Question

Difficulty: MediumInterpreting Linear Relationships in Context

A scientist measures the density of a core sample of ice as a function of depth. The density dd, in grams per cubic centimeter (g/cm3\text{g/cm}^3), of the ice at a depth of xx meters below the glacier surface is modeled by the equation d=0.0004x+0.917d = 0.0004x + 0.917. According to the model, what is the depth, in meters, at which the ice density is 0.935 g/cm30.935\text{ g/cm}^3?

Answer: 45 meters

Answer

The depth is 45 meters.
To find the depth at which the density is 0.935 g/cm30.935\text{ g/cm}^3, substitute 0.9350.935 for the density dd in the model equation, yielding 0.935=0.0004x+0.9170.935 = 0.0004x + 0.917. Subtracting 0.9170.917 from both sides gives 0.018=0.0004x0.018 = 0.0004x. Dividing both sides by 0.00040.0004 results in x=45x = 45. Therefore, the depth is 45 meters.

Step-by-Step Solution

1
Substitute the target density of 0.935 g/cm30.935\text{ g/cm}^3 for dd in the given model equation.
0.935=0.0004x+0.9170.935 = 0.0004x + 0.917
This sets up the linear equation to solve for the corresponding depth xx.
2
Subtract 0.9170.917 from both sides of the equation.
0.018=0.0004x0.018 = 0.0004x
This isolates the term containing the variable xx on one side of the equation.
3
Divide both sides of the equation by 0.00040.0004 to find the value of xx.
x=45x = 45
Dividing 0.0180.018 by 0.00040.0004 solves for the depth xx in meters.

Key Concept

Solving linear relationships in context for the independent variable given a value of the dependent variable.
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