Algebra

432 questions

Question 421Question

In the inequality 3(2x5)+82(kx3)1-3(2x - 5) + 8 \geq 2(kx - 3) - 1, kk is a constant. If the solution set for xx is x2x \leq 2, what is the value of kk?

Show answer & explanation

Answer: 4.5

Answer

4.5
To find the value of kk, simplify both sides of the inequality: 3(2x5)+82(kx3)1-3(2x - 5) + 8 \geq 2(kx - 3) - 1 becomes 6x+232kx7-6x + 23 \geq 2kx - 7. Grouping the variable terms on the left and constants on the right gives (6+2k)x30-(6 + 2k)x \geq -30. Because the solution set is x2x \leq 2, dividing by the negative coefficient reverses the inequality sign to yield x306+2kx \leq \frac{30}{6 + 2k}. Setting the boundary value 306+2k\frac{30}{6 + 2k} equal to 2 gives the equation 30=2(6+2k)=12+4k30 = 2(6 + 2k) = 12 + 4k. Subtracting 12 from both sides gives 18=4k18 = 4k, which results in k=4.5k = 4.5.

Step-by-Step Solution

1
Simplify both sides of the inequality
6x+232kx7-6x + 23 \geq 2kx - 7
Distribute the constants on both sides: 3(2x5)+8=6x+15+8=6x+23-3(2x - 5) + 8 = -6x + 15 + 8 = -6x + 23, and 2(kx3)1=2kx61=2kx72(kx - 3) - 1 = 2kx - 6 - 1 = 2kx - 7.
2
Isolate the variable terms on the left side and constants on the right side
(6+2k)x30-(6 + 2k)x \geq -30
Subtract 2kx2kx and 2323 from both sides to get 6x2kx723-6x - 2kx \geq -7 - 23, then factor out xx to get (6+2k)x30-(6 + 2k)x \geq -30.
3
Relate the inequality to the given solution boundary
x306+2kx \leq \frac{30}{6 + 2k}
Since the solution is x2x \leq 2, dividing both sides by the negative coefficient (6+2k)-(6 + 2k) reverses the inequality sign, yielding x30(6+2k)=306+2kx \leq \frac{-30}{-(6 + 2k)} = \frac{30}{6 + 2k}.
4
Solve for kk using the boundary equation
k=4.5k = 4.5
Set the boundary expression equal to 2: 306+2k=2\frac{30}{6 + 2k} = 2. Multiply both sides by 6+2k6 + 2k to get 30=12+4k30 = 12 + 4k, which simplifies to 18=4k18 = 4k, giving k=4.5k = 4.5.

Key Concept

Solving linear inequalities in one variable involving variable coefficients and applying the inequality direction flip when dividing by a negative value.
Question 422Question

Which of the following represents all possible values of xx that satisfy the inequality 2(x4)+9>2x+5-2(x - 4) + 9 > 2x + 5?

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Answer: x<3x < 3

Answer

x<3x < 3
Expanding the inequality by distributing 2-2 yields 2x+8+9>2x+5-2x + 8 + 9 > 2x + 5, which simplifies to 2x+17>2x+5-2x + 17 > 2x + 5. Subtracting 2x2x and 1717 from both sides isolates the variable terms, giving 4x>12-4x > -12. Dividing both sides by the negative coefficient 4-4 and reversing the inequality sign results in the solution set representing all values of xx less than 33.

Step-by-Step Solution

1
Distribute the coefficient 2-2 to the terms inside the parentheses on the left side of the inequality.
2x+8+9>2x+5-2x + 8 + 9 > 2x + 5
Applying the distributive property removes the parentheses so like terms can be combined.
2
Combine the constant terms on the left side.
2x+17>2x+5-2x + 17 > 2x + 5
Simplifying the constant terms makes it easier to isolate the variable.
3
Subtract 2x2x and 1717 from both sides of the inequality.
4x>12-4x > -12
This groups all terms containing the variable on the left side and all constant terms on the right side.
4
Divide both sides by 4-4 and reverse the inequality sign.
x<3x < 3
Dividing both sides of an inequality by a negative number requires reversing the direction of the inequality sign.

