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Difficulty: MediumNumber and Alphabet Series
Which of the following terms logically completes the given alphanumeric series?
C24X,F20U,I16R,L12O,?C24X, \quad F20U, \quad I16R, \quad L12O, \quad ?
  1. O8LO8LAnswer
  2. B
    N8LN8L
  3. C
    O8MO8M
  4. D
    O10LO10L

Answer

O8LO8L
The term containing O8LO8L is correct because it satisfies all three independent series rules: the first letter advances by 3 (L+3=OL + 3 = O), the middle number decreases by 4 (12−4=812 - 4 = 8), and the third letter shifts backward by 3 (O−3=LO - 3 = L).

Step-by-Step Solution

1
Analyze the pattern of the first letter in each term
The first letters follow the sequence: C(3)→+3F(6)→+3I(9)→+3L(12)→+3O(15)C (3) \xrightarrow{+3} F (6) \xrightarrow{+3} I (9) \xrightarrow{+3} L (12) \xrightarrow{+3} O (15).
The first letter advances by 3 positions in alphabetical order.
2
Analyze the pattern of the numerical term
The numbers follow the sequence: 24→−420→−416→−412→−4824 \xrightarrow{-4} 20 \xrightarrow{-4} 16 \xrightarrow{-4} 12 \xrightarrow{-4} 8.
Each number decreases by a constant difference of 4.
3
Analyze the pattern of the last letter in each term
The last letters follow the sequence: X(24)→−3U(21)→−3R(18)→−3O(15)→−3L(12)X (24) \xrightarrow{-3} U (21) \xrightarrow{-3} R (18) \xrightarrow{-3} O (15) \xrightarrow{-3} L (12).
The last letter moves backward by 3 positions in alphabetical order.
4
Combine the resulting components
Combining OO, 88, and LL yields the missing term O8LO8L.
Synthesizing all three independent rules completes the sequence.

Key Concept

Alphanumeric Series Completion with Simultaneous Forward-Reverse Letter Shifts and Arithmetic Decrement
Estimated Time:1m 0s
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Topics

Number and Alphabet Series

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