle), the Gutenberg Discontinuity (~2,900 km at the mantle-core boundary), and finally the Lehmann Discontinuity (~5,150 km at the outer core-inner core boundary).

Step-by-Step Solution

1

Identify the shallowest seismic boundary within the continental crust.

The Conrad Discontinuity lies within the upper crust at ~10–20 km depth, separating sial from sima.

It is the shallowest boundary listed.

2

Locate the boundary separating the crust from the underlying mantle.

The Mohorovičić (Moho) Discontinuity lies at the base of the crust at ~35 km average depth.

It marks the structural boundary between the crustal rocks and the denser mantle rocks.

3

Identify the ductile layer in the upper mantle.

The Asthenosphere lies beneath the lithosphere in the upper mantle (~100–250 km depth).

It is a semi-fluid zone of partial melting beneath the solid crust-upper mantle lithospheric cap.

4

Locate the deep mantle-core boundary.

The Gutenberg Discontinuity is situated at ~2,900 km depth.

It separates the silicate mantle from the metallic outer core.

5

Identify the boundary separating the outer and inner core zones.

The Lehmann Discontinuity is located at ~5,150 km depth near the Earth's center.

It defines the seismic transition between the liquid metallic outer core and the solid inner core.

Key Concept

Internal Structure of the Earth and Seismic Discontinuities

Question 125Question →

Which of the following geographical processes is an example of mass wasting rather than in-situ weathering?

The downslope movement of soil creep under the influence of gravity

The chemical breakdown of granite through hydrolysis

The physical peeling of rock layers due to exfoliation

The dissolution of limestone by carbonic acid

Show answer & explanation

Answer: The downslope movement of soil creep under the influence of gravity

Answer

The downslope movement of soil creep under the influence of gravity is a mass wasting process.

Soil creep involves the slow, downhill movement of soil and rock debris purely under the force of gravity, satisfying the fundamental definition of mass wasting. In contrast, weathering processes break down rock material in-situ without transporting it.

Step-by-Step Solution

1

Identify the core mechanism of weathering versus mass wasting

Weathering involves the static, in-situ disintegration or decomposition of rocks, whereas mass wasting involves the movement of weathered materials down a slope under gravity.

Mass wasting requires downhill transport driven primarily by gravity.

2

Evaluate the given options against this distinction

Hydrolysis, exfoliation, and carbonation break down rock in place (weathering). Soil creep involves downslope movement (mass wasting).

Soil creep is the only process described that involves downslope displacement.

Key Concept

Distinction between in-situ weathering and gravity-driven mass wasting

Estimated Time:45s

Question 126Question →

Geological analyses of the Earth's crust and outer physical spheres demonstrate distinct compositional differences between continental and oceanic crustal layers, as well as specific exogenic mechanisms operating on surface rocks. Which of the following statements accurately differentiates between the sial and sima layers of the lithosphere while correctly identifying the exogenic process responsible for the in-situ physical breakdown of exposed sialic bedrock?

Sial is predominantly granitic, less dense, and composed of silica and alumina forming continental crust, whereas sima is basaltic, denser, and composed of silica and magnesium forming oceanic crust; exposed sialic bedrock disintegrates in situ through weathering.

Sial is predominantly granitic, less dense, and composed of silica and alumina forming continental crust, whereas sima is basaltic, denser, and composed of silica and magnesium forming oceanic crust; exposed sialic bedrock disintegrates in situ through mass wasting.

Sial is a denser layer of sedimentary marine deposits underlying oceanic basins, whereas sima is a lighter granitic layer formed through regional metamorphism; exposed sialic bedrock disintegrates in situ through weathering.

Sial is denser than sima and forms the lower basaltic layer of the lithosphere, whereas sima forms the lighter continental crust; exposed sialic bedrock disintegrates downslope through mass wasting.

Show answer & explanation

Answer: Sial is predominantly granitic, less dense, and composed of silica and alumina forming continental crust, whereas sima is basaltic, denser, and composed of silica and magnesium forming oceanic crust; exposed sialic bedrock disintegrates in situ through weathering.

Answer

Sial is predominantly granitic, less dense, and composed of silica and alumina forming continental crust, whereas sima is basaltic, denser, and composed of silica and magnesium forming oceanic crust; exposed sialic bedrock disintegrates in situ through weathering.