Key Concept

To solve a multi-step linear inequality, apply the distributive property, combine like terms, isolate the variable, and reverse the inequality sign when multiplying or dividing both sides by a negative number.
Question 423Question

A truck rental company charges a daily fee of 45.00plus45.00 plus 0.75 per mile driven. A driver rents a truck for one day, has a budget of at most $150.00, and is required to drive at least 60 miles for a delivery. What is the maximum number of additional miles the driver can drive beyond the required 60 miles without exceeding the budget?

Show answer & explanation

Answer: 80

Answer

80
To find the maximum number of additional miles, we set up the inequality 45+0.75(60+a)15045 + 0.75(60 + a) \leq 150, where aa represents the number of additional miles driven. Distributing 0.750.75 yields 45+45+0.75a15045 + 45 + 0.75a \leq 150, which simplifies to 90+0.75a15090 + 0.75a \leq 150. Subtracting 9090 from both sides gives 0.75a600.75a \leq 60. Finally, dividing by 0.750.75 gives a80a \leq 80. The maximum value of aa is therefore 80.

Step-by-Step Solution

1
Set up the inequality representing the total budget constraint.
45+0.75(60+a)15045 + 0.75(60 + a) \leq 150, where aa is the number of additional miles.
The daily fee is 45,thepermilerateis45, the per-mile rate is 0.75, the driver must drive at least 60 miles plus aa additional miles, and the total cost cannot exceed the $150 budget.
2
Simplify the expression by distributing 0.750.75 and combining constant terms.
90+0.75a15090 + 0.75a \leq 150
0.75×60=450.75 \times 60 = 45, and adding the daily fee of 4545 gives 9090.
3
Isolate the variable term by subtracting 9090 from both sides.
0.75a600.75a \leq 60
This determines the remaining budget available for the additional miles.
4
Solve for aa by dividing both sides by 0.750.75.
a80a \leq 80
Dividing 6060 by 0.750.75 gives the maximum number of additional miles.

Key Concept

Solving multi-step linear inequalities in context
Question 424Question

Which inequality is equivalent to 3(3x5)4<2x+18-3(3x - 5) - 4 < -2x + 18?

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Answer: x>1x > -1

Answer

x>1x > -1
The correct inequality is found by first expanding 3(3x5)-3(3x - 5) to get 9x+15-9x + 15. The inequality becomes 9x+154<2x+18-9x + 15 - 4 < -2x + 18, which simplifies to 9x+11<2x+18-9x + 11 < -2x + 18. Adding 2x2x to both sides gives 7x+11<18-7x + 11 < 18. Subtracting 1111 from both sides gives 7x<7-7x < 7. Dividing both sides by the negative coefficient 7-7 requires reversing the inequality sign, yielding x>1x > -1.

Step-by-Step Solution

1
Distribute 3-3 to both terms inside the parentheses: 3(3x5)-3(3x - 5).
9x+154<2x+18-9x + 15 - 4 < -2x + 18
This expands the expression using the distributive property, making sure to multiply both 3x3x and 5-5 by 3-3, which changes the sign of the constant term to positive 1515.
2
Combine the constant terms on the left side of the inequality.
9x+11<2x+18-9x + 11 < -2x + 18
Simplifying the constant terms (154=1115 - 4 = 11) makes it easier to isolate the variable.
3
Add 2x2x to both sides of the inequality to group the variable terms on the left.
7x+11<18-7x + 11 < 18
This combines the xx terms on one side of the inequality.
4
Subtract 1111 from both sides of the inequality to group the constant terms on the right.
7x<7-7x < 7
This isolates the term with the variable on the left side.
5
Divide both sides of the inequality by 7-7 and reverse the inequality sign.
x>1x > -1
Since we are dividing by a negative number, the inequality sign must be reversed from less than (<<) to greater than (>>).

