Question

Difficulty: EasyDivisibility Rules and Remainder Theorem

If the six-digit number 45231x45231x is completely divisible by 99, what is the value of the digit xx?

Answer: 3

Answer

3
According to the divisibility rule for 9, a number is divisible by 9 if the sum of its digits is a multiple of 9. For the number 45231x45231x, the sum of the digits is 4+5+2+3+1+x=15+x4 + 5 + 2 + 3 + 1 + x = 15 + x. The smallest multiple of 9 that is greater than or equal to 15 is 18. Setting 15+x=1815 + x = 18 gives x=3x = 3.

Step-by-Step Solution

1
Find the sum of the known digits in the given number.
4+5+2+3+1=154 + 5 + 2 + 3 + 1 = 15
The divisibility rule for 9 requires analyzing the sum of all digits.
2
Formulate the condition for divisibility by 9.
15+x15 + x must be a multiple of 9.
Including the unknown unit digit xx, the total digit sum is 15+x15 + x.
3
Solve for the single-digit integer xx where 0x90 \le x \le 9.
x=3x = 3
The smallest multiple of 9 greater than or equal to 15 is 18, giving 15+x=1815 + x = 18, so x=3x = 3.

Key Concept

Divisibility Rule for 9

Alternative Method

Dividing 452,310 by 9 yields 50,256 with a remainder of 6. To make the number divisible by 9, the remaining amount needed is 96=39 - 6 = 3, so the unit digit xx must be 3.
Estimated Time:45s
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