Question

Difficulty: MediumNumber and Alphabet Series
What is the next term that continues the pattern established in the following alphanumeric sequence?
Z2B,X6E,V12H,T20K,Z2B, X6E, V12H, T20K, \dots
  1. R30NR30NAnswer
  2. B
    R28NR28N
  3. C
    R30MR30M
  4. D
    S30NS30N

Answer

R30NR30N
The sequence consists of three parallel sub-patterns: the first letters decrease by 2 positions (ZXVTRZ \rightarrow X \rightarrow V \rightarrow T \rightarrow R), the middle numbers increase by expanding even differences +4,+6,+8,+10+4, +6, +8, +10 (261220302 \rightarrow 6 \rightarrow 12 \rightarrow 20 \rightarrow 30), and the trailing letters increase by 3 positions (BEHKNB \rightarrow E \rightarrow H \rightarrow K \rightarrow N). Combining these yields R30NR30N.

Step-by-Step Solution

1
Analyze the pattern of the first letter in each term
Z (26) -> X (24) -> V (22) -> T (20) -> R (18)
Each term's first letter shifts backward by 2 positions in alphabetical order.
2
Analyze the pattern of the middle number in each term
2, 6, 12, 20, 30
The difference between consecutive numbers increases by 2 each step (+4, +6, +8, +10).
3
Analyze the pattern of the last letter in each term
B (2) -> E (5) -> H (8) -> K (11) -> N (14)
Each term's last letter shifts forward by 3 positions in alphabetical order.
4
Combine the derived elements to form the next term
First letter: R, Middle number: 30, Last letter: N => R30N
Synthesizing all three independent rules yields the required term in the sequence.

Key Concept

Multi-pattern Alphanumeric Series
Estimated Time:1m 15s
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