Practical Geography Practice Questions — JAMB UTME — Page 9

Question 161Question →

An environmental management team in Nigeria is configuring a Geographic Information System (GIS) to analyze continuous geographical phenomena across a river basin, such as elevation gradients and soil moisture distribution. Which of the following GIS data models is most suitable for accurately representing these continuous spatial phenomena?

The raster data model, because it represents continuous surface features through an array of grid cells, each storing a specific value.

The vector data model, because doubling grid linear dimensions automatically quadruples areal detail for continuous surfaces.

The attribute data table model, because spatial location is defined by inverting representative fractions into ground distance ratios.

The topological network model, because continuous terrain features are defined primarily as clustered nucleated points.

Show answer & explanation

Answer: The raster data model, because it represents continuous surface features through an array of grid cells, each storing a specific value.

Answer

The raster data model is most suitable because it represents continuous surface features through an array of grid cells, each storing a specific attribute value.

The raster data model divides geographical space into a continuous grid of cells (pixels), where every cell stores a measurement representing phenomena that vary continuously across a surface, such as land elevation, temperature, or moisture levels.

Step-by-Step Solution

1

Identify the nature of the spatial phenomena being modeled

Elevation gradients and soil moisture distribution vary smoothly across space without defined boundaries, making them continuous spatial phenomena.

Geographical data is categorized into discrete features (with clear boundaries) and continuous surfaces (changing seamlessly across space).

2

Select the GIS data structure optimized for continuous surface representation

The raster data structure represents space as a regular tessellation of grid cells or pixels, assigning a scalar value to every cell location.

Raster grids are mathematically and structurally ideal for continuous elevation models (DEMs), satellite imagery, and environmental gradients.

Key Concept

Raster vs. Vector GIS Data Models for Continuous and Discrete Phenomena

Estimated Time:1m 0s

Question 162Question →

A forest reserve is represented as a rectangular feature measuring $8\text{ cm}$ by $10\text{ cm}$ on Map X, which is drawn to a scale of $1 : 50,000$ . On a newly drawn map, Map Y, the same forest reserve occupies an area of $320\text{ cm}^2$ . What is the representative fraction scale of Map Y?

1 : 25,000

1 : 12,500

1 : 100,000

1 : 200,000

Show answer & explanation

Answer: $1 : 25,000$

Answer

The representative fraction scale of Map Y is

1 : 25,000

.

The original map area is

80\text{ cm}^2

and the enlarged area on Map Y is

320\text{ cm}^2

, giving an area scale factor of

4

. Taking the square root gives a linear scale factor of

2

. Dividing the original scale denominator of

50,000

by

2

gives

25,000

, resulting in a scale of

1 : 25,000

.

Step-by-Step Solution

1

Calculate the area of the forest reserve on Map X

\text{Area on Map X} = 8\text{ cm} \times 10\text{ cm} = 80\text{ cm}^2

Finding the initial area on the original map is required to determine the area enlargement ratio.

2

Calculate the area scale factor between Map X and Map Y

\text{Area Scale Factor} = \frac{\text{Area on Map Y}}{\text{Area on Map X}} = \frac{320\text{ cm}^2}{80\text{ cm}^2} = 4

The area scale factor indicates how many times larger the surface area appears on Map Y compared to Map X.

3

Determine the linear scale factor

\text{Linear Scale Factor} = \sqrt{\text{Area Scale Factor}} = \sqrt{4} = 2

Because surface area changes as the square of linear dimensions (

n^2

), the linear scale factor

n

is the square root of the area factor.

4

Calculate the new representative fraction scale for Map Y

\text{New Scale Denominator} = \frac{50,000}{2} = 25,000 \Rightarrow 1 : 25,000

Map enlargement increases the scale of the map, which means decreasing the scale denominator by dividing it by the linear scale factor.

Key Concept

Linear vs. Area Scale Relationship in Map Enlargement

Estimated Time:1m 30s

Question 163Question →

Match each description of contour line configuration on the left with the corresponding relief feature it depicts on the right.

