Question

Difficulty: MediumLinear Functions and Graphs

In the xyxy-plane, the graph of the linear function ff passes through the point (2,5)(2, 5) and has a yy-intercept of (0,b)(0, b), where bb is a constant. The function gg is defined by g(x)=f(x)4g(x) = f(x) - 4. If the xx-intercept of the graph of gg is (6,0)(6, 0), what is the value of bb?

  1. A
    10
  2. B
    192\frac{19}{2}
  3. 112\frac{11}{2}Answer
  4. D
    114\frac{11}{4}

Answer

The correct value of bb is 112\frac{11}{2}.
The correct answer is the value 112\frac{11}{2}. By writing f(x)=mx+bf(x) = mx + b and using the point (2,5)(2, 5), we get m=5b2m = \frac{5-b}{2}. Applying the definition of g(x)=f(x)4g(x) = f(x) - 4 gives g(x)=mx+b4g(x) = mx + b - 4. Since the graph of gg has an xx-intercept of (6,0)(6, 0), substituting x=6x = 6 and g(6)=0g(6) = 0 gives 6m+b4=06m + b - 4 = 0. Substituting the expression for mm yields 3(5b)+b4=03(5-b) + b - 4 = 0, which simplifies to 112b=011 - 2b = 0, and thus b=112b = \frac{11}{2}.

Step-by-Step Solution

1
Write the linear function f(x)f(x) in slope-intercept form using the given yy-intercept (0,b)(0, b).
f(x)=mx+bf(x) = mx + b, where mm is the slope of the line.
This sets up the general equation of the line with unknown parameters mm and bb.
2
Substitute the coordinates of the point (2,5)(2, 5) into the equation for f(x)f(x) to express mm in terms of bb.
5=2m+b5 = 2m + b, which simplifies to m=5b2m = \frac{5 - b}{2}.
Since the point lies on the graph of ff, its coordinates must satisfy the equation.
3
Define g(x)g(x) using the relationship g(x)=f(x)4g(x) = f(x) - 4 and apply the xx-intercept (6,0)(6, 0).
g(x)=mx+b4g(x) = mx + b - 4. Since the xx-intercept is (6,0)(6, 0), we have g(6)=0g(6) = 0, which gives 6m+b4=06m + b - 4 = 0.
The xx-intercept is the point where the output of the function is zero.
4
Substitute the expression for mm from Step 2 into the equation from Step 3 and solve for bb.
6(5b2)+b4=03(5b)+b4=0153b+b4=0112b=0b=1126\left(\frac{5-b}{2}\right) + b - 4 = 0 \Rightarrow 3(5-b) + b - 4 = 0 \Rightarrow 15 - 3b + b - 4 = 0 \Rightarrow 11 - 2b = 0 \Rightarrow b = \frac{11}{2}.
This solves the system of equations to determine the value of the constant bb.

Key Concept

Linear Functions and Graphs
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