Question

Difficulty: MediumExponential Functions and Equations

If 5a+2=25b5^{a + 2} = 25^{b} and a+b=10a + b = 10, what is the value of bb?

Answer: 4

Answer

The correct answer is 4.
The correct answer is 4. By rewriting 25b25^b as (52)b=52b(5^2)^b = 5^{2b}, we can set the exponents equal to get a+2=2ba + 2 = 2b. Substituting a=10ba = 10 - b from the second equation into this relation yields (10b)+2=2b(10 - b) + 2 = 2b. Simplifying this gives 12=3b12 = 3b, which results in b=4b = 4.

Step-by-Step Solution

1
Rewrite the exponential equation using a common base.
5a+2=52b5^{a + 2} = 5^{2b}
Since 25=5225 = 5^2, we write 25b25^b as (52)b=52b(5^2)^b = 5^{2b} to match the base on the left side.
2
Equate the exponents from the base 5 terms.
a+2=2ba + 2 = 2b
When bases are equal, their exponents must be equal for the equation to hold.
3
Express aa in terms of bb using the linear equation a+b=10a + b = 10.
a=10ba = 10 - b
This allows for substitution into the equation from Step 2 to solve for a single variable.
4
Substitute a=10ba = 10 - b into a+2=2ba + 2 = 2b and solve for bb.
b=4b = 4
Substituting gives (10b)+2=2b    12b=2b    12=3b    b=4(10 - b) + 2 = 2b \implies 12 - b = 2b \implies 12 = 3b \implies b = 4.

Key Concept

Solving systems of equations involving exponential equations by finding a common base.
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