Click a left item, then click its matching right item

Show answer & explanation

Answer

Depression matches inwardly decreasing closed contours; Conical hill matches inwardly increasing closed contours; Concave slope matches closely spaced upper contours transitioning to widely spaced lower contours; Escarpment matches extremely tight parallel contours along a linear slope face.

Each landform is uniquely characterized by its contour signature: closed loops decreasing inward represent depressions, closed loops increasing inward mark conical hills, contours spreading out downhill indicate concave slopes, and tightly clustered parallel contours represent escarpments.

Step-by-Step Solution

1

Examine contour patterns for closed loop elevations.

Decreasing inward values indicate a depression, while increasing inward values represent a hill.

Contour values represent height above sea level; dropping values inside a loop signify a basin or pit.

2

Analyze contour spacing relative to elevation changes.

Close spacing near the top and wide spacing near the bottom forms a concave slope.

Closer contour lines represent steeper gradients, whereas wider spacing indicates flatter terrain.

3

Identify linear tight contour clustering.

Merged or nearly touching contours along a slope face depict an escarpment or cliff.

A steep vertical cliff compresses horizontal distance between successive vertical intervals.

Key Concept

Interpretation of relief landforms from contour line spacing and elevation trends

Estimated Time:1m 15s

Question 164Question →

A field surveyor analyzing a topographical map with a scale of $1 : 50,000$ measures a straight line distance of $4\text{ cm}$ along a road connecting Hilltop Village at an elevation of $350\text{ m}$ and Valley Junction at an elevation of $150\text{ m}$ . What is the gradient of the road between these two settlements?

1 \text{ in } 10

1 \text{ in } 1,000

1 \text{ in } 8

1 \text{ in } 1

Show answer & explanation

Answer: $1 \text{ in } 10$

Answer

The gradient of the road is

1 \text{ in } 10

.

The gradient is determined by dividing Vertical Interval (VI) by Horizontal Equivalent (HE). With a VI of

200\text{ m}

(

350\text{ m} - 150\text{ m}

) and a ground distance HE of

2,000\text{ m}

(

4\text{ cm} \times 50,000 = 200,000\text{ cm} = 2,000\text{ m}

), the ratio

\frac{200}{2,000}

simplifies to

\frac{1}{10}

or

1 \text{ in } 10

.

Step-by-Step Solution

1

Calculate the Vertical Interval (VI)

\text{VI} = 350\text{ m} - 150\text{ m} = 200\text{ m}

Vertical Interval is the difference in elevation between the two points.

2

Calculate the Horizontal Equivalent (HE) in meters

\text{HE} = 4\text{ cm} \times 50,000 = 200,000\text{ cm} = 2,000\text{ m}

Horizontal Equivalent is the actual ground distance converted to the same unit as VI.

3

Compute the slope gradient ratio

\text{Gradient} = \frac{\text{VI}}{\text{HE}} = \frac{200\text{ m}}{2,000\text{ m}} = \frac{1}{10}

or

1 \text{ in } 10

Gradient is defined as the ratio of Vertical Interval to Horizontal Equivalent.

Key Concept

Topographic Slope and Gradient Calculation

Question 165Question →

During a flood monitoring operation along the Benue River basin, hydrologists require satellite imagery that can penetrate dense cloud cover and function effectively during both day and night. Which remote sensing system is most suitable for this task?

Active microwave radar remote sensing

Passive optical multispectral sensing

Thermal infrared radiometry

Panchromatic aerial photographic survey

Show answer & explanation

Answer: Active microwave radar remote sensing

Answer

Active microwave radar remote sensing is the most suitable system because radar operates at long electromagnetic wavelengths that penetrate clouds and rain, and active sensors supply their own illumination allowing night-time imaging.

Active microwave radar remote sensing uses synthetic aperture radar (SAR) or similar active instruments that generate their own radiation in the microwave portion of the spectrum. Long microwave signals penetrate cloud cover, fog, and rain, while self-illumination allows data acquisition regardless of daylight.

Step-by-Step Solution

1

Analyze the operational constraints specified in the scenario.

Identified key requirements: cloud penetration and round-the-clock (day/night) imaging capacity.

Selecting an appropriate remote sensing sensor requires matching environmental conditions with sensor spectral bands and energy sources.

2

Evaluate sensor energy source types (active vs. passive).

