Question

Difficulty: MediumLinear and Exponential Growth

The number of active participants in an online educational forum has been growing exponentially since the forum was launched. At the launch of the forum (t=0t = 0), there were 5,0005,000 active participants. Two months after the launch (t=2t = 2), there were 7,2007,200 active participants. If the number of active participants continues to grow exponentially at this constant monthly percent rate, what is the number of active participants in the forum four months after the launch (t=4t = 4)?

Answer: 10368 participants

Answer

The correct number of active participants in the forum four months after the launch is 10,368.
To find the number of participants at t=4t = 4, we identify that the growth is exponential, meaning the population increases by a constant factor over equal time intervals. Since the population grew from 5,0005,000 to 7,2007,200 over a 2-month interval, the 2-month growth factor is 72005000=1.44\frac{7200}{5000} = 1.44. Because the interval from t=2t = 2 to t=4t = 4 is also exactly 2 months, the population will increase by the same factor of 1.441.44 again. Thus, the population at t=4t = 4 is 7200×1.44=103687200 \times 1.44 = 10368.

Step-by-Step Solution

1
Set up the general exponential growth model equation.
P(t)=P0btP(t) = P_0 \cdot b^t, where P(t)P(t) is the number of participants at time tt months, P0P_0 is the initial number of participants, and bb is the monthly growth factor.
Establishing the model is necessary to use the given data to solve for unknowns.
2
Solve for the growth factor squared (b2b^2) using the given data points.
7200=5000b2    b2=72005000=1.447200 = 5000 \cdot b^2 \implies b^2 = \frac{7200}{5000} = 1.44. Taking the square root gives a monthly growth factor of b=1.2b = 1.2.
Determining the growth factor allows us to project the population for future times.
3
Calculate the active participant population at t=4t = 4 using the growth factor.
P(4)=P(2)b2=72001.44=10368P(4) = P(2) \cdot b^2 = 7200 \cdot 1.44 = 10368 (or P(4)=5000(1.2)4=10368P(4) = 5000 \cdot (1.2)^4 = 10368).
Finding the number of participants four months after launch answers the question.

Key Concept

Linear and Exponential Growth
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