Question

Difficulty: MediumRatios, Rates, and Proportions

To create a specific type of mortar, a builder mixes cement and sand in a ratio of 22 to 55 by weight. To create a concrete mixture, the builder mixes this mortar with gravel in a ratio of 77 to 33 by weight. If the builder prepares 300300 kilograms of the concrete mixture, how many kilograms of sand are needed?

  1. A
    90
  2. B
    120
  3. 150Answer
  4. D
    210

Answer

150
To find the weight of the sand needed, first determine the weight of the mortar in the concrete mixture. The ratio of mortar to gravel is 77 to 33, meaning mortar represents 710\frac{7}{10} of the total 300300-kilogram concrete mixture. The weight of the mortar is 710×300=210\frac{7}{10} \times 300 = 210 kilograms. Next, since mortar consists of cement and sand in a ratio of 22 to 55, the sand represents 57\frac{5}{7} of the mortar's weight. Calculating 57\frac{5}{7} of 210210 kilograms yields 150150 kilograms. Therefore, the weight of the sand needed is 150150 kilograms.

Step-by-Step Solution

1
Find the total weight of the mortar in the concrete mixture.
210210 kilograms
The concrete mixture has a ratio of mortar to gravel of 77 to 33 by weight. This means mortar makes up 77+3=710\frac{7}{7+3} = \frac{7}{10} of the total concrete weight. Multiplying this fraction by the total weight of 300300 kilograms gives 710×300=210\frac{7}{10} \times 300 = 210 kilograms of mortar.
2
Find the weight of the sand within the mortar.
150150 kilograms
The mortar is composed of cement and sand in a ratio of 22 to 55 by weight. Thus, sand makes up 52+5=57\frac{5}{2+5} = \frac{5}{7} of the mortar's weight. Multiplying this fraction by the mortar's weight of 210210 kilograms yields 57×210=150\frac{5}{7} \times 210 = 150 kilograms of sand.

Key Concept

Solving multi-step ratio problems by determining part-to-whole relationships and compounding ratios.
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