Key Concept

Solving linear inequalities in one variable, including the distributive property and division by negative numbers.
Question 425Question

An environmentalist studies the sound level of a waterfall. The sound level, SS, in decibels (dB\text{dB}), at a distance of dd meters from the base of the waterfall is modeled by the equation S=920.15dS = 92 - 0.15d, where 0d2000 \leq d \leq 200. What is the best interpretation of the SS-intercept of the graph of this equation in the dSdS-plane?

Show answer & explanation

Answer: The sound level of the waterfall is 92 decibels92\text{ decibels} at its base.

Answer

The sound level of the waterfall is 92 decibels92\text{ decibels} at its base.
The SS-intercept of the graph in the dSdS-plane occurs where the horizontal variable, dd, is equal to 00. Substituting d=0d = 0 into the equation yields S=920.15(0)=92S = 92 - 0.15(0) = 92. Since dd represents the distance from the base of the waterfall in meters and SS represents the sound level in decibels, this means that at a distance of 00 meters (the base of the waterfall), the sound level is 92 decibels92\text{ decibels}.

Step-by-Step Solution

1
Identify the definition of the SS-intercept in the context of the dSdS-plane.
The SS-intercept is the point on the graph where the independent variable, dd (distance), is equal to 00.
By definition, the vertical intercept of a graph occurs where the horizontal coordinate is zero.
2
Substitute d=0d = 0 into the linear equation.
S=920.15(0)=92S = 92 - 0.15(0) = 92.
Evaluating the equation at d=0d = 0 determines the value of the sound level at zero meters from the base.
3
Interpret the mathematical result in the real-world context.
At a distance of 00 meters (which is the base of the waterfall), the sound level is 92 decibels92\text{ decibels}.
This connects the coordinate point (0,92)(0, 92) to the physical properties of the scenario.

Key Concept

Interpreting the vertical intercept of a linear relationship in context
Estimated Time:1m 30s
Question 426Question

In a certain board game, a player receives 1515 points for each quest completed, but loses 44 points for each penalty card drawn. A player completes 1212 quests and draws cc penalty cards. If the player's total score is greater than 120120 points, what is the maximum possible value of cc?

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Answer: 14

Answer

14
The player earns a base score of 15×12=18015 \times 12 = 180 points from quests, and loses 44 points for each of the cc penalty cards, resulting in a total score of 1804c180 - 4c points. Because the score must be greater than 120120, we write the inequality 1804c>120180 - 4c > 120. Subtracting 180180 from both sides yields 4c>60-4c > -60. Dividing by 4-4 and reversing the inequality sign gives c<15c < 15. Since cc must represent a whole number of cards, the maximum possible value is the largest integer less than 1515, which is 1414.

Step-by-Step Solution

1
Set up the inequality representing the score constraint.
1804c>120180 - 4c > 120
The player earns 1515 points for each of the 1212 quests (15×12=18015 \times 12 = 180) and loses 44 points for each of the cc penalty cards (4c4c), and this total must exceed 120120.
2
Isolate the variable term by subtracting 180180 from both sides.
4c>60-4c > -60
To solve for cc, we first subtract the constant term 180180 from both sides of the inequality.
3
Divide both sides by 4-4 and reverse the inequality sign.
c<15c < 15
Dividing an inequality by a negative number requires reversing the direction of the inequality sign.
4
Determine the maximum integer value for cc.
1414
Since the number of penalty cards cc must be a whole number and cc must be strictly less than 1515, the largest possible value is 1414.

Key Concept

Solving linear inequalities in one variable involving multiplication or division by a negative number and interpreting the solution set in a discrete context.
Question 427Question

A botanist is studying the transpiration rate of a certain plant species under controlled conditions. The transpiration rate TT, in grams of water vapor per square meter of leaf area per hour (g/m2/h\text{g/m}^2/\text{h}), is modeled by a linear function of the relative humidity HH, expressed as a decimal where 0.20H0.800.20 \leq H \leq 0.80. The model is represented by the equation T=4.8H+CT = -4.8H + C, where CC is a constant. Based on this model, if the relative humidity increases by 0.150.15, what is the corresponding decrease in the transpiration rate, in g/m2/h\text{g/m}^2/\text{h}?

