Question

Difficulty: HardLinear Equations in Two Variables

In the xyxy-plane, a line with a positive slope mm passes through the points (2,5)(2, 5) and (m,13)(m, 13). Which of the following is the yy-intercept of this line?

  1. A
    (0,3)(0, 3)
  2. B
    (0,9)(0, 9)
  3. (0,3)(0, -3)Answer
  4. D
    (0,1)(0, 1)

Answer

(0,3)(0, -3)
The correct answer is the point (0,3)(0, -3). The slope of the line passing through (2,5)(2, 5) and (m,13)(m, 13) is expressed as m=135m2=8m2m = \frac{13 - 5}{m - 2} = \frac{8}{m - 2}. Multiplying by m2m - 2 yields the quadratic equation m22m8=0m^2 - 2m - 8 = 0. Factoring this equation gives (m4)(m+2)=0(m - 4)(m + 2) = 0. Since the slope mm is given as positive, we select m=4m = 4. Using the point-slope form with m=4m = 4 and the point (2,5)(2, 5) yields the equation y5=4(x2)y - 5 = 4(x - 2), which simplifies to y=4x3y = 4x - 3. The yy-intercept of this line is found by setting x=0x = 0, giving y=3y = -3, or the coordinate point (0,3)(0, -3).

Step-by-Step Solution

1
Use the slope formula to express the slope of the line passing through (2,5)(2, 5) and (m,13)(m, 13) in terms of mm.
m=135m2    m=8m2m = \frac{13 - 5}{m - 2} \implies m = \frac{8}{m - 2}
The slope of a line is defined as the ratio of the change in yy to the change in xx between any two points on the line.
2
Solve the equation m=8m2m = \frac{8}{m - 2} for mm by converting it into a quadratic equation.
m(m2)=8    m22m8=0    (m4)(m+2)=0m(m - 2) = 8 \implies m^2 - 2m - 8 = 0 \implies (m - 4)(m + 2) = 0, which gives m=4m = 4 or m=2m = -2. Since the slope is positive, m=4m = 4.
Multiplying both sides by the denominator clears the fraction and allows us to solve for the unknown parameter mm using factoring.
3
Determine the equation of the line using the point-slope form with m=4m = 4 and the point (2,5)(2, 5).
y5=4(x2)    y=4x8+5    y=4x3y - 5 = 4(x - 2) \implies y = 4x - 8 + 5 \implies y = 4x - 3
The point-slope form provides a direct way to write the linear equation using a known point and the calculated slope.
4
Find the yy-intercept by evaluating the line equation at x=0x = 0.
y=4(0)3    y=3y = 4(0) - 3 \implies y = -3, which corresponds to the point (0,3)(0, -3).
The yy-intercept of any line is the point where the line crosses the yy-axis, which occurs at x=0x = 0.

Key Concept

Linear Equations in Two Variables

Alternative Method

Alternatively, once the slope m=4m = 4 is found, we can write the equation of the line in slope-intercept form y=4x+by = 4x + b. Substituting the coordinates of the point (2,5)(2, 5) into the equation gives 5=4(2)+b    5=8+b5 = 4(2) + b \implies 5 = 8 + b. Solving for bb gives b=3b = -3. Since bb is the yy-intercept, the point is (0,3)(0, -3).
Estimated Time:2m 30s
Rate this question