The correct statement accurately defines sial as the lighter, silica- and alumina-rich granitic layer forming continental landmasses and sima as the denser, silica- and magnesium-rich basaltic layer forming ocean floors. Furthermore, it correctly identifies weathering as the process responsible for breaking down rock in situ at the surface.

Step-by-Step Solution

1

Analyze the internal composition and density of sial and sima.

Sial (Silica + Alumina) forms continental crust with lower density (

\approx 2.7\text{ g/cm}^3

). Sima (Silica + Magnesia) forms oceanic crust and underlying layer with higher density (

\approx 3.0\text{ g/cm}^3

).

Internal structural layers of the Earth's crust are differentiated by chemical composition and specific gravity.

2

Differentiate exogenic processes acting on exposed rock at the Earth's surface.

In-situ breakdown of rock without transportation is defined as weathering. Downslope movement under gravity is mass wasting.

External surface dynamics require distinguishing between in-situ disintegration (weathering) and gravity-driven transport (mass wasting).

3

Synthesize structural layer properties with the correct exogenic process.

The correct option must state that sial is granitic/lighter, sima is basaltic/denser, and in-situ disintegration occurs via weathering.

Combines internal crustal differentiation with external physical breakdown.

Key Concept

Crustal differentiation (Sial vs Sima) and surface weathering mechanisms

Estimated Time:2m 0s

Question 127Question →

Match each rock type listed in Group I with its corresponding parent rock and specific formation process in Group II.

Click a left item, then click its matching right item

Show answer & explanation

Answer

Quartzite matches with thermal or regional metamorphism of sandstone causing quartz grains to recrystallize; Marble matches with metamorphism of calcareous sedimentary rock such as limestone; Schist matches with medium-to-high grade regional metamorphism of argillaceous shale; Anthracite matches with high-grade thermal and compressive alteration of sedimentary bituminous coal.

Each metamorphic rock is correctly aligned with its original parent rock (protolith) and corresponding thermodynamic transformation process: Quartzite stems from sandstone recrystallization, Marble from limestone recrystallization, Schist from shale foliation, and Anthracite from metamorphic distillation of bituminous coal.

Step-by-Step Solution

1

Analyze the mineral composition and origin of Quartzite.

Quartzite consists predominantly of recrystallized quartz grains originating from siliceous sandstone.

Under elevated heat and pressure, original quartz sand grains in sandstone recrystallize into a dense interlocking matrix.

2

Identify the parent rock (protolith) of Marble.

Marble forms through the metamorphism of calcareous rocks like limestone or dolomite.

Thermal contact or regional metamorphism drives the recrystallization of calcite micro-crystals into larger interlocking calcite grains.

3

Determine the metamorphic grade and protolith of Schist.

Schist develops from fine-grained argillaceous rocks (shale) undergoing moderate-to-high grade regional metamorphism.

Directed compressive stress aligns platy mica and chlorite minerals into distinct foliated bands visible to the naked eye.

4

Evaluate the formation mechanism of Anthracite.

Anthracite is produced by metamorphic alteration of organic sedimentary bituminous coal.

Extreme tectonic pressure and geothermal heat drive off volatile gases, yielding ultra-high carbon concentration.

Key Concept

Metamorphic Protoliths and Transformation Mechanisms

Question 128Question →

Match each geological material in Group I with its precise genesis and primary industrial application in Group II.

Click a left item, then click its matching right item

Show answer & explanation

Answer

Pumice pairs with extrusive vesicular pyroclastic rock used as a lightweight aggregate; Diatomite pairs with siliceous organically-formed sedimentary rock used as a filtration medium; Graphite pairs with carbonaceous metamorphic product used as a solid lubricant; Gypsum pairs with chemical evaporite sedimentary rock used as a cement setting retarder.

Each item is matched according to its fundamental rock classification group (Igneous pyroclastic, Organo-sedimentary, Metamorphic mineral, and Chemical evaporite) alongside its documented commercial utility in industrial geography.

Step-by-Step Solution

1

Analyze the formation process and economic role of Pumice

Pumice is an extrusive igneous rock with a vesicular texture formed by trapped volcanic gases, making it light enough to float and useful as an abrasive or lightweight concrete component.

Understanding volcanic texture differentiates extrusive pyroclastics from crystalline intrusive bodies.

2

Analyze the formation process and economic role of Diatomite

Diatomite is an organically derived sedimentary rock made of silica-based skeletal remains of diatoms, used extensively for industrial fluid filtration.

