Question

Difficulty: Very hardNonlinear Systems of Equations

In the xyxy-plane, a circle has center (6,8)(6, 8) and is tangent to the yy-axis. A line with a positive slope mm passes through the origin and is tangent to the circle. If mm is written as a fraction in simplest form, pq\frac{p}{q}, what is the value of p+qp + q?

Answer: 31

Answer

The value of p+qp + q is 31.
The radius of the circle is 6 since the center is (6,8)(6, 8) and it is tangent to the yy-axis. Substituting the line y=mxy = mx into the circle's equation (x6)2+(y8)2=36(x-6)^2 + (y-8)^2 = 36 yields a quadratic equation in xx: (1+m2)x2(12+16m)x+64=0(1+m^2)x^2 - (12+16m)x + 64 = 0. Since the line is tangent to the circle, there is exactly one solution, meaning the discriminant of this quadratic must equal zero: (12+16m)24(1+m2)(64)=0(12+16m)^2 - 4(1+m^2)(64) = 0. Simplifying this equation yields 24m7=024m - 7 = 0, which gives a slope of m=724m = \frac{7}{24}. Since the fraction is in simplest form, p=7p=7 and q=24q=24, and their sum is 3131.

Step-by-Step Solution

1
Determine the radius of the circle.
r=6r = 6
Since the center is at (6,8)(6, 8) and the circle is tangent to the yy-axis, the radius is the horizontal distance from the center to the yy-axis.
2
Write the equation of the circle.
(x6)2+(y8)2=36(x-6)^2 + (y-8)^2 = 36
A circle with center (h,k)(h, k) and radius rr has the equation (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2.
3
Substitute y=mxy = mx into the circle's equation.
(1+m2)x2(12+16m)x+64=0(1+m^2)x^2 - (12+16m)x + 64 = 0
Substituting the equation of the line y=mxy = mx into the circle's equation and expanding gives a quadratic equation in terms of xx.
4
Set the discriminant of the quadratic equation to zero.
Δ=(12+16m)2256(1+m2)=0\Delta = (12+16m)^2 - 256(1+m^2) = 0
For the line to be tangent to the circle, the system must have exactly one real solution, meaning the quadratic equation must have a discriminant of zero.
5
Solve for the positive slope mm.
m=724m = \frac{7}{24}
Expanding and simplifying the discriminant equation yields 24m7=024m - 7 = 0, which gives m=724m = \frac{7}{24}.
6
Calculate p+qp + q using the simplest form fraction.
3131
Since m=724m = \frac{7}{24} is in simplest form, p=7p = 7 and q=24q = 24. Therefore, p+q=7+24=31p + q = 7 + 24 = 31.

Key Concept

Nonlinear Systems of Equations
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