Question

Difficulty: MediumBlood Relations

An algorithmic database maps family connections using the following symbolic notation:

A+BA + B signifies that AA is the brother of BB.
ABA - B signifies that AA is the sister of BB.
A×BA \times B signifies that AA is the father of BB.
A÷BA \div B signifies that AA is the mother of BB.

Given the relational data sequence: C×DE×F+GC \times D - E \times F + G

Based strictly on this sequence, which of the following statements must be true?

  1. A
    GG is the grandson of CC.
  2. B
    DD is the maternal aunt of FF.
  3. CC is the paternal grandfather of GG.Answer
  4. D
    FF is the paternal uncle of GG.

Answer

The statement asserting that CC is the paternal grandfather of GG is definitely true.
The sequence E×F+GE \times F + G establishes that EE is the father of FF, and FF is the brother of GG. Therefore, EE is the father of both FF and GG. The preceding sequence C×DEC \times D - E establishes that CC is the father of DD, who is the sister of EE. Thus, CC is the father of EE. Since CC is the father of GG's father (EE), CC is definitively the paternal grandfather of GG.

Step-by-Step Solution

1
Analyze the first portion of the relational sequence: C×DEC \times D - E.
CC is the father of DD, and DD is the sister of EE. Therefore, CC is the father of both DD and EE.
To establish the relationships and gender identities in the first generation.
2
Analyze the second portion of the relational sequence: E×F+GE \times F + G.
EE is the father of FF, and FF is the brother of GG. Thus, EE is the father of both FF and GG. This also confirms that EE is male.
To establish the relationships in the second generation and confirm EE's role as a father.
3
Combine the deduced relationships across generations.
CC is the father of EE (who is male), and EE is the father of GG. Therefore, CC is the father of GG's father.
To deduce the final kinship required to evaluate the given statements.

Key Concept

Family Tree Tracing and Gender Identification in Coded Relations
Estimated Time:1m 0s
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