Question

Difficulty: EasyEquivalent Algebraic Expressions

If the expression (x+5)2(x3)2(x + 5)^2 - (x - 3)^2 is equivalent to ax+bax + b for all values of xx, where aa and bb are constants, what is the value of aa?

Answer: 16

Answer

16
Expanding (x+5)2(x + 5)^2 gives x2+10x+25x^2 + 10x + 25, and expanding (x3)2(x - 3)^2 gives x26x+9x^2 - 6x + 9. Subtracting the second expression from the first requires distributing the negative sign across all terms: x2+10x+25(x26x+9)=x2+10x+25x2+6x9x^2 + 10x + 25 - (x^2 - 6x + 9) = x^2 + 10x + 25 - x^2 + 6x - 9. Combining like terms yields 16x+1616x + 16. Comparing this to ax+bax + b shows that the coefficient of xx, aa, is 16.

Step-by-Step Solution

1
Expand the first squared binomial term
(x+5)2=x2+10x+25(x + 5)^2 = x^2 + 10x + 25
To express the binomial square as a trinomial using the perfect square identity (u+v)2=u2+2uv+v2(u + v)^2 = u^2 + 2uv + v^2.
2
Expand the second squared binomial term
(x3)2=x26x+9(x - 3)^2 = x^2 - 6x + 9
To express the binomial square as a trinomial using the perfect square identity (uv)2=u22uv+v2(u - v)^2 = u^2 - 2uv + v^2.
3
Subtract the expanded expressions and distribute the negative sign
x2+10x+25x2+6x9x^2 + 10x + 25 - x^2 + 6x - 9
To combine the terms while correctly applying the distributive property to the subtracted expression.
4
Combine like terms to simplify the polynomial
16x+1616x + 16
To find the final simplified polynomial of the form ax+bax + b.
5
Compare the simplified expression to the standard form to find the value of aa
a=16a = 16
The constant aa represents the coefficient of the linear term xx, which is 16.

Key Concept

Simplifying algebraic expressions by expanding binomial products and combining like terms.
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