Active sensors emit their own energy pulses and do not depend on solar radiation, enabling night operation.

Passive sensors relying on reflected solar radiation cannot acquire data at night.

3

Evaluate atmospheric penetration across spectral bands.

Microwave wavelengths (1 mm to 1 m) easily pass through atmospheric cloud droplets and precipitation particles.

Shorter visible and infrared wavelengths suffer severe atmospheric scattering and absorption by clouds.

Key Concept

Active vs. Passive Remote Sensing and Microwave Atmospheric Transmission

Question 166Question →

On a topographical map with a scale of $1 : 60,000$ , a railway track connects Hill Station $X$ at an elevation of $460\text{ m}$ to Junction $Y$ at an elevation of $340\text{ m}$ . If the distance between the two points measured along the map is $5\text{ cm}$ , what is the average gradient of the slope between Station $X$ and Junction $Y$ ?

1 \text{ in } 50

1 \text{ in } 25

1 \text{ in } 5

1 \text{ in } 2,500

Show answer & explanation

Answer: $1 \text{ in } 25$

Answer

The average gradient between Station X and Junction Y is

1 \text{ in } 25

.

The vertical interval between the two stations is

460\text{ m} - 340\text{ m} = 120\text{ m}

. Using the map scale of

1 : 60,000

, a map distance of

5\text{ cm}

represents a ground horizontal distance of

5 \times 60,000\text{ cm} = 300,000\text{ cm} = 3,000\text{ m}

. Dividing the vertical interval by the horizontal equivalent gives

\frac{120}{3000} = \frac{1}{25}

, which is expressed as

1 \text{ in } 25

.

Step-by-Step Solution

1

Calculate the Vertical Interval (VI)

\text{VI} = 460\text{ m} - 340\text{ m} = 120\text{ m}

The Vertical Interval is the absolute difference in elevation between the two points.

2

Calculate the Horizontal Equivalent (HE) in meters

\text{HE} = 5\text{ cm} \times 60,000 = 300,000\text{ cm} = 3,000\text{ m}

Convert the measured map distance to ground distance using the representative fraction scale, then convert centimeters to meters.

3

Calculate the gradient ratio

\text{Gradient} = \frac{\text{VI}}{\text{HE}} = \frac{120\text{ m}}{3,000\text{ m}} = \frac{1}{25} \text{ or } 1 \text{ in } 25

Express the ratio of Vertical Interval to Horizontal Equivalent in standard

1 \text{ in } N

form by dividing both values by the vertical interval.

Key Concept

Topographic Gradient Calculation

Question 167Question →

On a topographical map drawn to a scale of $1 : 30,000$ , a straight-line distance of $10\text{ cm}$ is measured along a hillside track connecting a radio mast at an elevation of $480\text{ m}$ to a valley bridge at an elevation of $180\text{ m}$ . What is the gradient of the slope between the radio mast and the valley bridge?

1 \text{ in } 10

1 \text{ in } 100

1 \text{ in } 6.25

1 \text{ in } 3

Show answer & explanation

Answer: $1 \text{ in } 10$

Answer

The gradient of the slope is

1 \text{ in } 10

.

The slope gradient is defined as the ratio of Vertical Interval (VI) to Horizontal Equivalent (HE). The vertical rise between the radio mast (

480\text{ m}

) and the bridge (

180\text{ m}

) is

300\text{ m}

. The actual ground distance represented by

10\text{ cm}

on a

1 : 30,000

scale map is

10 \times 30,000\text{ cm} = 300,000\text{ cm} = 3,000\text{ m}

. Dividing the vertical rise by the horizontal distance gives

\frac{300}{3000} = \frac{1}{10}

, expressed as a ratio of

1 \text{ in } 10

.

Step-by-Step Solution

1

Calculate the Vertical Interval (VI)

\text{VI} = 480\text{ m} - 180\text{ m} = 300\text{ m}

Vertical Interval is the difference in height between the highest point and the lowest point.

2

Calculate the Horizontal Equivalent (HE) in ground units (meters)

\text{Ground Distance} = 10\text{ cm} \times 30,000 = 300,000\text{ cm} = 3,000\text{ m}

Multiply map distance by the scale factor and convert from centimeters to meters.

