Question

Difficulty: MediumExponential Functions and Equations

The table below shows some values of the exponential function ff, where f(t)=pqtf(t) = p \cdot q^t for constants pp and qq.

ttf(t)f(t)
008080
22180180
44405405

What is the value of qq?

Answer: 1.5

Answer

1.5
The correct answer is 1.5. Since the value of the function at t=0t = 0 is 8080, the initial value coefficient is 8080. At t=2t = 2, the value is 180180, which gives the equation 80q2=18080 \cdot q^2 = 180. Solving for q2q^2 yields q2=2.25q^2 = 2.25, and taking the positive square root gives q=1.5q = 1.5.

Step-by-Step Solution

1
Set up the general exponential equation using the initial value
f(0)=pq0=80    p=80f(0) = p \cdot q^0 = 80 \implies p = 80
The initial value at t=0t = 0 directly gives the coefficient pp because q0=1q^0 = 1.
2
Substitute another point from the table to solve for the base qq
f(2)=80q2=180    q2=2.25f(2) = 80 \cdot q^2 = 180 \implies q^2 = 2.25
Using the point (2,180)(2, 180) allows us to write an equation with one variable, qq.
3
Solve for qq by taking the square root
q=1.5q = 1.5
Since the base of an exponential function must be positive, we take the positive square root of 2.25.

Key Concept

Determining the base of an exponential function from a table of values
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