Question

Difficulty: EasyQuadratic Functions and Graphs

The quadratic function ff is defined by f(x)=(x5)(x11)f(x) = (x - 5)(x - 11). In the xyxy-plane, the graph of y=f(x)y = f(x) is a parabola with vertex (h,k)(h, k). What is the value of hh?

Answer: 8

Answer

The value of hh is 88.
The given quadratic function is in factored form, f(x)=(x5)(x11)f(x) = (x - 5)(x - 11), which shows that the xx-intercepts of the graph are at x=5x = 5 and x=11x = 11. Because a parabola is symmetric, the xx-coordinate of its vertex, hh, is located exactly halfway between the two xx-intercepts. Calculating the average of the xx-intercepts gives h=5+112=8h = \frac{5 + 11}{2} = 8.

Step-by-Step Solution

1
Find the xx-intercepts of the parabola.
The xx-intercepts are x=5x = 5 and x=11x = 11.
The xx-intercepts of a quadratic function in the form f(x)=(xr1)(xr2)f(x) = (x - r_1)(x - r_2) occur at x=r1x = r_1 and x=r2x = r_2 because setting f(x)=0f(x) = 0 yields these roots.
2
Calculate the xx-coordinate of the vertex, hh.
h=8h = 8
Since a parabola is symmetric, its vertex lies on the axis of symmetry, which is the vertical line halfway between the xx-intercepts. The average of 55 and 1111 is 5+112=8\frac{5 + 11}{2} = 8.

Key Concept

Finding the vertex of a parabola from its factored form
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