Question

Difficulty: EasyExponential Functions and Equations

If 3x+4=9x3^{x+4} = 9^x, what is the value of xx?

  1. 4Answer
  2. B
    2
  3. C
    -4
  4. D
    43\frac{4}{3}

Answer

4
To solve the equation 3x+4=9x3^{x+4} = 9^x, we rewrite the base 9 as 323^2, which gives 3x+4=(32)x3^{x+4} = (3^2)^x. Applying the exponent rule (am)n=amn(a^m)^n = a^{mn}, we get 3x+4=32x3^{x+4} = 3^{2x}. Since the bases are now the same, we can set the exponents equal to each other: x+4=2xx+4 = 2x. Subtracting xx from both sides yields the solution 44.

Step-by-Step Solution

1
Express both sides of the equation with a common base.
Since 9=329 = 3^2, the equation 3x+4=9x3^{x+4} = 9^x can be rewritten as 3x+4=(32)x3^{x+4} = (3^2)^x. Using the power of a power rule, this becomes 3x+4=32x3^{x+4} = 3^{2x}.
To solve an exponential equation, it is helpful to have the same base on both sides so that the exponents can be equated.
2
Set the exponents equal to each other.
x+4=2xx + 4 = 2x
Since the bases are equal and positive (and not equal to 1), their exponents must be equal.
3
Solve the linear equation for xx.
4=x4 = x (or x=4x = 4)
Subtract xx from both sides of the equation to isolate the variable.

Key Concept

Solving exponential equations by expressing terms with a common base and equating their exponents.
Estimated Time:45s
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