Question

Difficulty: HardNumber and Alphabet Series

Consider the numerical sequence: 5,11,24,51,106,217,5, 11, 24, 51, 106, 217, \dots. What is the value of the next term in this sequence?

Answer: 440

Answer

The next term in the sequence is 440.
The sequence follows the recurrence pattern where each term is twice the previous term plus an increasing integer offset: 5×2+1=115 \times 2 + 1 = 11, 11×2+2=2411 \times 2 + 2 = 24, 24×2+3=5124 \times 2 + 3 = 51, 51×2+4=10651 \times 2 + 4 = 106, 106×2+5=217106 \times 2 + 5 = 217. Following this pattern, the next term is 217×2+6=440217 \times 2 + 6 = 440.

Step-by-Step Solution

1
Examine the relationship between successive terms.
The differences between successive terms are 6,13,27,55,1116, 13, 27, 55, 111, and the second-level differences are 7,14,28,567, 14, 28, 56 (doubling each step). Alternatively, each term is multiplied by 2 and increased by an incrementing integer.
Analyzing both direct operations and higher-order differences establishes the recurrence rule an+1=2an+na_{n+1} = 2a_n + n.
2
Determine the required operation for the next step in the sequence.
Multiply the 6th term (217) by 2 and add 6.
The additive component increases by 1 at each term (+1,+2,+3,+4,+5+6+1, +2, +3, +4, +5 \rightarrow +6).
3
Calculate the value of the next term.
217×2+6=440217 \times 2 + 6 = 440.
217×2=434217 \times 2 = 434, and adding 6 yields 440.

Key Concept

Recurrent series with multiplicative factor and sequential linear increment
Estimated Time:1m 30s
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