Question

Difficulty: MediumLinear Equations in Two Variables

An artist creates custom ceramic tiles in two shapes: square tiles and hexagonal tiles. Each square tile has an area of 1212 square inches, and each hexagonal tile has an area of 2828 square inches. The artist is designing a mosaic with a total area of 460460 square inches using only these two types of tiles. If the artist uses 1515 square tiles, how many hexagonal tiles are used in the mosaic?

Answer: 10

Answer

The correct answer is 10. By setting up a linear equation representing the total area of the mosaic, 12s+28h=46012s + 28h = 460, and substituting the given value of 15 for the number of square tiles, we solve for the number of hexagonal tiles to get 10.
To find the number of hexagonal tiles used in the mosaic, we set up a linear equation in two variables representing the total area. Let ss represent the number of square tiles, and let hh represent the number of hexagonal tiles. The total area is the sum of the areas of the square tiles and the hexagonal tiles, which is 12s+28h=46012s + 28h = 460. Given that the artist uses 1515 square tiles, we substitute s=15s = 15 into the equation to get 12(15)+28h=46012(15) + 28h = 460. Simplifying the equation yields 180+28h=460180 + 28h = 460. Subtracting 180180 from both sides gives 28h=28028h = 280. Dividing both sides by 2828 yields h=10h = 10. Therefore, the artist uses 10 hexagonal tiles.

Step-by-Step Solution

1
Define variables and set up the linear equation representing the total area of the mosaic.
12s+28h=46012s + 28h = 460, where ss is the number of square tiles and hh is the number of hexagonal tiles.
This models the relationship between the quantities of each tile type used and the total surface area of the mosaic.
2
Substitute the given number of square tiles into the equation.
12(15)+28h=46012(15) + 28h = 460, which simplifies to 180+28h=460180 + 28h = 460.
We are given that the artist uses exactly 15 square tiles in the design.
3
Isolate the variable term by subtracting the constant from both sides.
28h=28028h = 280.
This isolates the term containing the unknown variable on one side of the equation.
4
Solve for the remaining variable by dividing both sides by its coefficient.
h=10h = 10.
Dividing both sides by the coefficient yields the final count of hexagonal tiles.

Key Concept

Linear Equations in Two Variables
Estimated Time:1m 30s
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