Question

Difficulty: EasyFactors, Multiples, and Prime Factorization

What is the total number of positive integer factors of 120120?

Answer: 16

Answer

The total number of positive integer factors of 120120 is 1616.
By prime factorizing 120120, we get 23×31×512^3 \times 3^1 \times 5^1. Applying the factor count formula (a+1)(b+1)(c+1)(a+1)(b+1)(c+1), we obtain (3+1)(1+1)(1+1)=4×2×2=16(3+1)(1+1)(1+1) = 4 \times 2 \times 2 = 16.

Step-by-Step Solution

1
Find the prime factorization of 120120
120=23×31×51120 = 2^3 \times 3^1 \times 5^1
To calculate the total number of factors systematically, express the number as a product of prime factors.
2
Apply the total factor count formula
Number of factors = (3+1)(1+1)(1+1)(3 + 1)(1 + 1)(1 + 1)
If a number N=pa×qb×rcN = p^a \times q^b \times r^c, the total number of positive factors is (a+1)(b+1)(c+1)(a+1)(b+1)(c+1).
3
Compute the product
4×2×2=164 \times 2 \times 2 = 16
Multiplying the incremented prime exponents gives the total count of factors.

Key Concept

Number of Positive Factors from Prime Factorization
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