Question

Difficulty: MediumEquivalent Algebraic Expressions

For x>0x > 0, which of the following is equivalent to the expression x3xx34\frac{\sqrt{x^3 \cdot \sqrt{x}}}{\sqrt[4]{x^3}}?

  1. A
    x4x^4
  2. B
    xx4x\sqrt[4]{x}
  3. xxAnswer
  4. D
    x2xx^2\sqrt{x}

Answer

The expression is equivalent to xx.
To simplify the expression, convert each radical into an expression with a rational exponent. The inner term of the numerator contains x=x1/2\sqrt{x} = x^{1/2}. Multiplying this by x3x^3 yields x3x1/2=x3+1/2=x7/2x^3 \cdot x^{1/2} = x^{3 + 1/2} = x^{7/2}. Applying the outer square root to this product yields x7/2=(x7/2)1/2=x7/4\sqrt{x^{7/2}} = (x^{7/2})^{1/2} = x^{7/4}. The denominator is x34=x3/4\sqrt[4]{x^3} = x^{3/4}. Dividing the simplified numerator by the denominator is performed by subtracting the exponent of the denominator from that of the numerator: x7/4/x3/4=x7/43/4=x4/4=xx^{7/4} / x^{3/4} = x^{7/4 - 3/4} = x^{4/4} = x. Therefore, the expression simplifies to xx.

Step-by-Step Solution

1
Convert the inner radical in the numerator into a fractional exponent.
The term x\sqrt{x} becomes x1/2x^{1/2}, so the product inside the outer square root becomes x3x1/2x^3 \cdot x^{1/2}.
Converting radicals to rational exponents allows the application of standard exponent properties.
2
Combine the terms inside the outer square root using exponent addition rules.
Since 3+1/2=7/23 + 1/2 = 7/2, the product is x7/2x^{7/2}.
When multiplying exponential terms with the same base, their exponents are added.
3
Simplify the entire numerator by applying the outer square root.
The numerator becomes x7/2=(x7/2)1/2=x7/4\sqrt{x^{7/2}} = (x^{7/2})^{1/2} = x^{7/4}.
Applying a square root to a term is equivalent to raising that term to the power of 1/21/2.
4
Convert the denominator into a fractional exponent.
The denominator x34\sqrt[4]{x^3} becomes x3/4x^{3/4}.
Converting the denominator's radical to a rational exponent allows division with the numerator.
5
Divide the numerator by the denominator using exponent subtraction rules.
The final expression is x7/4/x3/4=x7/43/4=x4/4=xx^{7/4} / x^{3/4} = x^{7/4 - 3/4} = x^{4/4} = x.
When dividing exponential terms with the same base, the exponent of the denominator is subtracted from the exponent of the numerator.

Key Concept

Simplification of equivalent algebraic expressions involving radical and rational exponents.

Alternative Method

An alternative approach is to substitute a convenient value for xx that is a perfect power of 4, such as x=16x = 16. The numerator becomes 16316=40964=16384=128\sqrt{16^3 \cdot \sqrt{16}} = \sqrt{4096 \cdot 4} = \sqrt{16384} = 128. The denominator becomes 1634=40964=8\sqrt[4]{16^3} = \sqrt[4]{4096} = 8. Evaluating the fraction yields 128/8=16128 / 8 = 16. Since substituting x=16x = 16 yields a value of 1616, the expression must be equivalent to xx.
Estimated Time:1m 15s
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