Question

Difficulty: MediumLinear Functions and Graphs

In the xyxy-plane, the graph of the linear function ff passes through the points (k,12)(k, 12) and (8,k)(8, k), where kk is a constant. If the slope of the graph of ff is 13-\frac{1}{3}, what is the value of kk?

Answer: 14

Answer

14
The slope of a line passing through (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}. Substituting the given points (k,12)(k, 12) and (8,k)(8, k) and the slope 13-\frac{1}{3} into the formula gives 13=k128k-\frac{1}{3} = \frac{k - 12}{8 - k}. Cross-multiplying yields 3(k12)=1(8k)3(k - 12) = -1(8 - k), which simplifies to 3k36=8+k3k - 36 = -8 + k. Isolating the variable kk gives 2k=282k = 28, so k=14k = 14.

Step-by-Step Solution

1
Apply the slope formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} using the points (k,12)(k, 12) and (8,k)(8, k) with slope 13-\frac{1}{3}.
13=k128k-\frac{1}{3} = \frac{k - 12}{8 - k}
The slope of a linear function is constant and defined by the ratio of the change in yy-values to the change in xx-values.
2
Cross-multiply to solve the equation for kk.
3(k12)=1(8k)3(k - 12) = -1(8 - k)
To eliminate the fractions and solve the rational equation.
3
Distribute and simplify both sides of the equation.
3k36=8+k3k - 36 = -8 + k
Distributing the constants on both sides prepares the equation for isolating the variable kk.
4
Isolate the variable kk by subtracting kk from both sides and adding 3636 to both sides.
2k=282k = 28
Grouping like terms on opposite sides of the equation.
5
Divide by 22 to find the value of kk.
k=14k = 14
To find the final numerical value of the constant kk.

Key Concept

Linear function slope formula
Estimated Time:1m 30s
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