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Answer: 0.72

Answer

The correct answer is 0.72.
In the linear equation T=4.8H+CT = -4.8H + C, the coefficient of HH (which is 4.8-4.8) represents the slope of the line. The slope indicates that for every increase of 1.01.0 in the relative humidity HH, the transpiration rate TT decreases by 4.84.8 grams of water vapor per square meter of leaf area per hour. To find the decrease in transpiration rate corresponding to an increase of 0.150.15 in relative humidity, multiply the rate of change by the change in relative humidity: 4.8×0.15=0.724.8 \times 0.15 = 0.72. Thus, the transpiration rate decreases by 0.720.72 grams of water vapor per square meter of leaf area per hour.

Step-by-Step Solution

1
Identify the slope of the linear model.
The slope is 4.8-4.8.
The coefficient of HH in the linear equation T=4.8H+CT = -4.8H + C represents the rate of change of the transpiration rate with respect to the relative humidity.
2
Calculate the change in the transpiration rate (ΔT\Delta T) for an increase of 0.150.15 in the relative humidity (ΔH=0.15\Delta H = 0.15).
ΔT=4.8×0.15=0.72\Delta T = -4.8 \times 0.15 = -0.72
The change in the dependent variable is equal to the slope multiplied by the change in the independent variable.
3
Determine the magnitude of the decrease.
The decrease in the transpiration rate is 0.720.72.
The negative sign in the change ΔT=0.72\Delta T = -0.72 represents a decrease, so the amount of decrease is 0.720.72.

Key Concept

Interpreting the slope of a linear relationship in context as the rate of change of the dependent variable with respect to the independent variable.
Question 428Question

A manufacturing plant uses a heating chamber for curing composite materials. The temperature TT, in degrees Celsius (C^\circ\text{C}), of the chamber mm minutes after the heating element is turned on is modeled by the equation T=3.5m+22T = 3.5m + 22, where 0m600 \leq m \leq 60. The chamber must reach a target temperature of 180C180^\circ\text{C} for the curing process. Which of the following is the best interpretation of the value 180223.5\frac{180 - 22}{3.5} in this context?

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Answer: The number of minutes it takes for the heating chamber to reach the target temperature of 180C180^\circ\text{C}

Answer

The number of minutes it takes for the heating chamber to reach the target temperature of 180C180^\circ\text{C}
The correct answer represents the time needed to reach the target temperature. To find when the temperature TT reaches 180C180^\circ\text{C}, we substitute 180180 for TT in the equation T=3.5m+22T = 3.5m + 22, giving 180=3.5m+22180 = 3.5m + 22. Solving for time mm requires subtracting the initial temperature of 22C22^\circ\text{C} from the target temperature of 180C180^\circ\text{C}, and then dividing by the heating rate of 3.5C3.5^\circ\text{C} per minute. This algebraic isolation results in m=180223.5m = \frac{180 - 22}{3.5}, representing the duration in minutes to reach that target.

Step-by-Step Solution

1
Identify the meaning of each term in the linear model.
In the equation T=3.5m+22T = 3.5m + 22, TT represents the chamber's temperature, mm represents time in minutes, 3.53.5 represents the rate of temperature increase per minute, and 2222 represents the initial temperature of the chamber.
Understanding the components of the linear equation helps contextualize the mathematical operations performed in the expression.
2
Set up the equation using the target temperature.
The target temperature is 180C180^\circ\text{C}. Setting T=180T = 180 gives the linear equation 180=3.5m+22180 = 3.5m + 22.
This establishes the relationship between the target temperature and the time mm required to reach it.
3
Solve for the variable mm representing time.
Subtract 2222 from both sides to get 18022=3.5m180 - 22 = 3.5m, then divide both sides by 3.53.5 to isolate mm, yielding m=180223.5m = \frac{180 - 22}{3.5}.
Isolating mm shows that the expression is mathematically equivalent to the time, in minutes, at which the temperature reaches 180C180^\circ\text{C}.

