Question

Difficulty: HardVenn Diagrams and Set-Based Data

A survey was conducted among 400400 administrative officers in a state secretariat regarding their operational oversight of three major public welfare projects: Project Alpha, Project Beta, and Project Gamma. The survey collected the following data:

- 190190 officers oversee Project Alpha.
- 180180 officers oversee Project Beta.
- 170170 officers oversee Project Gamma.
- 8585 officers oversee both Project Alpha and Project Beta.
- 7575 officers oversee both Project Beta and Project Gamma.
- 7070 officers oversee both Project Alpha and Project Gamma.
- 4040 officers do not oversee any of these three projects.

Based on the given information, how many administrative officers oversee exactly two projects?

  1. 8080Answer
  2. B
    130130
  3. C
    180180
  4. D
    230230

Answer

The number of administrative officers who oversee exactly two projects is 8080.
The value 8080 is correct because subtracting those in no projects from the total of 400400 gives 360360 officers in at least one project. Using the inclusion-exclusion principle formula yields 5050 officers in all three projects. Subtracting 5050 from each pairwise intersection gives 3535, 2525, and 2020 for the three exclusive two-project regions, summing to 8080.

Step-by-Step Solution

1
Calculate the total number of officers supervising at least one project.
ABC=40040=360|A \cup B \cup C| = 400 - 40 = 360
Officers who oversee at least one project are found by subtracting those overseeing none from the total surveyed officers.
2
Apply the Principle of Inclusion-Exclusion for three sets to find the triple intersection (ABC|A \cap B \cap C|).
360=190+180+170(85+75+70)+ABC    360=540230+ABC    ABC=50360 = 190 + 180 + 170 - (85 + 75 + 70) + |A \cap B \cap C| \implies 360 = 540 - 230 + |A \cap B \cap C| \implies |A \cap B \cap C| = 50
The standard set formula accounts for single set totals, pairwise intersections, and the three-set intersection.
3
Determine the number of officers in each exclusive two-project intersection.
Only Alpha & Beta = 8550=3585 - 50 = 35; Only Beta & Gamma = 7550=2575 - 50 = 25; Only Alpha & Gamma = 7050=2070 - 50 = 20
Subtracting the triple intersection from each pairwise intersection yields the count of officers managing exactly two projects.
4
Sum the exclusive two-project regions.
35+25+20=8035 + 25 + 20 = 80
Adding these three disjoint set regions gives the total number of officers handling exactly two projects.

Key Concept

Three-Set Inclusion-Exclusion Principle and Set Region Decomposition
Estimated Time:2m 30s
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