3

Compute the gradient ratio

\text{Gradient} = \frac{\text{VI}}{\text{HE}} = \frac{300\text{ m}}{3,000\text{ m}} = \frac{1}{10} = 1 \text{ in } 10

Gradient is expressed as the ratio of Vertical Interval to Horizontal Equivalent in identical units.

Key Concept

Slope and Gradient Calculation

Estimated Time:1m 30s

Question 168Question →

A geography student constructs a pie chart to illustrate the annual export earnings of agricultural commodities from a region. The total value of all exports is $\text{\$}480\text{ million}$ , with oil palm products accounting for $\text{\$}108\text{ million}$ . What is the central angle, in degrees, of the sector representing oil palm products?

Show answer & explanation

Answer: 81

Answer

The central angle of the sector representing oil palm products is

81^\circ

.

The correct answer is obtained by finding the component share of the total value (108 / 480 = 0.225) and multiplying by 360 degrees, yielding an angle of 81 degrees.

Step-by-Step Solution

1

Calculate the fractional proportion of the specific component relative to the total data value

\frac{108}{480} = 0.225

A sector in a pie chart represents a fractional part of the total statistical value.

2

Convert the calculated proportion into degrees of a circle

0.225 \times 360^\circ = 81^\circ

A full pie chart circle contains

360^\circ

, so multiplying the component proportion by

360^\circ

gives its angular representation.

Key Concept

Calculating Sector Angles in Pie Charts

Question 169Question →

Match each Geographic Information System (GIS) spatial analysis function on the left with its corresponding real-world geographic application on the right.

Click a left item, then click its matching right item

Show answer & explanation

Answer

Buffering pairs with creating a 500-meter protection zone; Overlay Analysis pairs with combining land use, slope, and soil maps for landfill site selection; Network Analysis pairs with finding the most efficient travel route through an urban road system; and Spatial Interpolation pairs with estimating temperature values at unmeasured locations.

Each spatial function maps directly to its operational definition: Buffering establishes distance boundaries (500-meter river zone); Overlay Analysis combines multiple layer criteria (landfill site selection); Network Analysis optimizes routing over line networks (emergency response travel); and Spatial Interpolation estimates continuous surface fields from point measurements (weather station interpolation).

Step-by-Step Solution

1

Identify the core operation of Buffering

Buffering involves creating a perimeter zone of defined distance around points, lines, or polygons, matching the creation of a 500-meter protection zone around a river.

Proximity analysis functions establish distance thresholds around spatial objects.

2

Identify the core operation of Overlay Analysis

Overlay analysis superimposes multiple thematic maps (slope, land use, soil) to solve multi-criteria suitability problems like landfill siting.

Spatially combining vector or raster layers enables multi-layered evaluation.

3

Identify the core operation of Network Analysis

Network analysis relies on interconnected linear paths to model flow, impedance, and optimal paths, matching emergency vehicle route selection.

Transportation and routing problems require topological network structures.

4

Identify the core operation of Spatial Interpolation

Spatial interpolation predicts values at unknown locations from known point samples, matching temperature estimation from surrounding weather stations.

Continuous atmospheric or environmental surfaces are modeled from point measurements.

Key Concept

GIS Spatial Analysis Functions

Question 170Question →

Match each drainage pattern type with its corresponding underlying geological or structural control.

Click a left item, then click its matching right item

Show answer & explanation

Answer

Dendritic pattern matches Uniformly resistant horizontal rock strata; Trellis pattern matches Folded topography with alternating parallel belts of hard and soft rocks; Radial pattern matches Central elevated dome, volcanic cone, or isolated peak; Centripetal pattern matches Enclosed inland basin, crater lake, or structural depression.

Each drainage pattern forms under specific geological conditions: uniform rock lithology allows random tree-like branching (dendritic), folded alternating hard/soft rocks force right-angle junctions along strike valleys (trellis), central high points divert water outward in all directions (radial), and central low depressions gather surrounding drainage inward (centripetal).

Step-by-Step Solution

1

Identify the geometrical characteristics of each drainage network

Tree-like branching (Dendritic), rectangular grid-like joining (Trellis), radiating outwards (Radial), and converging inwards (Centripetal).