Siliceous organic sediment contrasts with calcareous organic sediment such as chalk or limestone.

3

Analyze the formation process and economic role of Graphite

Graphite forms under high-temperature/pressure metamorphic transformation of carbonaceous matter in sediments, yielding a soft, heat-resistant conductor and solid lubricant.

Metamorphic recrystallization alters organic carbon into pure crystalline carbon lattices.

4

Analyze the formation process and economic role of Gypsum

Gypsum forms via chemical precipitation in arid evaporite environments and serves as a crucial setting-time regulator in cement manufacture.

Evaporite minerals precipitate directly from concentrated hypersaline water.

Key Concept

Genesis, micro-structural characteristics, and industrial applications of igneous, sedimentary, and metamorphic rock types.

Question 129Question →

Match each physical geography process in Column A with its correct defining characteristic or mechanism in Column B.

Click a left item, then click its matching right item

Show answer & explanation

Answer

Carbonation matches chemical dissolution of limestone by carbonic acid; Exfoliation matches physical peeling of outer rock layers; Soil Creep matches extremely slow downslope soil movement under gravity; Rockfall matches rapid free-fall of detached rock fragments.

Carbonation is matched with chemical dissolution because carbonic acid reacts with limestone. Exfoliation matches the peeling of rock sheets caused by differential expansion and pressure release. Soil Creep matches slow, continuous soil movement downslope. Rockfall matches fast, gravity-driven free-falling of rock debris down steep slopes.

Step-by-Step Solution

1

Distinguish between weathering processes (in-situ rock breakdown) and mass wasting processes (downslope displacement under gravity).

Carbonation and Exfoliation are weathering processes, whereas Soil Creep and Rockfall are mass wasting processes.

Categorizing by fundamental mechanism simplifies pairing.

2

Identify the chemical versus physical nature of the weathering processes.

Carbonation involves chemical dissolution of limestone, while Exfoliation is physical onion-skin peeling of rock layers.

Chemical weathering alters mineral composition, while physical weathering breaks rocks mechanically.

3

Differentiate the mass wasting processes by rate of movement.

Soil Creep represents the slowest movement of surface soil, whereas Rockfall represents a rapid, direct vertical fall of rocks.

Mass wasting phenomena are categorized primarily by movement speed and material state.

Key Concept

Classification and mechanisms of weathering and mass wasting processes.

Question 130Question →

Match each rock listed in Column I with its correct classification, characteristic texture, or primary economic application in Column II.

Click a left item, then click its matching right item

Show answer & explanation

Answer

Obsidian matches with the extrusive igneous rock with a glassy texture; Gypsum matches with the chemical sedimentary rock formed by evaporation used for plaster of Paris; Anthracite matches with the high-rank organic metamorphic rock used as fuel; Quartzite matches with the hard, non-foliated metamorphic rock derived from quartz sandstone.

Each rock is paired accurately according to its genetic rock family and physical/economic properties: Obsidian is a glassy extrusive igneous rock, Gypsum is an evaporite chemical sedimentary rock used in construction, Anthracite is an organic metamorphic coal with high heat value, and Quartzite is a durable metamorphic rock derived from sandstone.

Step-by-Step Solution

1

Identify the origin and texture of Obsidian.

Obsidian is volcanic glass formed by rapid cooling of lava without crystallization.

Rapid surface cooling prevents mineral crystals from forming.

2

Identify the formation process and economic use of Gypsum.

Gypsum is a chemical evaporite used in building materials like plaster of Paris.

Evaporation leaves behind calcium sulfate deposits.

3

Identify the classification and composition of Anthracite.

Anthracite is metamorphosed organic material rich in carbon.

Heat and pressure transform peat/lignite into hard metamorphic coal.

4

Identify the parent rock and resistance of Quartzite.

Quartzite is formed from quartz sandstone via recrystallization.

Metamorphism locks quartz mineral grains into a dense interlocking matrix.

Key Concept

Rock Types, Formation, and Economic Importance

Question 131Question →

Match each Earth structural layer or atmospheric zone listed in Column I with its correct physical or compositional characteristic in Column II.

Click a left item, then click its matching right item

Show answer & explanation

Answer

Asthenosphere matches with the semi-fluid upper mantle layer; Barysphere matches with the dense iron-nickel central core; Atmospheric Mesosphere matches with the atmospheric layer above the stratosphere where temperature decreases with altitude; Sialic Crust matches with the upper continental granitic layer rich in silica and aluminium.

