Question

Difficulty: Very hardNumber and Alphabet Series
Consider the following complex alphanumeric sequence:
C3F,E8I,H18L,L38O,Q78R,C3F, E8I, H18L, L38O, Q78R, \dots

Which of the following terms logically completes the series?

  1. W158UW158UAnswer
  2. B
    V158UV158U
  3. C
    W156UW156U
  4. D
    W158VW158V

Answer

W158UW158U
The term is obtained by breaking the alphanumeric code into three parallel streams: (1) First letter follows increasing step intervals (+2, +3, +4, +5, +6), bringing Q (17) to W (23). (2) Numerical component uses the rule 2x+22x + 2, converting 78 to 158. (3) Second letter has a constant increment of +3, moving R (18) to U (21). Combining these gives the complete term W158UW158U.

Step-by-Step Solution

1
Analyze the pattern of the first letter in each term
Positions in alphabet: C (3), E (5), H (8), L (12), Q (17). The positional increments are +2, +3, +4, +5. Following this pattern, the next increment must be +6. Adding 6 to Q (17) yields 23, which corresponds to the letter W.
The first element follows an increasing arithmetic step pattern.
2
Analyze the numerical progression in the terms
Sequence of numbers: 3, 8, 18, 38, 78. The recurrence relation is Nk=2×Nk1+2N_k = 2 \times N_{k-1} + 2. Calculating the next value: 2×78+2=156+2=1582 \times 78 + 2 = 156 + 2 = 158.
Each number is formed by doubling the previous term and adding 2.
3
Analyze the pattern of the second letter in each term
Positions in alphabet: F (6), I (9), L (12), O (15), R (18). The positional increment is constant at +3. Adding 3 to R (18) yields 21, which corresponds to the letter U.
The third element follows a constant positional step pattern.
4
Synthesize the components to form the final term
Combining the calculated first letter (W), numerical middle value (158), and second letter (U) yields W158UW158U.
All three independent term rules must be combined.

Key Concept

Multi-Pattern Alphanumeric Series Completion
Estimated Time:2m 0s
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