Question

Difficulty: MediumInterpreting Linear Relationships in Context

A commercial bakery uses a mixing bowl that initially contains some flour. A machine adds flour to the bowl at a constant rate. After the machine has been running for 88 minutes, the total mass of the flour in the bowl is 1414 kilograms. After the machine has been running for 2020 minutes, the total mass of the flour in the bowl is 2929 kilograms. The relationship between the total mass of the flour in the bowl, MM, in kilograms, and the time the machine has been running, tt, in minutes, is linear. What is the mass of the flour, in kilograms, in the bowl before the machine starts running?

Answer: 4 kg

Answer

4
The relationship between the total mass of the flour, MM, and the time, tt, is linear and can be represented by the equation M=mt+bM = mt + b, where mm is the rate at which flour is added and bb is the initial mass of the flour in the bowl. Using the two given points, (8,14)(8, 14) and (20,29)(20, 29), the slope mm is calculated as m=2914208=1512=1.25m = \frac{29 - 14}{20 - 8} = \frac{15}{12} = 1.25 kilograms per minute. Substituting m=1.25m = 1.25 and the point (8,14)(8, 14) into the linear equation gives 14=1.25(8)+b14 = 1.25(8) + b, which simplifies to 14=10+b14 = 10 + b. Solving for bb yields b=4b = 4. Therefore, the mass of the flour in the bowl before the machine starts running is 44 kilograms.

Step-by-Step Solution

1
Find the rate of change (slope) of the linear relationship.
The rate is 1.251.25 kilograms per minute.
The slope of a linear relationship represents the constant rate at which flour is added to the bowl.
2
Set up the linear equation and solve for the y-intercept.
The initial mass is 44 kilograms.
The y-intercept represents the initial mass of the flour in the bowl at t=0t = 0 minutes.

Key Concept

Interpreting the y-intercept of a linear relationship in context
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