Channel alignment is determined directly by geological controls and landforms.

2

Relate stream geometry to underlying rock structure and topography

Uniform resistance creates dendritic, folded structures yield trellis, high peaks create radial, and central depressions yield centripetal flow.

Subsurface rock hardness and surface slope dictate drainage network pattern formation.

Key Concept

Geological and structural controls on drainage patterns

Question 171Question →

A cartographer is tasked with displaying population density across different administrative districts in a state by applying varying intensities of shading, where darker shades represent higher densities. Which statistical mapping technique is being described, and what is a primary cartographic limitation of this method?

Isopleth map, which inverts the numerical scale ratio when plotting continuous lines of equal value across administrative boundaries.

Choropleth map, which falsely assumes a uniform distribution of the phenomenon throughout each administrative unit.

Proportional symbol map, which incorrectly assumes that doubling the map's linear scale doubles the represented surface area.

Flow map, which misattributes depositional statistics to upper course geographical regions.

Show answer & explanation

Answer: Choropleth map, which falsely assumes a uniform distribution of the phenomenon throughout each administrative unit.

Answer

The correct mapping technique is a choropleth map, whose primary limitation is creating an illusion of uniform population distribution across the entire administrative unit.

A choropleth map uses tonal shading or graduated colors applied to specific boundary units (such as states or districts) to display average values or densities. A major limitation of this technique is the false assumption that population density is evenly distributed across the entire area inside each boundary.

Step-by-Step Solution

1

Identify the mapping technique based on the spatial data display method.

The technique using varying shades or patterns applied within pre-defined administrative boundaries to show density or average values is a choropleth map.

Choropleth mapping relies on quantitative areal data aggregated by spatial units such as states or districts.

2

Analyze the cartographic limitations of choropleth maps.

Choropleth shading covers entire administrative zones evenly, giving the false impression that values are uniform throughout each zone.

Administrative boundaries rarely align with natural transitions in population density or spatial phenomena.

Key Concept

Choropleth Mapping and Spatial Data Generalization

Question 172Question →

During a long-distance linear measurement along a proposed road alignment, two survey assistants are conducting a chain survey. At the end of every full chain length laid on the ground, which surveying accessory is driven into the ground by the leader to mark the position and assist in tallying the total distance measured?

Marking arrows

Wooden pegs

Ranging poles

Offset rods

Show answer & explanation

Answer: Marking arrows

Answer

Marking arrows are used by the leader at the end of each full chain length to mark the spot and keep count of the distance measured.

Marking arrows (chaining pins) are small steel wire pins used during chain surveying. The leader carries a bundle of arrows and inserts one into the ground at the end of every full chain length. As the survey progresses, the follower picks them up. The number of arrows collected by the follower at any point indicates the exact number of full chain lengths measured.

Step-by-Step Solution

1

Identify the fieldwork process described

The process described is measuring a continuous long distance along a line using a chain, involving a follower and a leader.

Chain surveying over long distances requires tracking how many full chain lengths have been measured.

2

Analyze the function of each surveying accessory

Marking arrows (chaining pins) are specifically supplied in sets (usually 10) for insertion into the ground at the forward end of each chain length by the leader. The follower collects them as they move forward, providing an exact tally.

Distinguishing between station marking accessories (pegs), alignment accessories (ranging poles), offset accessories (offset rods), and tallying accessories (arrows) is essential for accurate survey procedure.

Key Concept

Fieldwork Accessories and Functions in Chain Surveying

Estimated Time:1m 0s

Question 173Question →

In a Geographic Information System (GIS) project aimed at protecting riverbanks from agricultural runoff in the Ogun River basin, environmental planners need to generate a continuous 100-metre protective zone surrounding all stream vectors. Which spatial analysis operation is most appropriate for creating this distance-based boundary zone?

Buffering

Overlay analysis

Spatial interpolation

Network analysis

Show answer & explanation

Answer: Buffering

Answer

Buffering is the spatial analysis operation designed to generate a polygon zone at a specified distance around geographic features.

