Question

Difficulty: MediumFunction Notation and Transformations

A transformation is applied to the exponential function f(x)=2x3f(x) = 2^x - 3 to obtain a new function gg, where g(x)=f(x1)+2g(x) = -f(x - 1) + 2. What is the yy-intercept of the graph of y=g(x)y = g(x) in the xyxy-plane?

  1. A
    (0,3)(0, 3)
  2. B
    (0,32)(0, -\frac{3}{2})
  3. (0,92)(0, \frac{9}{2})Answer
  4. D
    (0,12)(0, -\frac{1}{2})

Answer

(0,92)(0, \frac{9}{2})
The correct answer is the coordinate point with yy-coordinate 92\frac{9}{2}. The yy-intercept of the graph of g(x)g(x) is found by evaluating g(0)g(0). Substituting x=0x = 0 into the transformation equation gives g(0)=f(1)+2g(0) = -f(-1) + 2. Using the definition of f(x)f(x), we find f(1)=213=0.53=2.5f(-1) = 2^{-1} - 3 = 0.5 - 3 = -2.5. Substituting this value back into the equation for g(0)g(0) yields g(0)=(2.5)+2=2.5+2=4.5g(0) = -(-2.5) + 2 = 2.5 + 2 = 4.5, which is equivalent to 92\frac{9}{2}. Therefore, the yy-intercept is the coordinate point containing 92\frac{9}{2}.

Step-by-Step Solution

1
Substitute x=0x = 0 into the definition of g(x)g(x) to find the yy-coordinate of the yy-intercept.
g(0)=f(01)+2=f(1)+2g(0) = -f(0 - 1) + 2 = -f(-1) + 2
The yy-intercept of any function y=g(x)y = g(x) occurs where the input xx is equal to 00.
2
Evaluate f(1)f(-1) using the definition f(x)=2x3f(x) = 2^x - 3.
f(1)=213=123=2.5f(-1) = 2^{-1} - 3 = \frac{1}{2} - 3 = -2.5
Evaluating f(1)f(-1) is necessary to substitute its value back into the expression for g(0)g(0).
3
Substitute the value of f(1)f(-1) back into the expression for g(0)g(0) and simplify.
g(0)=(2.5)+2=2.5+2=4.5=92g(0) = -(-2.5) + 2 = 2.5 + 2 = 4.5 = \frac{9}{2}
This yields the final yy-coordinate of the yy-intercept, which is 92\frac{9}{2}, giving the coordinate point (0,92)(0, \frac{9}{2}).

Key Concept

Applying horizontal translation, reflection across the x-axis, and vertical translation to evaluate a function at a specific point.
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