Key Concept

Interpreting expressions derived from linear relationships in real-world contexts

Alternative Method

Use dimensional analysis to verify the units of the expression. The numerator (18022)(180 - 22) represents the difference between two temperatures in degrees Celsius (C^\circ\text{C}), which yields a temperature change in C^\circ\text{C}. The denominator, 3.53.5, represents the rate of change in degrees Celsius per minute (C/min^\circ\text{C}/\text{min}). Dividing C^\circ\text{C} by C/min^\circ\text{C}/\text{min} results in minutes: CC/min=min\frac{^\circ\text{C}}{^\circ\text{C}/\text{min}} = \text{min}. This confirms the expression represents a time duration.
Estimated Time:1m 30s
Question 429Question

What is the solution set for the inequality 2(3x4)+5x+3-2(3x - 4) + 5 \leq -x + 3?

Show answer & explanation

Answer: x2x \geq 2

Answer

x2x \geq 2
Distributing 2-2 over 3x43x - 4 yields 6x+8-6x + 8. Combining the constants on the left gives 6x+13x+3-6x + 13 \leq -x + 3. Subtracting 1313 and adding xx to both sides results in 5x10-5x \leq -10. Dividing both sides by 5-5 and flipping the inequality symbol yields the solution set of all values greater than or equal to 22.

Step-by-Step Solution

1
Distribute the 2-2 coefficient on the left side of the inequality.
6x+8+5x+3-6x + 8 + 5 \leq -x + 3
Applying the distributive property simplifies the expression inside the parentheses.
2
Combine the constant terms on the left side of the inequality.
6x+13x+3-6x + 13 \leq -x + 3
Combining like terms simplifies the left-hand side before isolating the variable.
3
Subtract 1313 from both sides of the inequality.
6xx10-6x \leq -x - 10
This begins the process of isolating the variable terms on one side and constant terms on the other.
4
Add xx to both sides of the inequality.
5x10-5x \leq -10
This groups all variable terms together on the left-hand side.
5
Divide both sides of the inequality by 5-5 and reverse the direction of the inequality sign.
x2x \geq 2
Dividing an inequality by a negative number requires reversing the inequality sign to maintain a true statement.

Key Concept

Solving linear inequalities in one variable using algebraic properties, specifically distributing a negative value and reversing the inequality direction when dividing by a negative number.
Question 430Question

A shipping service charges a flat rate of 15.50toshipabox,plus15.50 to ship a box, plus 0.50 per ounce of the total weight of the box. A customer wants to ship a package and wants the total shipping cost to be at most $40.00. If the empty box weighs 14 ounces, what is the maximum weight, in ounces, of the contents that can be placed inside the box?

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Answer: 35

Answer

The maximum weight of the contents that can be placed inside the box is 35 ounces.
To find the maximum weight of the contents, let ww represent the weight of the contents in ounces. The total weight of the package is the sum of the content weight and the empty box weight, or w+14w + 14 ounces. The total shipping cost is the flat rate of 15.50plus15.50 plus 0.50 times the total weight, which is represented by the expression 15.50+0.50(w+14)15.50 + 0.50(w + 14). Since the customer wants the cost to be at most 40.00,wewritetheinequality40.00, we write the inequality 15.50 + 0.50(w + 14) \leq 40.00 .Distributing. Distributing 0.50 yields yields 15.50 + 0.50w + 7 \leq 40.00 .Combiningtheconstanttermsgives. Combining the constant terms gives 22.50 + 0.50w \leq 40.00 .Subtracting. Subtracting 22.50 frombothsidesresultsin from both sides results in 0.50w \leq 17.50 .Finally,dividingbothsidesby. Finally, dividing both sides by 0.50 gives gives w \leq 35$. Thus, the maximum weight of the contents is 35 ounces.