The matching pairs reflect true geological and atmospheric definitions: the Asthenosphere is the ductile upper mantle region driving plate dynamics, the Barysphere is the central dense core, the Atmospheric Mesosphere is the thermal region above the stratosphere where temperature decreases with height, and the Sialic Crust is the granitic continental layer.

Step-by-Step Solution

1

Analyze the physical properties of the internal structural layers of the Earth.

The asthenosphere is a ductile zone within the upper mantle, the barysphere is the dense inner metallic core, and the sialic crust forms the upper continental layer rich in silica and aluminium.

Different internal Earth zones are differentiated by density, mineral composition, and rheology.

2

Analyze the physical characteristics of the external sphere (atmospheric mesosphere).

The atmospheric mesosphere is situated above the stratosphere and experiences a steady temperature decline with increasing altitude.

External atmospheric layers are categorized by thermal structure and environmental properties.

3

Match each structural item in Column I to its accurate defining characteristic in Column II.

Each layer is accurately paired to its specific chemical composition or mechanical behavior.

Verification confirms no overlap or misattribution among structural boundaries.

Key Concept

Internal and External Structure of the Earth

Question 132Question →

Town X is located at longitude $15^\circ\text{W}$ where the local solar time is recorded as $08:20\text{ AM}$ . At the exact same instant, a solar observatory at Town Y records a local solar time of $05:00\text{ PM}$ . What is the longitude of Town Y?

115^\circ\text{E}

115^\circ\text{W}

145^\circ\text{E}

145^\circ\text{W}

Show answer & explanation

Answer: $115^\circ\text{E}$

Answer

The longitude of Town Y is

115^\circ\text{E}

.

Because Town Y has a local solar time of

05:00\text{ PM}

compared to

08:20\text{ AM}

at Town X, Town Y is

8\text{ hours } 40\text{ minutes}

ahead. Converting this time difference to angular distance (

520\text{ minutes} \div 4 = 130^\circ

) shows Town Y is

130^\circ

east of

15^\circ\text{W}

. Traveling

15^\circ

east reaches the Greenwich Meridian (

0^\circ

), and the remaining

115^\circ

east places Town Y at

115^\circ\text{E}

.

Step-by-Step Solution

1

Calculate the time difference between Town X and Town Y

Time difference =

05:00\text{ PM} (17:00) - 08:20\text{ AM} = 8\text{ hours } 40\text{ minutes}

Determining the time span between the two locations provides the basis for calculating angular separation.

2

Convert the time difference into degrees of longitude

8\text{ hours } 40\text{ minutes} = 520\text{ minutes}

. Total angular distance =

520\text{ minutes} \div 4\text{ minutes/degree} = 130^\circ

Earth rotates

1^\circ

every 4 minutes (

15^\circ

per hour).

3

Determine direction and final longitude of Town Y

Since Town Y's time (

05:00\text{ PM}

) is ahead of Town X's time (

08:20\text{ AM}

), Town Y lies to the East of Town X. Moving

130^\circ

East from

15^\circ\text{W}

:

130^\circ - 15^\circ = 115^\circ\text{E}

Locations further east experience later local solar times. Crossing the

0^\circ

Prime Meridian shifts coordinates from West to East.

Key Concept

Calculating Longitude from Local Solar Time Differences Across Hemispheres

Question 133Question →

An astronomical observatory located at longitude $64^\circ\text{E}$ records a cosmic ray pulse at $04:12\text{ PM}$ local solar time. Simultaneously, a ground monitoring station records the exact same event at $11:48\text{ AM}$ local solar time. What is the longitude of the ground monitoring station in degrees West ( $^\circ\text{W}$ )?

Show answer & explanation

Answer: 2

Answer

The longitude of the ground monitoring station is

2^\circ\text{W}

.

The time difference between

04:12\text{ PM}

(

16:12

) and

11:48\text{ AM}

(

11:48

) is

4\text{ hours and } 24\text{ minutes}

, which corresponds to an angular separation of

66^\circ

(

4 \times 15^\circ + 24/4^\circ

). Because the time at the ground station is earlier, it lies to the west of

64^\circ\text{E}

. Subtracting

66^\circ

from

64^\circ\text{E}

crosses the

0^\circ

Prime Meridian to reach

2^\circ\text{W}

.

