Question

Difficulty: HardDivisibility Rules and Remainder Theorem

Consider the largest three-digit natural number NN which, when successively divided by 66, 77, and 88, leaves remainders of 44, 33, and 55 respectively. What is the true positive remainder when the mathematical expression E=4263NE = 42^{63} - N is divided by 1313?

  1. A
    3
  2. 7Answer
  3. C
    8
  4. D
    6

Answer

The correct remainder is 7.
The correct answer is derived by first reconstructing the number through successive division logic to find N=904N = 904. Next, applying Fermat's Little Theorem simplifies 4263(mod13)42^{63} \pmod{13} to 11. The expression becomes 17=6(mod13)1 - 7 = -6 \pmod{13}, which correctly maps to a true positive remainder of 77.

Step-by-Step Solution

1
Determine the algebraic form of the number NN based on the successive division conditions.
N=336Q3+232N = 336 \cdot Q_3 + 232
By working backward from the final quotient Q3Q_3, we construct the relations: Q2=8Q3+5Q_2 = 8 \cdot Q_3 + 5, Q1=7Q2+3Q_1 = 7 \cdot Q_2 + 3, and N=6Q1+4N = 6 \cdot Q_1 + 4. Substituting these yields the general form for NN.
2
Find the largest three-digit natural number NN.
N=904N = 904
Substitute increasing integer values for Q3Q_3. For Q3=0Q_3 = 0, N=232N = 232. For Q3=1Q_3 = 1, N=568N = 568. For Q3=2Q_3 = 2, N=904N = 904. For Q3=3Q_3 = 3, N=1240N = 1240 (which is four digits). Thus, 904904 is the largest valid three-digit number.
3
Calculate the remainder of 426342^{63} divided by 1313.
42631(mod13)42^{63} \equiv 1 \pmod{13}
Since 42=13×3+342 = 13 \times 3 + 3, 423(mod13)42 \equiv 3 \pmod{13}. By Fermat's Little Theorem, 3121(mod13)3^{12} \equiv 1 \pmod{13}. Breaking down the exponent: 63=12×5+363 = 12 \times 5 + 3. Thus, 363(312)533152727(mod13)3^{63} \equiv (3^{12})^5 \cdot 3^3 \equiv 1^5 \cdot 27 \equiv 27 \pmod{13}. Finally, 27(mod13)=127 \pmod{13} = 1.
4
Calculate the remainder of NN divided by 1313 and evaluate the full expression EE.
E7(mod13)E \equiv 7 \pmod{13}
904=13×69+7904 = 13 \times 69 + 7, so N7(mod13)N \equiv 7 \pmod{13}. Substituting the remainders into the expression: E17=6(mod13)E \equiv 1 - 7 = -6 \pmod{13}. To find the true positive remainder, add the divisor: 6+13=7-6 + 13 = 7.

Key Concept

Combining Successive Division modeling with Modular Exponentiation and Negative Remainder conversion.
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