Question

Difficulty: MediumNonlinear Systems of Equations
y+11=x2y3x=7\begin{aligned} y + 11 &= x^2 \\ y - 3x &= 7 \end{aligned}

If (x,y)(x, y) is a solution to the system of equations above and x>0x > 0, what is the value of x+yx + y?

Answer: 31

Answer

The correct answer is 31.
Solving the system of equations by expressing yy in terms of xx from the linear equation gives y=3x+7y = 3x + 7. Substituting this expression for yy in the first equation yields (3x+7)+11=x2(3x + 7) + 11 = x^2, which simplifies to x23x18=0x^2 - 3x - 18 = 0. Factoring the quadratic expression gives (x6)(x+3)=0(x - 6)(x + 3) = 0, so x=6x = 6 or x=3x = -3. Since the problem specifies that x>0x > 0, the xx-value of the solution must be 66. Substituting x=6x = 6 back into the linear equation gives y=3(6)+7=25y = 3(6) + 7 = 25. The sum of xx and yy is 6+25=316 + 25 = 31.

Step-by-Step Solution

1
Express yy in terms of xx from the linear equation.
y=3x+7y = 3x + 7
This isolates the variable yy to facilitate substitution.
2
Substitute the expression for yy into the quadratic equation.
(3x+7)+11=x2(3x + 7) + 11 = x^2
This eliminates the variable yy, yielding a single equation in terms of xx.
3
Rearrange the equation into standard quadratic form.
x23x18=0x^2 - 3x - 18 = 0
Standard form (ax2+bx+c=0ax^2 + bx + c = 0) is required to solve by factoring.
4
Factor the quadratic equation.
(x6)(x+3)=0(x - 6)(x + 3) = 0
Finding factors helps determine the possible values of xx.
5
Find the values of xx and apply the positive constraint.
x=6x = 6
The equation yields x=6x = 6 and x=3x = -3. The condition x>0x > 0 restricts the solution to x=6x = 6.
6
Calculate the corresponding value of yy.
y=25y = 25
Substituting x=6x = 6 into the linear equation gives y=3(6)+7=25y = 3(6) + 7 = 25.
7
Calculate the sum of xx and yy.
3131
The problem asks for the value of x+yx + y.

Key Concept

Solving systems of nonlinear equations algebraically using substitution and quadratic factoring.

Alternative Method

Alternatively, solve the linear equation for xx to get x=y73x = \frac{y - 7}{3} and substitute this into the quadratic equation to solve for yy first. This approach is more complex because it introduces fractional terms.
Estimated Time:1m 30s
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