Step-by-Step Solution

1
Define the variable and write the inequality representing the total cost constraints.
15.50+0.50(w+14)40.0015.50 + 0.50(w + 14) \leq 40.00
The total weight is the sum of the contents (ww) and the empty box (14 ounces), and the cost is 15.50plus15.50 plus 0.50 per ounce, which cannot exceed $40.00.
2
Distribute the rate of $0.50 per ounce across the weight terms and simplify.
22.50+0.50w40.0022.50 + 0.50w \leq 40.00
Applying the distributive property gives 0.50w+7.000.50w + 7.00, and adding the flat rate 15.5015.50 simplifies the left side.
3
Isolate the variable term by subtracting 22.5022.50 from both sides.
0.50w17.500.50w \leq 17.50
This isolates the variable term 0.50w0.50w on one side of the inequality.
4
Solve for ww by dividing both sides by 0.500.50.
w35w \leq 35
Dividing by 0.500.50 (or multiplying by 2) yields the maximum weight limit for the contents.

Key Concept

Solving linear inequalities in one variable using distributive properties and combining like terms.
Question 431Question

An agricultural irrigation system draws water from a storage tank at a constant rate. The volume of water, VV, in gallons, remaining in the tank mm minutes after the irrigation begins is given by the equation V=12,00045mV = 12,000 - 45m. According to the model, after how many minutes of irrigation will there be exactly 8,4008,400 gallons of water remaining in the tank?

Show answer & explanation

Answer: 80

Answer

The irrigation system will have exactly 8,4008,400 gallons of water remaining after 8080 minutes.
To find the number of minutes, mm, when the volume of water remaining is exactly 8,4008,400 gallons, substitute 8,4008,400 for VV in the given linear model: 8,400=12,00045m8,400 = 12,000 - 45m. Subtracting 12,00012,000 from both sides of the equation yields 3,600=45m-3,600 = -45m. Dividing both sides of the equation by 45-45 yields m=80m = 80. Therefore, after 8080 minutes, there will be exactly 8,4008,400 gallons of water remaining in the tank.

Step-by-Step Solution

1
Substitute the target volume of 8,4008,400 gallons for VV in the linear model equation.
8,400=12,00045m8,400 = 12,000 - 45m
We want to find the number of minutes, mm, when the remaining volume, VV, is exactly 8,4008,400 gallons.
2
Subtract 12,00012,000 from both sides of the equation.
3,600=45m-3,600 = -45m
This isolates the variable term 45m-45m on one side of the equation.
3
Divide both sides by 45-45 to solve for mm.
m=80m = 80
This isolates mm to find the number of minutes elapsed.

Key Concept

Solving linear equations in context
Question 432Question

A commercial drone descends from a mapping mission at a constant rate. The altitude of the drone, AA, in meters, tt seconds after it begins its descent is modeled by the equation A=4.5t+360A = -4.5t + 360. The graph of this equation in the tAtA-plane is shown below.

Which of the following is the best interpretation of the tt-intercept of the graph in this context?

Show answer & explanation

Answer: The number of seconds it takes for the drone to reach sea level.

Answer

The tt-intercept represents the number of seconds it takes for the drone to reach sea level.
The correct answer is the option stating that the intercept represents the number of seconds it takes for the drone to reach sea level. The tt-intercept is the point on the graph where A=0A = 0. In this context, A=0A = 0 means the drone's altitude is 00 meters (sea level), and tt represents the time elapsed in seconds. Setting A=0A = 0 in the equation A=4.5t+360A = -4.5t + 360 gives t=80t = 80, meaning it takes 8080 seconds for the drone to reach sea level.

Step-by-Step Solution

1
Identify the meaning of the tt-intercept on the graph.
The tt-intercept is the point on the graph where the vertical coordinate, AA, is equal to 00.
By definition, the horizontal intercept of a function occurs when the dependent variable (altitude, AA) is zero.
2
Relate the condition A=0A = 0 to the context.
An altitude of A=0A = 0 meters corresponds to sea level.
The variable AA represents altitude in meters, so A=0A = 0 represents the level where altitude is zero, which is sea level.
3
Interpret the corresponding value of tt.
The tt-coordinate represents the time, in seconds, when the altitude is 0.
Since tt represents the number of seconds after the descent began, the tt-intercept (80,0)(80, 0) indicates that it takes 8080 seconds for the drone to reach sea level.

Key Concept

Interpreting the intercepts of a linear relationship in context.
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