Question

Difficulty: Very hardLogical Venn Diagrams

In a district administrative audit of 240240 agricultural cooperatives, compliance with three digital platforms was surveyed: E-Farming Portal (PP), Soil Health Database (SS), and Crop Insurance Registry (II). It was found that 115115 cooperatives use PP, 110110 use SS, and 105105 use II. Exactly 2525 cooperatives do not use any of the three platforms, and 2020 cooperatives use all three platforms. Furthermore, the number of cooperatives using only PP, only SS, and only II are in the ratio 8:9:78 : 9 : 7, respectively. How many cooperatives use exactly two of these digital platforms?

  1. 75Answer
  2. B
    95
  3. C
    55
  4. D
    90

Answer

The number of cooperatives using exactly two digital platforms is 75.
By applying the principle of inclusion-exclusion across the 3 sets, the union of all three platforms is 24025=215240 - 25 = 215. Expressing the total elements as the sum of single-platform users (a+b+c)(a+b+c), exactly-two-platform users (d+e+f)(d+e+f), and all-three-platform users (2020), we get (a+b+c)+(d+e+f)=195(a+b+c) + (d+e+f) = 195. Summing the individual set totals without the central intersection yields (a+b+c)+2(d+e+f)=95+90+85=270(a+b+c) + 2(d+e+f) = 95 + 90 + 85 = 270. Subtracting the first equation from the second eliminates (a+b+c)(a+b+c) directly, leaving d+e+f=270195=75d+e+f = 270 - 195 = 75.

Step-by-Step Solution

1
Calculate the total number of cooperatives using at least one digital platform.
Total using at least one platform = 24025=215240 - 25 = 215.
Subtracting the cooperatives that use none of the platforms from the total audited population gives the union of all three sets PSI|P \cup S \cup I|.
2
Set up equations for single-region and double-region intersection counts using set partition variables.
Let a,b,ca, b, c be the counts for only PP, only SS, and only II respectively. Let d,e,fd, e, f be the counts for exactly two platforms (PSP \cap S only, SIS \cap I only, PIP \cap I only). The count for all three platforms is g=20g = 20.
Dividing the 3-set Venn diagram into 7 mutually exclusive regions allows exact algebraic formulation.
3
Express total set union and individual set totals in terms of these regions.
Equation 1 (Union): (a+b+c)+(d+e+f)+20=215    (a+b+c)+(d+e+f)=195(a + b + c) + (d + e + f) + 20 = 215 \implies (a + b + c) + (d + e + f) = 195.
Individual sets:
P=a+d+f+20=115    a+d+f=95|P| = a + d + f + 20 = 115 \implies a + d + f = 95
S=b+d+e+20=110    b+d+e=90|S| = b + d + e + 20 = 110 \implies b + d + e = 90
I=c+e+f+20=105    c+e+f=85|I| = c + e + f + 20 = 105 \implies c + e + f = 85.
Each individual set sum accounts for its unique region, adjacent two-set intersections, and the three-set intersection.
4
Sum the three individual set equations and solve for (d+e+f)(d + e + f).
Equation 2 (Sum of set equations): (a+b+c)+2(d+e+f)=95+90+85=270(a + b + c) + 2(d + e + f) = 95 + 90 + 85 = 270.
Subtracting Equation 1 from Equation 2:
[(a+b+c)+2(d+e+f)][(a+b+c)+(d+e+f)]=270195[(a + b + c) + 2(d + e + f)] - [(a + b + c) + (d + e + f)] = 270 - 195
(d+e+f)=75(d + e + f) = 75.
Subtracting the union sum eliminates the single-region terms (a+b+c)(a + b + c) directly, isolating the sum of regions representing exactly two platforms.

Key Concept

Principle of Inclusion-Exclusion and Region Partitioning in 3-Set Venn Diagrams
Estimated Time:3m 0s
Rate this question