Buffering is a core GIS spatial analysis tool used to perform proximity calculations. It generates a polygon zone at a predetermined distance around point, line, or polygon vector features, making it the correct method for creating a 100-metre riparian protection corridor along stream networks.

Step-by-Step Solution

1

Identify the geographical requirement stated in the problem.

The requirement is to create a uniform 100-metre protective corridor surrounding stream vectors.

Establishing a distance-based boundary around spatial features requires a proximity analysis tool.

2

Evaluate GIS spatial operations against distance corridor generation.

Buffering constructs new polygon features at a specified radius or offset distance surrounding target vector geometries.

Buffering is the standard GIS operation used for setback zones, noise boundaries, and riparian conservation corridors.

Key Concept

GIS Proximity Analysis and Buffering

Question 174Question →

Match each Geographic Information System (GIS) and Remote Sensing concept on the left with its correct functional definition on the right.

Click a left item, then click its matching right item

Show answer & explanation

Answer

Vector Data Model matches discrete feature representation via points, lines, and polygons; Georeferencing matches alignment of spatial data to coordinate reference systems; Spatial Overlay matches superimposition of thematic layers to evaluate spatial relationships; Passive Remote Sensing matches detection of natural solar reflected or thermal emitted energy.

Each fundamental GIS and Remote Sensing term directly pairs with its core technical mechanism: Vector Data Model represents discrete features using points, lines, and polygons; Georeferencing assigns spatial coordinates to digital data; Spatial Overlay combines multi-layer thematic information; and Passive Remote Sensing records naturally available solar or thermal radiation.

Step-by-Step Solution

1

Identify the data structural representation mechanism for discrete objects

Vector Data Model uses coordinate-based points, lines, and polygons to model discrete geographical features.

Vector data models store explicit geometry and boundaries using spatial coordinates.

2

Determine the process of establishing spatial location coordinates

Georeferencing links image pixels or vector nodes to real-world ground coordinates.

Without georeferencing, digital spatial data lacks real-world spatial positioning.

3

Analyze layer-based spatial integration operations

Spatial Overlay merges separate thematic layers to examine intersections and attributes.

Overlay analysis relies on combining spatial boundaries across multiple data layers.

4

Classify the sensor energy source mechanism

Passive Remote Sensing relies on ambient radiation emitted or reflected from target surfaces.

Passive sensors do not emit their own energy signal, relying instead on naturally available solar or thermal radiation.

Key Concept

GIS Data Models, Coordinate Operations, and Remote Sensing Data Acquisition Fundamentals

Estimated Time:1m 30s

Question 175Question →

Arrange the following sequential stages of a satellite remote sensing and GIS land-use mapping workflow in the correct order from initial energy capture to final spatial analysis.

Drag items to arrange them in the correct order

Show answer & explanation

Answer

The correct sequence is: (1) Detection and digital recording of reflected electromagnetic radiation by the satellite sensor, (2) Application of radiometric and geometric corrections to eliminate atmospheric and orbital distortions, (3) Supervised spectral classification to categorize land surface pixels into distinct land-use cover classes, and (4) Conversion of classified raster data into vector layers for overlay and spatial query in a GIS.

The workflow follows a standard sequence from physical signal capture to analytical integration: electromagnetic radiation is first recorded by satellite sensors, pre-processed to remove radiometric and atmospheric distortions, classified spectrally into thematic land-use categories, and finally converted into vector layers within a GIS database for spatial decision-making.

Step-by-Step Solution

1

Identify the initial physical process of data collection

Recording reflected electromagnetic energy at the sensor stage

Remote sensing workflows begin when sensors collect radiant energy from target surface features.

2

Determine the necessary data preparation step

Radiometric and geometric image pre-processing

Raw satellite imagery contains atmospheric noise and sensor distortions that must be rectified before extraction of analytical information.

3

Identify the thematic information extraction phase

Supervised spectral image classification

Corrected pixels are grouped into meaningful environmental or land-use categories using spectral response patterns.

4

Determine the final GIS integration and mapping stage

Vector conversion and GIS database overlay

Classified thematic layers are imported into GIS vector models for overlay analysis, spatial querying, and decision support.

Key Concept

Remote Sensing Data Processing and GIS Integration Workflow

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