Question

Difficulty: HardLogical Venn Diagrams

In a state administration academy, a cohort of 150150 officer trainees completed specialized skill modules in Artificial Intelligence (AA), Blockchain Technology (BB), and Cyber Security (CC). Data from the academy administration indicates:
- 7575 trainees enrolled in Artificial Intelligence (AA)
- 6565 trainees enrolled in Blockchain Technology (BB)
- 6060 trainees enrolled in Cyber Security (CC)
- 3030 trainees enrolled in both Artificial Intelligence and Blockchain Technology
- 2525 trainees enrolled in both Blockchain Technology and Cyber Security
- 2020 trainees enrolled in both Artificial Intelligence and Cyber Security
- 1010 trainees enrolled in all three modules

Based on the provided data, which of the following statements regarding the trainee enrollment are correct?

  1. The total number of trainees enrolled in exactly one training module is 8080.Answer
  2. B
    The total number of trainees enrolled in exactly two training modules is 7575.
  3. The total number of trainees enrolled in at least two training modules is 5555.Answer
  4. D
    The total number of trainees enrolled in none of the three training modules is 2525.

Answer

The statements asserting that 8080 trainees are enrolled in exactly one training module and that 5555 trainees are enrolled in at least two training modules are correct.
The correct evaluation shows that exactly one module enrollment totals 35+20+25=8035 + 20 + 25 = 80, and at least two modules enrollment totals 45+10=5545 + 10 = 55.

Step-by-Step Solution

1
Identify the region for trainees taking all three modules.
n(ABC)=10n(A \cap B \cap C) = 10.
This fundamental triple intersection value must be subtracted from pairwise intersections to isolate dual-module regions.
2
Calculate trainees enrolled in exactly two modules.
Only A and B=3010=20A \text{ and } B = 30 - 10 = 20; Only B and C=2510=15B \text{ and } C = 25 - 10 = 15; Only A and C=2010=10A \text{ and } C = 20 - 10 = 10. Total taking exactly two modules = 20+15+10=4520 + 15 + 10 = 45.
Subtracting the triple intersection isolates individuals taking exclusively two subjects.
3
Calculate trainees enrolled in exactly one module.
Only A=75(20+10+10)=35A = 75 - (20 + 10 + 10) = 35; Only B=65(20+15+10)=20B = 65 - (20 + 15 + 10) = 20; Only C=60(10+15+10)=25C = 60 - (10 + 15 + 10) = 25. Total taking exactly one module = 35+20+25=8035 + 20 + 25 = 80.
Subtracting dual and triple overlaps from total single set numbers yields single-module counts.
4
Determine total trainees taking at least one module and trainees taking none.
Total taking at least one module =80 (single)+45 (double)+10 (triple)=135= 80 \text{ (single)} + 45 \text{ (double)} + 10 \text{ (triple)} = 135. Trainees taking none =150135=15= 150 - 135 = 15.
Applying set summation gives total enrolled trainees, from which the non-enrolled count is derived.

Key Concept

Three-Set Venn Diagram Region Decomposition using Inclusion-Exclusion Principle
Estimated Time:2m 0s
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