Step-by-Step Solution

1

Calculate the difference in local solar time between the two stations.

Time difference =

16:12 - 11:48 = 4\text{ hours and } 24\text{ minutes}

.

Determining the time interval is the first step to finding angular separation.

2

Convert the total time difference into degrees of longitude.

(4 \times 15^\circ) + (24 \div 4^\circ) = 60^\circ + 6^\circ = 66^\circ

.

The Earth rotates

15^\circ

per hour (

1^\circ

every 4 minutes).

3

Determine the relative directional position of the ground station.

The ground station is

66^\circ

west of the observatory.

Earlier local solar time indicates a position further to the west.

4

Calculate the absolute longitude across the Prime Meridian.

66^\circ - 64^\circ\text{E} = 2^\circ\text{W}

.

Moving west from

64^\circ\text{E}

uses

64^\circ

to reach

0^\circ

, leaving

2^\circ

in the Western Hemisphere.

Key Concept

Calculating longitude position across hemispheres using local solar time differences.

Question 134Question →

An international scientific symposium begins at $11:15\text{ AM}$ local solar time in City P, located at longitude $40^\circ\text{E}$ . At what local solar time does the symposium begin for a participant watching live from City Q, located at longitude $15^\circ\text{W}$ ?

07:35\text{ AM}

02:55\text{ PM}

09:35\text{ AM}

12:55\text{ PM}

Show answer & explanation

Answer: $07:35\text{ AM}$

Answer

07:35\text{ AM}

To find the time at City Q (

15^\circ\text{W}

) given the time at City P (

40^\circ\text{E}

), first calculate the total angular separation across the Prime Meridian:

40^\circ + 15^\circ = 55^\circ

. Multiplying by

4\text{ minutes per degree}

gives a total time difference of

220\text{ minutes}

, which equals

3\text{ hours } 40\text{ minutes}

. Because City Q is located to the west of City P, time must be subtracted:

11:15\text{ AM}

minus

3\text{ hours } 40\text{ minutes}

gives

07:35\text{ AM}

.

Step-by-Step Solution

1

Calculate the total longitudinal difference between City P (

40^\circ\text{E}

) and City Q (

15^\circ\text{W}

).

Longitudinal difference =

40^\circ + 15^\circ = 55^\circ

Since the two locations lie in different hemispheres (East and West), their longitudinal values must be added together to find total angular separation.

2

Convert the longitudinal difference into a time difference using the rate of

1^\circ = 4\text{ minutes}

.

Time difference =

55 \times 4\text{ minutes} = 220\text{ minutes} = 3\text{ hours } 40\text{ minutes}

The Earth rotates

360^\circ

in 24 hours, which corresponds to

15^\circ

per hour or

1^\circ

every 4 minutes.

3

Determine the local solar time at City Q by adjusting for directional orientation relative to City P.

11:15\text{ AM} - 3\text{ hours } 40\text{ minutes} = 07:35\text{ AM}

City Q is located to the west of City P, so its local time is behind (earlier than) City P.

Key Concept

Calculation of local solar time differences using longitudes across hemispheres

Estimated Time:1m 30s

Question 135Question →

Field observations along a newly excavated mountain road cut in a humid tropical region reveal that intense seasonal rainfall caused a saturated, liquefied mantle of regolith to move rapidly downhill along a distinct shear plane. Which statement accurately classifies this process and distinguishes it from weathering?

It is a mass wasting event governed by gravitational shear stress, whereas weathering involves strictly in-situ rock disintegration without downslope material transport.

It is a chemical weathering process driven by hydrolysis, wherein rainwater directly transports dissolved minerals downslope.

It is physical exfoliation weathering, in which differential thermal expansion causes outer rock sheets to slide rapidly down steep gradients.

It is metamorphic recrystallization, in which extreme pore-water pressure alters clay minerals into slate, causing slope failure.

Show answer & explanation

Answer: It is a mass wasting event governed by gravitational shear stress, whereas weathering involves strictly in-situ rock disintegration without downslope material transport.

Answer

It is a mass wasting event governed by gravitational shear stress, whereas weathering involves strictly in-situ rock disintegration without downslope material transport.

The phenomenon described involves the rapid downhill movement of saturated soil and regolith down a slope under the primary force of gravity, which defines mass wasting (e.g., mudflow or debris slide). Weathering, by contrast, is strictly an in-situ breakdown of rock without mass displacement.

