Question

Difficulty: EasyFunction Notation and Transformations

If the graph of y=f(x)y = f(x) contains the point (3,7)(3, 7), and the function gg is defined by g(x)=f(x+4)−2g(x) = f(x + 4) - 2, what is the value of g(−1)g(-1)?

Answer: 5

Answer

5
Since the graph of y=f(x)y = f(x) contains the point (3,7)(3, 7), we have f(3)=7f(3) = 7. The function gg is defined as g(x)=f(x+4)−2g(x) = f(x + 4) - 2. To find the value of g(−1)g(-1), we substitute x=−1x = -1 into the definition of gg: g(−1)=f(−1+4)−2=f(3)−2g(-1) = f(-1 + 4) - 2 = f(3) - 2. Substituting f(3)=7f(3) = 7 gives g(−1)=7−2=5g(-1) = 7 - 2 = 5.

Step-by-Step Solution

1
Translate the point (3,7)(3, 7) on the graph of f(x)f(x) into function notation.
f(3)=7f(3) = 7
By definition, if a point (a,b)(a, b) is on the graph of y=f(x)y = f(x), then f(a)=bf(a) = b.
2
Substitute x=−1x = -1 into the expression for g(x)g(x) to evaluate g(−1)g(-1).
g(−1)=f(−1+4)−2g(-1) = f(-1 + 4) - 2
To find g(−1)g(-1), replace every occurrence of xx with −1-1 in the function definition of g(x)g(x).
3
Simplify the input of the function ff and compute the final value.
g(−1)=f(3)−2=7−2=5g(-1) = f(3) - 2 = 7 - 2 = 5
Simplify −1+4-1 + 4 to 33, then substitute the known value f(3)=7f(3) = 7 and subtract 22.

Key Concept

Evaluating a transformed function using function notation and given coordinate points.
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