If January 15, 1894 fell on a Monday, what day of the week was January 15, 1904?
Answer: Friday / friday / FRIDAY
Answer
Friday
The period from January 15, 1894 to January 15, 1904 covers exactly 10 years. Within this period, we must count how many times February 29th is crossed. The year 1896 contributes one extra day. The year 1900 is a century year not divisible by 400, so it is a common year and contributes no extra days. The year 1904 is a leap year, but because the end date is January 15, we do not cross its February 29th, so it also contributes no extra days to this interval. The total number of odd days is 10 (for the 10 years) + 1 (for 1896) = 11. Dividing 11 by 7 leaves a remainder of 4. Four days after Monday is Friday.
Step-by-Step Solution
Key Concept
Calculating odd days across a century boundary and evaluating leap year inclusion based on the month.
Alternative Method
You can count the shift year by year: 1894 to 1895 (+1), '95 to '96 (+1), '96 to '97 (+2, crosses Feb '96), '97 to '98 (+1), '98 to '99 (+1), '99 to 1900 (+1), 1900 to '01 (+1), '01 to '02 (+1), '02 to '03 (+1), '03 to 1904 (+1, stops in Jan). The total is 11, giving a net shift of 4 days.
Estimated Time:1m 0s