Step-by-Step Solution

1

Analyze the observed phenomenon described in the scenario.

The scenario describes bulk, rapid movement of saturated regolith down a slope along a shear surface following heavy rainfall.

Identifying whether the process involves material movement or in-place breakdown is necessary to categorize it.

2

Differentiate between weathering and mass wasting.

Weathering is strictly an in-situ process (disintegration or decomposition of rocks in place without movement), while mass wasting is the downslope transfer of rock material under the direct influence of gravity.

Understanding the fundamental distinction between transport mechanisms and in-situ alteration enables correct process identification.

3

Evaluate the options based on geographical definitions.

The movement of saturated regolith downhill under gravity is a mass wasting event (such as a mudflow or debris slide), confirming that the correct response properly identifies gravitational transport while contrasting it with stationary in-situ weathering.

Eliminating options that confuse chemical/physical weathering or metamorphic rock formation with mass wasting yields the correct answer.

Key Concept

Distinction between in-situ weathering and gravity-driven mass wasting processes

Question 136Question →

Rocks are classified into three major groups based on their mode of formation. Which of the following features is a distinct characteristic of sedimentary rocks?

Stratification into layers and frequent inclusion of fossils

Interlocking crystalline structure resulting from deep thermal metamorphism

Down-slope mass movement of weathered debris driven purely by gravity

Foliated mineral banding formed by rapid cooling of molten volcanic lava

Show answer & explanation

Answer: Stratification into layers and frequent inclusion of fossils

Answer

Stratification into layers and frequent inclusion of fossils is the key defining feature of sedimentary rocks.

Sedimentary rocks are created by the deposition of organic and inorganic particles in successive strata (bedding planes). Because the process takes place at normal ambient temperatures on the surface, dead organisms buried in these layers can be preserved as fossils.

Step-by-Step Solution

1

Identify the rock formation process described.

Sedimentary rocks accumulate in layers (strata) through weathering, erosion, deposition, and lithification.

Understanding how sediments settle in water or land bodies explains their structural appearance.

2

Analyze unique characteristics resulting from this process.

Because formation occurs at low temperatures on the Earth's surface, organic material (plants and animals) can be buried and preserved as fossils between bedding planes.

Igneous rocks destroy fossils due to high molten temperatures, and metamorphic rocks deform or destroy fossils under extreme heat and pressure.

Key Concept

Characteristics of Sedimentary Rocks

Question 137Question →

The atmosphere forms the gaseous outer envelope of the Earth, divided into distinct concentric layers based on temperature trends and physical characteristics. Arrange the four atmospheric layers listed below in sequence starting from the layer closest to the Earth's surface and moving progressively upward toward outer space. What is the correct order of these atmospheric layers from lowest to highest altitude?

Drag items to arrange them in the correct order

Show answer & explanation

Answer

The correct order of atmospheric layers from the Earth's surface outward is: Troposphere, Stratosphere, Mesosphere, and Thermosphere.

The correct sequence from lowest to highest altitude is Troposphere, Stratosphere, Mesosphere, and Thermosphere. The troposphere rests on the Earth's surface, followed by the stratosphere (containing the ozone layer), then the mesosphere (where meteors burn up), and finally the thermosphere extending into space.

Step-by-Step Solution

1

Identify the atmospheric layer directly in contact with the Earth's surface.

Troposphere (0 to 8–15 km altitude).

It contains the majority of the atmosphere's mass and is the site of all meteorological processes.

2

Identify the second layer situated immediately above the tropopause.

Stratosphere (15 to 50 km altitude).

It houses the ozone layer which absorbs harmful ultraviolet radiation.

3

Identify the third layer located above the stratopause.

Mesosphere (50 to 85 km altitude).

It is the coldest layer of the atmosphere where incoming meteors burn up due to friction.

4

Identify the fourth layer extending above the mesopause toward space.

Thermosphere (85 to 600+ km altitude).

It absorbs high-energy solar X-rays and ultraviolet radiation, resulting in high thermal energy.

Key Concept

Vertical stratification and arrangement of atmospheric layers

Estimated Time:1m 0s

Question 138Question →

A coastal cliff composed of permeable sandstone overlying impermeable clay becomes saturated after heavy rainfall, causing a distinct block of rock and soil to move downslope along a curved concave surface with a backward rotational movement. Which type of mass wasting process does this scenario describe?

Slumping

Exfoliation

Carbonation

Metamorphism

Show answer & explanation

Answer: Slumping

Answer

Slumping is the correct answer because it refers to the rotational downslope movement of saturated rock and soil along a concave fracture plane.

Slumping occurs when a permeable layer overlies an impermeable layer, allowing water saturation to reduce friction and create a curved slip surface. Gravity causes the entire mass of earth to slide downward while rotating backward.

Step-by-Step Solution

1

Analyze the process mechanism and structural indicators described in the scenario.

The movement involves downslope displacement of saturated material along a curved failure plane with backward rotation.

Identifying the specific movement geometry helps distinguish slumping from other mass wasting types like soil creep or rockfall.

2

Distinguish mass movement from in-situ weathering or rock formation processes.

Process involves gravitational downslope transport rather than chemical dissolution or thermal breakdown in place.

Mass wasting requires bodily displacement under gravity, confirming slumping as the correct process.

Key Concept

Mass wasting processes (slumping/rotational slide vs. in-situ chemical/physical weathering)

Estimated Time:1m 0s

Question 139Question →

A live international cultural event is broadcast from a venue at longitude $15^\circ\text{E}$ starting at 4:00 p.m. local time. What is the local solar time for a viewer watching the live broadcast at longitude $45^\circ\text{W}$ ?

8:00 p.m.

12:00 p.m. (noon)

2:00 p.m.

6:00 p.m.

Show answer & explanation

Answer: 12:00 p.m. (noon)

Answer

12:00 p.m. (noon)

To find local solar time at

45^\circ\text{W}

relative to

15^\circ\text{E}

, calculate the total angular separation (

15^\circ + 45^\circ = 60^\circ

). Dividing by

15^\circ

per hour yields a 4-hour difference. Because

45^\circ\text{W}

lies to the west of

15^\circ\text{E}

, subtract 4 hours from 4:00 p.m., resulting in 12:00 p.m. (noon).

Step-by-Step Solution

1

Calculate total longitudinal difference between the two locations.

Since

15^\circ\text{E}

and

45^\circ\text{W}

are in opposite hemispheres relative to the Greenwich Meridian, add the values:

15^\circ + 45^\circ = 60^\circ

.

Longitudes in opposite eastern and western hemispheres must be summed to find total angular distance.

2

Convert longitudinal difference into time difference using the rate of Earth rotation (

15^\circ = 1\text{ hour}

).

\frac{60^\circ}{15^\circ/\text{hr}} = 4\text{ hours}

.

The Earth rotates

360^\circ

in 24 hours, which corresponds to

15^\circ

per hour.

3

Determine local time by applying the directional rule (East gain, West lose).

4:00\text{ p.m.} - 4\text{ hours} = 12:00\text{ p.m. (noon)}

.

The target location (

45^\circ\text{W}

) is west of the broadcasting venue (

15^\circ\text{E}

), so the time difference must be subtracted.

Key Concept

Longitude, Earth Rotation, and Local Time Calculation

Question 140Question →

Match each rock type in Column I with its corresponding formation characteristic or economic importance in Column II.

Click a left item, then click its matching right item

Show answer & explanation

Answer

Marble corresponds to the metamorphic rock formed from limestone used for decorative building; Coal corresponds to the organically formed sedimentary rock used as an energy fuel source; Basalt corresponds to the extrusive igneous rock formed by rapid cooling of lava.

Marble matches the metamorphic rock derived from limestone; Coal matches the organically accumulated sedimentary rock; Basalt matches the extrusive igneous rock formed from surface lava cooling.

Step-by-Step Solution

1

Examine Marble's origin and characteristics

Marble is a metamorphic rock formed by heat and pressure acting on limestone (parent rock).

Metamorphic processes alter pre-existing rocks without melting them.

2

Examine Coal's origin and characteristics

Coal is formed from dead vegetative matter in swampy environments, making it an organic sedimentary rock.

Sedimentary rocks can be formed mechanically, chemically, or organically.

3

Examine Basalt's origin and characteristics

Basalt cools rapidly from erupted lava on the Earth's surface, making it fine-grained and extrusive igneous.

Igneous rocks formed outside the Earth's crust are extrusive or volcanic.

Key Concept

Classification of major rock types, their formation processes, and economic applications

Physical Geography

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept