General Mental Ability

303 questions

Question 21Question

What is the next letter in the given alphabetical series: Z,X,V,T,R,Z, X, V, T, R, \dots?

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Answer: PP

Answer

The correct next letter in the sequence is PP.
Each term in the series moves backward by 2 steps in the standard English alphabet: Z(26)X(24)V(22)T(20)R(18)Z (26) \rightarrow X (24) \rightarrow V (22) \rightarrow T (20) \rightarrow R (18). Continuing this constant decrease of 2 leads to the 16th letter, which is PP.

Step-by-Step Solution

1
Determine the alphabetical positions of each given letter in the series
Z=26Z = 26, X=24X = 24, V=22V = 22, T=20T = 20, R=18R = 18
Converting letters to numerical positions helps reveal the mathematical pattern.
2
Identify the common difference between consecutive terms
2426=224 - 26 = -2, 2224=222 - 24 = -2, 2022=220 - 22 = -2, 1820=218 - 20 = -2
Each letter is obtained by moving 2 positions backward in the alphabet.
3
Apply the pattern to find the next position and letter
182=1618 - 2 = 16, which corresponds to the letter PP
Subtracting 2 positions from the 18th letter (RR) gives the 16th letter (PP).

Key Concept

Reverse Alphabetical Positional Shifts
Question 22Question
Consider the following multi-pattern alphanumeric sequence:
D4W,G9T,L16P,S35K,D66E,D4W, G9T, L16P, S35K, D66E, \dots
Which of the following terms logically completes the sequence?
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Answer: Q137XQ137X

Answer

The term that logically completes the sequence is Q137XQ137X.
The next term in the sequence is obtained by synthesizing three distinct rules: the first letter moves forward by consecutive prime steps (+13+13 from DD yields QQ), the number multiplies by 22 and adds 55 to yield 137137, and the trailing letter moves +7+7 steps in reverse positional values (EE at reverse index 22 moves to 29, which is reverse index 3 or letter XX). Combining these gives Q137XQ137X.

Step-by-Step Solution

1
Analyze the first letter progression: DGLSD?D \rightarrow G \rightarrow L \rightarrow S \rightarrow D \rightarrow ?
Alphabetical positions (1 to 26): D=4,G=7,L=12,S=19,D=304(mod26)D=4, G=7, L=12, S=19, D=30 \equiv 4\pmod{26}. The step differences are +3,+5,+7,+11+3, +5, +7, +11, which are prime numbers. The next prime increment is +13+13. Adding 1313 to D(4)D(4) gives 1717, corresponding to letter QQ.
The first letter advances according to consecutive prime increments modulo 26.
2
Analyze the numerical middle component: 4,9,16,35,66,?4, 9, 16, 35, 66, ?
9=2(4)+19 = 2(4) + 1, 16=2(9)216 = 2(9) - 2, 35=2(16)+335 = 2(16) + 3, 66=2(35)466 = 2(35) - 4. Following Nk=2Nk1+(1)k+1kN_k = 2 N_{k-1} + (-1)^{k+1} k, the next term is 2(66)+5=1372(66) + 5 = 137.
The numerical pattern multiplies the previous number by 2 and alternates adding/subtracting sequential integers.
3
Analyze the second letter progression using reverse positional values: W,T,P,K,E,?W, T, P, K, E, ?
Reverse positions (Z=1,Y=2,,A=26Z=1, Y=2, \dots, A=26): W=4,T=7,P=11,K=16,E=22W=4, T=7, P=11, K=16, E=22. Increments in reverse positions are +3,+4,+5,+6+3, +4, +5, +6. The next reverse position increment is +7+7, giving 22+7=293(mod26)22 + 7 = 29 \equiv 3\pmod{26}. Reverse position 3 corresponds to forward letter XX (273=2427 - 3 = 24).
The second letter steps through increasing increments in reverse alphabetical indexing.

Key Concept

Multi-pattern alphanumeric series involving prime positional shifts, alternating linear recursive relations, and reverse alphabetical indexing.
Estimated Time:2m 30s
Question 23Question

In a regional agricultural seed bank's categorization system, crop names are converted into numerical codes for database entry. Under this specific protocol, the crop name "WHEAT" is coded as "4-19-5-1-7", and the crop name "BARLEY" is coded as "25-1-9-15-5-2". Following the exact same logical pattern, how will the crop name "MAIZE" be coded?

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Answer: 14-1-9-1-5

Answer

14-1-9-1-5
The correct answer is derived by observing that all consonants are transformed into their reverse alphabetical positions (e.g., M=13 becomes 14, Z=26 becomes 1), while all vowels maintain their standard forward alphabetical positions (e.g., A=1, I=9, E=5). Combining these values in sequence produces 14-1-9-1-5.

Step-by-Step Solution

1
Determine the standard alphabetical positions of the letters in the first example, 'WHEAT'.
W=23, H=8, E=5, A=1, T=20.
Establishing the base numerical values is the first step in identifying coding transformations.
2
Compare the base numerical values of 'WHEAT' with its given code: '4-19-5-1-7'.
W(23) becomes 4. H(8) becomes 19. E(5) remains 5. A(1) remains 1. T(20) becomes 7.
This comparison reveals the specific mathematical or logical transformation applied to each letter.
3
Identify the underlying logical rule governing the transformations.
Consonants (W, H, T) are assigned their reverse alphabetical positions (calculated as 27 - forward position). Vowels (E, A) retain their standard forward alphabetical positions.
Defining the conditional rule is required before it can be reliably applied to other words.
4
Verify the identified rule using the second example, 'BARLEY'.
Forward positions: B=2, A=1, R=18, L=12, E=5, Y=25. Applying the rule: B(consonant) -> 25, A(vowel) -> 1, R(consonant) -> 9, L(consonant) -> 15, E(vowel) -> 5, Y(consonant) -> 2. Code is 25-1-9-15-5-2, which perfectly matches the given code.
Testing the hypothesis against a second dataset confirms the logic is universally applied within the system.
5
Apply the verified rule to the target word 'MAIZE'.
M(13, consonant) -> 27-13 = 14. A(1, vowel) -> 1. I(9, vowel) -> 9. Z(26, consonant) -> 27-26 = 1. E(5, vowel) -> 5.
Translating the target string using the established algorithm yields the final answer.

Key Concept

Mixed Alphanumeric Substitution using Vowel/Consonant Conditional Logic and Reverse Indexing
Question 24Question

Select the letter-cluster that is related to the third letter-cluster in the same way that the second letter-cluster is related to the first letter-cluster.

TASK : XYWI :: POND : ?

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Answer: TMRB

Answer

The correct letter-cluster is TMRB.
The relationship between the first and second letter-clusters follows an alternating alphabetical shift pattern. The first and third letters are shifted forward by 4 positions (+4), while the second and fourth letters are shifted backward by 2 positions (-2), with standard circular alphabetical wrap-around. Applying this identical +4, -2, +4, -2 sequence to the letters P, O, N, and D yields T, M, R, and B respectively.

Step-by-Step Solution

1
Analyze the positional shifts between the first pair of letter-clusters: TASK and XYWI.
T(20) to X(24) is +4. A(1 or 27) to Y(25) is -2. S(19) to W(23) is +4. K(11) to I(9) is -2.
Establishing the underlying logical rule requires checking the step interval for every individual letter to ensure the full pattern is identified.
2
Determine the unified rule governing the analogy.
The alternating shift sequence is +4, -2, +4, -2.
This confirms that the transformation is not a uniform shift, but an alternating forward and backward arithmetic progression.
3
Apply the identical +4, -2, +4, -2 pattern to the target letter-cluster: POND.
P(16) + 4 = T(20). O(15) - 2 = M(13). N(14) + 4 = R(18). D(4) - 2 = B(2).
To maintain the analogical relationship, the exact sequence of operations must be applied to the new group.

Key Concept

Alphabetical Positional Alternating Shifts
Question 25Question

A tourist is exploring a historical monument. He starts from the main gate and walks 30 m30\text{ m} towards the West. He then turns 135135^{\circ} to his left and walks 202 m20\sqrt{2}\text{ m}. Next, he turns 4545^{\circ} to his right and walks 10 m10\text{ m}. Finally, he turns 9090^{\circ} to his left and walks 50 m50\text{ m}. What is his shortest distance and direction from the main gate?

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Answer: 50 m50\text{ m}, South-East

Answer

The shortest distance is 50 m50\text{ m} and the direction is South-East.
By tracking the movements sequentially on a 2D coordinate plane from an origin of (0, 0), the tourist's positions are (-30, 0), (-10, -20), (-10, -30), and finally (40, -30). The straight-line distance from the origin to (40, -30) is the hypotenuse of a right triangle with legs of 40 and 30, which equals 50. The coordinate (40, -30) lies in the lower-right quadrant, indicating a South-East direction.

Step-by-Step Solution

1
Map the starting point as the origin (0, 0) and execute the first movement.
Walking 30 m30\text{ m} West places the tourist at (-30, 0) facing West.
Establishing a Cartesian coordinate system allows for precise tracking of movements.
2
Calculate the second movement: turn 135135^{\circ} left and walk 202 m20\sqrt{2}\text{ m}.
A 135135^{\circ} left turn from West changes the facing direction to South-East. Moving 202 m20\sqrt{2}\text{ m} South-East adds +20+20 to the X-axis and 20-20 to the Y-axis. New position: (-30 + 20, 0 - 20) = (-10, -20).
A left turn is counter-clockwise. West minus 135135^{\circ} equals South-East. Breaking this diagonal vector into components yields equivalent +20 m+20\text{ m} East and 20 m-20\text{ m} South.
3
Calculate the third movement: turn 4545^{\circ} right and walk 10 m10\text{ m}.
A 4545^{\circ} right (clockwise) turn from South-East points South. Walking 10 m10\text{ m} South subtracts 10 from the Y-axis. New position: (-10, -20 - 10) = (-10, -30).
Right turns add clockwise rotation, shifting the direction from diagonal to a cardinal line.
4
Calculate the final movement: turn 9090^{\circ} left and walk 50 m50\text{ m}.
A 9090^{\circ} left (counter-clockwise) turn from South points East. Walking 50 m50\text{ m} East adds 50 to the X-axis. Final position: (-10 + 50, -30) = (40, -30).
Standard orthogonal rotation maps the final displacement vector.
5
Calculate the direct distance and direction from the origin (0,0) to the final point (40, -30).
Distance = 402+(30)2=1600+900=50 m\sqrt{40^2 + (-30)^2} = \sqrt{1600 + 900} = 50\text{ m}. Since X is positive (East) and Y is negative (South), the direction is South-East.
The Pythagorean theorem determines the shortest straight-line Euclidean distance, and the quadrant dictates the cardinal direction.

Key Concept

Vector displacement combining angular turns, Cartesian mapping, and the Pythagorean theorem.
Question 26Question

Six historic ships��Bounty, Cutty Sark, Discovery, Endeavour, Mayflower, and Victoria—are anchored in a single straight row facing North (towards the harbor). Their left-to-right positions are determined by the following conditions:

1. The Discovery is anchored at the extreme left end of the row.
2. The Victoria is anchored exactly midway between the Mayflower and the Endeavour.
3. The Bounty anchors immediately to the right of the Mayflower.
4. The Cutty Sark anchors immediately to the left of the Endeavour.
5. The Cutty Sark and the Victoria are anchored next to each other.

Arrange the ships in the correct order from the extreme left (1st position) to the extreme right (6th position).

Drag items to arrange them in the correct order

Show answer & explanation

Answer

The correct sequence from left to right is: Discovery, Mayflower, Bounty, Victoria, Cutty Sark, Endeavour.
The correct sequence is established by recognizing how the adjacency rules merge into larger blocks. By deducing that the Cutty Sark and Endeavour form a 'C-E' pair, and Victoria must sit next to Cutty Sark to form 'V-C-E', we establish the exact distance between Victoria and Endeavour (2 positions). Because Victoria must be midway between Mayflower and Endeavour, the Mayflower must also be exactly 2 positions away on the opposite side. This forces the 'Mayflower-Bounty' pair to sit immediately left of Victoria, yielding a unified 5-ship block 'M-B-V-C-E' that perfectly slots in next to the Discovery.

Step-by-Step Solution

1
Establish the given anchor.
Position 1 is Discovery (D). The sequence is currently D, _, _, _, _, _.
Condition 1 explicitly states Discovery is at the extreme left end.
2
Combine adjacency conditions to form fixed spatial blocks.
We identify a two-ship block (M - B) and a three-ship block (V - C - E).
Condition 4 requires Cutty Sark (C) to be immediately left of Endeavour (E), forming 'C - E'. Condition 5 requires Victoria (V) to be next to C. Since placing V to the right of C would break the 'C - E' block, V must be immediately to the left of C, forming 'V - C - E'. Condition 3 requires Bounty (B) to be immediately right of Mayflower (M), forming 'M - B'.
3
Apply the midway condition to combine the blocks into a single sequence.
The combined sequence becomes M - B - V - C - E.
Condition 2 states V is exactly midway between M and E. In our 'V - C - E' block, E is exactly two positions to the right of V. Therefore, M must be exactly two positions to the left of V. Placing the 'M - B' block immediately before V perfectly satisfies this midway requirement.
4
Finalize the arrangement by placing the unified block.
The final arrangement is D, M, B, V, C, E.
We have a solid 5-ship sequence (M - B - V - C - E). With Discovery anchored at position 1, the only way to fit the remaining 5 ships is consecutively in positions 2 through 6.

Key Concept

Linear seating arrangement combining relative positional blocks and distance/midpoint constraints.
Estimated Time:2m 30s
Question 27Question

In a cryptographic system used for secure communications, the word 'CROWN' is coded as 'ETNYP'. Based on this same coding logic, match the following words on the left with their correct coded forms on the right.

Click a left item, then click its matching right item

Items

PAINT
SHARK
MOUSE
BRICK

Matches

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Answer

PAINT matches with RZHPV, SHARK matches with UJZTM, MOUSE matches with ONTUD, and BRICK matches with DTHEM.
Each word perfectly aligns with its encrypted code when applying the specific rule derived from the stem: shifting consonants forward by 2 letters in the alphabet, and shifting vowels backward by 1 letter.

Step-by-Step Solution

1
Analyze the example 'CROWN' to identify the shift pattern for each letter.
C becomes E (+2), R becomes T (+2), O becomes N (-1), W becomes Y (+2), and N becomes P (+2).
Identifying how the example word is transformed is the first step in decoding the underlying encryption logic.
2
Generalize the coding rule based on the distinct letter types.
Consonants (C, R, W, N) are shifted forward by 2 positions (+2). The vowel (O) is shifted backward by 1 position (-1).
A consistent rule must be established that applies differently to vowels and consonants in order to decode other words.
3
Apply the derived rule to the target words on the left.
Applying the rule yields: PAINT -> RZHPV, SHARK -> UJZTM, MOUSE -> ONTUD, BRICK -> DTHEM.
Encoding each word accurately allows us to find its correct corresponding match on the right side.

Key Concept

Coding based on letter categorization (vowels vs. consonants) with distinct positional shifts.
Question 28Question

A university establishes a new scholarship fund on September 15, 2195, which happens to be a Friday. The founding document states that a major administrative review of the fund will occur exactly 1212 years later on September 15, 2207. What day of the week will this review take place?

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Answer: Friday; friday; FRIDAY

Answer

Friday
The 1212-year period from 2195 to 2207 contains only 22 leap years (2196 and 2204). The year 2200 is a century year not divisible by 400400, meaning it is a common year with 365365 days. The total shift in days of the week is equal to the number of years (1212) plus the number of extra leap days (22), resulting in a total shift of 1414 days. Since 1414 is a perfect multiple of 77, there are 00 odd days. The day of the week shifts by exactly 00 days, meaning the review will also take place on a Friday.

Step-by-Step Solution

1
Identify the total number of years in the given interval.
From 2195 to 2207 is exactly 1212 years.
This sets the baseline shift, as every standard year shifts the calendar by at least 11 day.
2
Determine the number of leap years in this 12-year interval.
The years divisible by 44 in this range are 2196, 2200, and 2204. However, century years are only leap years if divisible by 400400. Since 2200 is not divisible by 400400, it is not a leap year. Thus, there are only 22 leap years: 2196 and 2204.
Each leap year adds an additional 11 day to the shift because it has 366366 days instead of 365365.
3
Calculate the total number of odd days (total shift in days of the week).
Each normal year contributes 11 odd day, and each leap year contributes 22 odd days. For 1212 years with 22 leap years, the easiest calculation is: 1212 (one for each year) +2+ 2 (extra day for each leap year) =14= 14 days.
This gives the absolute number of days the weekday will advance.
4
Determine the final day of the week.
A shift of 1414 days is exactly 22 full weeks (1414 divided by 77 leaves a remainder of 00). Therefore, the day of the week remains the same. Friday +0+ 0 days == Friday.
Days of the week repeat every 77 days, so we use modulo 77 arithmetic.

Key Concept

Calculating day of the week shifts across century boundaries, accounting for the rule that non-400 century years are not leap years.
Question 29Question

If the letter-group SOUL transforms into the code VLFO according to a specific alphanumeric rule, which of the following letter-groups represents the word DIRT under the identical rule?

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Answer: GRUW

Answer

GRUW
The underlying logical rule distinguishes between consonants and vowels. Consonants are shifted forward by 3 positions in the English alphabet (e.g., S becomes V, L becomes O). Vowels are replaced by their opposite/mirror letter from the reverse alphabetical order (e.g., O becomes L, U becomes F). Applying this rule to DIRT: The consonants D, R, and T shift forward by 3 to become G, U, and W. The vowel I is replaced by its reverse alphabetical counterpart, R. Therefore, the resulting letter-group is GRUW.

Step-by-Step Solution

1
Analyze the transformation from the reference word SOUL to its corresponding code VLFO to deduce the underlying rule.
By examining the alphabetical positions, consonants (S, L) shift forward by 3 positions to become (V, O). Vowels (O, U) are replaced by their opposite/mirror letters from the reverse alphabet (L, F).
Establishing the precise logical coding pattern is necessary to solve the analogy.
2
Categorize the letters in the target word DIRT into consonants and vowels.
Consonants: D, R, T. Vowel: I.
The established rule relies on treating consonants and vowels differently.
3
Apply the respective rules to the categorized letters of DIRT.
D (+3) yields G. I (reverse mirror) yields R. R (+3) yields U. T (+3) yields W. Combining these results in the string GRUW.
Applying the exact established rule provides the final encoded letter-cluster.

Key Concept

Letter Pattern Analogies and Positional Coding
Question 30Question

Consider the following pair of character sequences that share a specific structural relationship:

PLANT : MQBOI

Applying the exact same underlying logic, which sequence correctly completes the analogous pair below?

YIELD : ?

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Answer: DTXQY

Answer

The correct sequence is DTXQY.
The established relationship relies on a two-step transformation: first, finding the alphabetical opposite (mirror) of each letter, and second, shifting that new letter forward by 2 positions in the alphabet. Applying this logic to YIELD first gives its alphabetical mirror BRVOW. Shifting each letter in BRVOW forward by 2 positions produces DTXQY.

Step-by-Step Solution

1
Analyze the transformation from the first word (PLANT) to the second word (MQBOI) by examining the primary letter relationship.
The opposite (mirror) letters for P, L, A, N, T are K, O, Z, M, G respectively.
A common structural pattern in alphabet analogies is reverse indexing, where A=Z, B=Y, C=X, etc.
2
Determine the secondary transformation required to get from the intermediate mirror letters to the final code.
Shifting K, O, Z, M, G forward by 2 positions (+2) results in M, Q, B, O, I.
This establishes the complete two-step rule: find the alphabetical opposite, then shift forward by 2.
3
Apply the first step of the established rule to the target word (YIELD).
The opposite letters for Y, I, E, L, D are B, R, V, O, W.
Consistency in applying the exact same logical framework to the analogous pair.
4
Apply the second step of the rule to the intermediate result.
Shifting B, R, V, O, W forward by 2 positions yields D, T, X, Q, Y.
Completing the logic gives the final analogous character group.

Key Concept

Dual-Step Alphabet Analogy (Reverse Indexing and Positional Shifting)
Question 31Question

In a regional sports academy, a group of 7070 trainees were surveyed about their participation in two sports: Cricket and Football. 4545 trainees play Cricket, 3030 trainees play Football, and 1010 trainees play neither sport. How many trainees play both Cricket and Football?

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Answer: 1515

Answer

15 trainees play both Cricket and Football.
The total number of trainees participating in at least one sport is found by subtracting the 1010 non-participants from the total 7070, giving 6060. Summing the individual sport counts gives 45+30=7545 + 30 = 75. The overlap represents those counted twice, which is 7560=1575 - 60 = 15.

Step-by-Step Solution

1
Calculate the total number of trainees who play at least one sport.
Trainees playing at least one sport = 7010=6070 - 10 = 60.
Subtract trainees playing neither sport from the total group size.
2
Apply the Principle of Inclusion-Exclusion for two sets.
N(CricketFootball)=N(Cricket)+N(Football)N(CricketFootball)N(\text{Cricket} \cup \text{Football}) = N(\text{Cricket}) + N(\text{Football}) - N(\text{Cricket} \cap \text{Football}).
The sum of individual sets double-counts the intersection.
3
Substitute the known values into the equation and solve for the intersection.
60=45+30N(CricketFootball)    N(CricketFootball)=7560=1560 = 45 + 30 - N(\text{Cricket} \cap \text{Football}) \implies N(\text{Cricket} \cap \text{Football}) = 75 - 60 = 15.
Algebraic simplification yields the number of trainees playing both sports.

Key Concept

Two-Set Inclusion-Exclusion Principle
Question 32Question

In a state policy research institute, a survey of 200200 research analysts was conducted regarding their domain specializations in three sectors: Health (HH), Education (EE), and Agriculture (AA). The data revealed that 9090 analysts specialize in Health, 8585 in Education, and 8080 in Agriculture. Furthermore, 3535 analysts specialize in both Health and Education, 3030 in both Education and Agriculture, 2525 in both Health and Agriculture, and 1010 analysts specialize in all three sectors. How many research analysts specialize in corporate policy research analysts who specialize in exactly two of these sectors?

Show answer & explanation

Answer: 6060

Answer

The number of research analysts who specialize in exactly two sectors is 6060.
To find the number of analysts specializing in exactly two sectors, we must determine the exclusive intersection of each pair of sectors. The given intersections represent analysts in at least two sectors.
- Analysts specializing in ONLY Health and Education = 3510=2535 - 10 = 25
- Analysts specializing in ONLY Education and Agriculture = 3010=2030 - 10 = 20
- Analysts specializing in ONLY Health and Agriculture = 2510=1525 - 10 = 15

Summing these exclusive regions gives 25+20+15=6025 + 20 + 15 = 60.

Step-by-Step Solution

1
Identify given set values and intersections
n(HE)=35n(H \cap E) = 35, n(EA)=30n(E \cap A) = 30, n(HA)=25n(H \cap A) = 25, and n(HEA)=10n(H \cap E \cap A) = 10.
Each pairwise intersection given includes both analysts specializing in exactly two sectors and analysts specializing in all three sectors.
2
Calculate the number of analysts specializing ONLY in each specific pair of two sectors
Only Health & Education = 3510=2535 - 10 = 25; Only Education & Agriculture = 3010=2030 - 10 = 20; Only Health & Agriculture = 2510=1525 - 10 = 15.
Subtracting n(HEA)n(H \cap E \cap A) isolates the analysts specializing in exactly two sectors for each pair.
3
Sum the three isolated regions of exactly two specializations
Total = 25+20+15=6025 + 20 + 15 = 60.
Adding these three mutually exclusive regions yields the overall count of analysts specializing in exactly two sectors.

Key Concept

Logical Venn Diagrams - Intersection Exclusion Principle

Alternative Method

Using the general formula: Exactly two sets=n(HE)+n(EA)+n(HA)3×n(HEA)=35+30+253(10)=9030=60\text{Exactly two sets} = n(H \cap E) + n(E \cap A) + n(H \cap A) - 3 \times n(H \cap E \cap A) = 35 + 30 + 25 - 3(10) = 90 - 30 = 60.
Estimated Time:1m 30s
Question 33Question

In a consolidated merit list of 90 applicants for a university fellowship, Marcus is ranked 25th25^{\text{th}} from the top, while Elena is ranked 44th44^{\text{th}} from the bottom. If David is positioned exactly in the middle of Marcus and Elena in this merit list, what is David's rank from the bottom?

Show answer & explanation

Answer: 55th55^{\text{th}}

Answer

David's rank from the bottom is the 55th55^{\text{th}} position.
To find David's position, we first standardise the reference points. Elena's 44th44^{\text{th}} position from the bottom corresponds to the 47th47^{\text{th}} position from the top (calculated as 9044+190 - 44 + 1). The exact midpoint between the 25th25^{\text{th}} and 47th47^{\text{th}} ranks is the 36th36^{\text{th}} rank from the top (calculated as the average: (25+47)/2=36(25 + 47) / 2 = 36). Finally, converting David's 36th36^{\text{th}} top rank to a bottom rank yields 9036+1=55th90 - 36 + 1 = 55^{\text{th}}.

Step-by-Step Solution

1
Convert Elena's bottom rank to a top rank to establish a common directional reference.
Elena's rank from the top is 9044+1=47th90 - 44 + 1 = 47^{\text{th}}.
To calculate the number of people strictly between Marcus and Elena, both ranks must be measured from the same end (the top).
2
Calculate the number of applicants positioned strictly between Marcus and Elena.
There are 47251=2147 - 25 - 1 = 21 applicants between them.
Subtracting the top ranks and deducting 1 excludes both Marcus and Elena from the middle count.
3
Determine David's exact relative position starting from Marcus.
David is the 11th11^{\text{th}} person after Marcus.
The exact midpoint of 21 people is (21+1)/2=11(21 + 1) / 2 = 11 positions away from the starting person.
4
Calculate David's overall absolute rank from the top.
David's top rank is 25+11=36th25 + 11 = 36^{\text{th}}.
Adding David's relative interval to Marcus's top rank yields David's absolute top rank.
5
Convert David's top rank back to a bottom rank to answer the final question.
David's rank from the bottom is 9036+1=55th90 - 36 + 1 = 55^{\text{th}}.
Applying the standard linear ranking formula: Total=Top Rank+Bottom Rank1\text{Total} = \text{Top Rank} + \text{Bottom Rank} - 1.

Key Concept

Positional overlap calculation and dual-rank directional conversion
Question 34Question

A historian finds a perfectly preserved wall calendar for the year 1892. In which of the following subsequent years could this exact same calendar be used for the entire year without any discrepancies?

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Answer: 1904

Answer

The exact same calendar as 1892 can be reused in the year 1904.
For a calendar to completely match a leap year like 1892, the target year must start on the same day of the week and also be a leap year. While leap years typically repeat every 28 years, the inclusion of the non-leap century year 1900 disrupts this cycle. Counting the odd days from 1892 forward yields exactly 14 odd days by the end of 1903. This means 1904 starts on the same weekday, and because 1904 is a leap year itself, it shares the exact same calendar.

Step-by-Step Solution

1
Determine the properties required for the calendar to match.
The target year must begin on the same day of the week and must also be a leap year, just like 1892.
A leap year has 366 days. If the target year is not a leap year, the days will not match after February 28th.
2
Calculate the cumulative odd days year by year starting from 1892.
1892 (2 odd days), 1893 (1), 1894 (1), 1895 (1), 1896 (2), 1897 (1), 1898 (1), 1899 (1). The sum so far is 10 odd days.
Every standard year adds 1 odd day, while a leap year adds 2 odd days. We must find a point where the sum is a multiple of 7.
3
Evaluate the century year 1900 and continue the odd days calculation.
1900 is a standard year (1 odd day). Continuing: 1900 (1), 1901 (1), 1902 (1), 1903 (1). The total sum of odd days from 1892 to 1903 is exactly 14.
Century years are only leap years if divisible by 400. Since 1900 is not divisible by 400, it is a standard year, which breaks the usual 28-year repetition cycle.
4
Verify the candidate year 1904.
Because the odd days up to 1903 sum to 14 (a multiple of 7), 1904 starts on the same day. Since 1904 is divisible by 4 and not a century year, it is a leap year.
Satisfying both requirements (same starting day and leap year status) means the entire calendar for 1904 is identical to 1892.

Key Concept

Calendar Repetition Across Non-Leap Century Years
Question 35Question

Based on the specific letter transformation rule demonstrated in the first pair, which letter cluster correctly completes the second pair?

PLUM : NJXK :: BEAR : ?

Show answer & explanation

Answer: ZHDP

Answer

The correct letter cluster is ZHDP.
The underlying logic applies different shift rules based on whether a letter is a consonant or a vowel. In the first word, the consonants (P, L, M) are shifted backward by 2 positions in the English alphabet, while the vowel (U) is shifted forward by 3 positions. Applying this exact rule to the target word, the consonants (B, R) shift backward by 2 (resulting in Z, P) and the vowels (E, A) shift forward by 3 (resulting in H, D). This produces the final cluster 'ZHDP'.

Step-by-Step Solution

1
Analyze the transformation from 'PLUM' to 'NJXK' by checking the positional shifts in the alphabet.
P(16) → N(14) is -2; L(12) → J(10) is -2; U(21) → X(24) is +3; M(13) → K(11) is -2.
Establishing the individual letter shifts is necessary to identify the governing logical pattern.
2
Determine the rule that explains the different shifts (-2, -2, +3, -2).
The letters P, L, and M are consonants and they shift backward by 2. The letter U is a vowel and shifts forward by 3. The rule is: Consonants -2, Vowels +3.
Since the shift is not uniform or simply alternating, categorizing letters into vowels and consonants reveals the true logic.
3
Apply the identified rule to the target word 'BEAR'.
B (Consonant) - 2 = Z; E (Vowel) + 3 = H; A (Vowel) + 3 = D; R (Consonant) - 2 = P.
Applying the exact same vowel/consonant transformation rule yields the correct analogous pair.
4
Combine the transformed letters to form the final cluster.
Z, H, D, P combined form the cluster ZHDP.
This completes the analogy PLUM : NJXK :: BEAR : ZHDP.

Key Concept

Alphabet Pattern Analogy (Consonant and Vowel rules)
Question 36Question

A commemorative time capsule was sealed by a city council on Tuesday, August 15, 1876. The municipal charter mandates that it must be opened exactly 50 years later, on August 15, 1926. Based on the standard Gregorian calendar, on what day of the week will the capsule be opened?

Show answer & explanation

Answer: Sunday

Answer

The capsule will be opened on Sunday.
The correct answer accurately calculates the shift by accounting for 50 base years and exactly 11 leap days. It properly excludes 1900 as a leap year (due to the century rule) and correctly skips the 1876 leap day because the interval starts in August. Adding the resulting 61 odd days to Tuesday (61 mod 7 = 5) shifts the day forward by 5 days to Sunday.

Step-by-Step Solution

1
Determine the total number of base years in the interval.
1926 - 1876 = 50 years.
Each normal year adds exactly 1 odd day to the calendar shift.
2
Count the number of leap days crossed between August 15, 1876, and August 15, 1926.
There are 11 leap days (1880, 1884, 1888, 1892, 1896, 1904, 1908, 1912, 1916, 1920, 1924).
We must add 1 extra odd day for every February 29th crossed. The year 1876 is skipped because the start date is in August. The year 1900 is skipped because century years not divisible by 400 are not leap years.
3
Calculate the total number of odd days.
50 (from base years) + 11 (from leap days) = 61 total odd days.
Combining the normal yearly shift with the extra leap day shifts provides the total day shift.
4
Find the remainder when dividing the total odd days by 7 and apply it to the starting day.
61 divided by 7 leaves a remainder of 5. Tuesday + 5 days = Sunday.
The days of the week repeat in cycles of 7. Adding the remainder to the starting day gives the final day of the week.

Key Concept

Calculating odd days across century boundaries using the Gregorian calendar leap year rules.
Question 37Question

A network administrator is establishing a 5-step automated security protocol. The five steps—Backup Creation, Database Sync, Malware Scan, System Initialization, and User Authentication—must be arranged in a specific sequence based on the following constraints:

1. The Database Sync must occur exactly two steps after User Authentication.
2. The Malware Scan must occur sometime after System Initialization, but before Backup Creation.
3. The Database Sync cannot be the final step, and User Authentication cannot be the first step.

Arrange the five security steps in the correct chronological order from first to last.

Drag items to arrange them in the correct order

Show answer & explanation

Answer

The correct sequence is: System Initialization, User Authentication, Malware Scan, Database Sync, and Backup Creation.
The rules restrict the User Authentication and Database Sync pair strictly to steps 2 and 4. The remaining three steps (System Initialization, Malware Scan, Backup Creation) must maintain a strict relative order to satisfy the second rule, naturally falling into the remaining slots 1, 3, and 5.

Step-by-Step Solution

1
Determine the fixed positions for User Authentication and Database Sync based on constraints 1 and 3.
User Authentication must be step 2 and Database Sync must be step 4.
They have a fixed gap of one step between them. They cannot be steps 1 and 3 (User Authentication cannot be first), nor steps 3 and 5 (Database Sync cannot be last). Therefore, they must occupy steps 2 and 4.
2
Assign the remaining three steps (System Initialization, Malware Scan, and Backup Creation) to the empty slots.
System Initialization is step 1, Malware Scan is step 3, and Backup Creation is step 5.
Constraint 2 requires them to be in the strict relative order: System Initialization -> Malware Scan -> Backup Creation. The only remaining empty slots are 1, 3, and 5, so they must sequentially fill these slots.

Key Concept

Relative Positional Arrangement and Constraint Satisfaction
Estimated Time:1m 30s
Question 38Question

Determine the correct chronological progression of the following entities, from their foundational biological origin to the finalized consumer product:

Drag items to arrange them in the correct order

Show answer & explanation

Answer

The correct logical and chronological sequence is: Cotton Seed, Plant, Yarn, Fabric, Garment.
The sequence accurately traces the continuous lifecycle of textile production, moving logically from agriculture to manufacturing. It begins with the biological origin (Cotton Seed), which grows into a living organism (Plant). The plant produces raw cotton fibers that are extracted and spun into threads (Yarn). These threads are then woven together on a loom to create sheets of cloth (Fabric). Finally, the cloth is cut and tailored to create a finished piece of clothing (Garment).

Step-by-Step Solution

1
Identify the absolute origin point of the lifecycle.
Cotton Seed is the starting point.
Before any agricultural growth or industrial manufacturing can begin, the seed must be planted.
2
Determine the natural biological outcome of the seed.
The seed grows into a Plant.
Biological maturation must occur to produce the raw agricultural resource (cotton bolls).
3
Identify the first industrial transformation step.
The harvested cotton is spun into Yarn.
Raw cotton fibers cannot be woven directly; they must first be processed and spun into continuous threads.
4
Determine the next manufacturing stage.
The Yarn is woven into Fabric.
Individual threads are interlaced on a loom to create a solid, continuous sheet of textile material.
5
Identify the final consumer end-product.
The Fabric is sewn into a Garment.
The woven material is finally measured, cut, and stitched to create wearable clothing.

Key Concept

Logical Sequencing and Process Classification
Question 39Question

A global climate summit was inaugurated on Tuesday, March 15, 2016. Based on the standard Gregorian calendar, on what day of the week will the same date fall in the year 2027?

Show answer & explanation

Answer: Monday; monday; MONDAY

Answer

Monday
To find the day of the week, we track the odd days. Between 2016 and 2027, there are 11 years, providing a baseline of 11 odd days. The interval strictly crosses two leap days (in 2020 and 2024), adding 2 more odd days. Crucially, the 2016 leap day is not counted because the interval starts in March, after February 29th. The total is 13 odd days13 \text{ odd days}, and since 13(mod7)=613 \pmod{7} = 6, shifting 6 days forward from Tuesday gives Monday.

Step-by-Step Solution

1
Calculate the total number of years between the two dates.
20272016=11 years2027 - 2016 = 11 \text{ years}
Each standard year shifts the calendar forward by 1 odd day1 \text{ odd day} because 365(mod7)=1365 \pmod{7} = 1.
2
Identify the leap days (February 29th) that actually fall within this specific date range.
Only 22 leap days are crossed: February 29, 2020, and February 29, 2024.
Although 2016 is a leap year, its February 29th occurred before the start date of March 15, 2016, so it does not add an extra day to this interval.
3
Calculate the total number of odd days accumulated over the interval.
11 base days+2 leap days=13 total odd days11 \text{ base days} + 2 \text{ leap days} = 13 \text{ total odd days}
Combining the normal year shifts and the extra days from leap years gives the total day shift.
4
Determine the final day of the week by taking the total odd days modulo 7.
13(mod7)=6 odd days13 \pmod{7} = 6 \text{ odd days}. Tuesday +6 days=Monday+ 6 \text{ days} = \text{Monday}.
The days of the week operate on a 7-day repeating cycle.

Key Concept

The inclusion of a leap year's extra day in a calculation strictly depends on whether February 29th falls within the exact given date interval, not just whether the year itself is a leap year.

Alternative Method

Instead of grouping odd days at the end, you can calculate the day year-by-year: 2016 to 2017 (+1, Wednesday), 2017 to 2018 (+1, Thursday), 2018 to 2019 (+1, Friday), 2019 to 2020 (+2 due to Feb 2020, Sunday), and so on, arriving at Monday for 2027.
Estimated Time:1m 0s
Question 40Question

In a single row of books on a library shelf, an Encyclopedia is 28th28^{\text{th}} from the left end and a Dictionary is 35th35^{\text{th}} from the right end. If there are exactly 12 books placed strictly between them, what is the minimum possible total number of books in this row?

Show answer & explanation

Answer: 49

Answer

The minimum possible total number of books is 49.
The minimum total is found using the overlapping queue formula: L+RM2L + R - M - 2. Substituting the given values yields 28+35122=4928 + 35 - 12 - 2 = 49.

Step-by-Step Solution

1
Identify the queue configuration for the minimum capacity.
The minimum possible number of books occurs in an overlapping scenario.
In an overlapping scenario, the item counted from the right (Dictionary) is placed to the left of the item counted from the left (Encyclopedia), yielding the smallest overall total length.
2
Apply the minimum capacity formula.
Total=L+RM2\text{Total} = L + R - M - 2
We add the rank from the left (LL) and the rank from the right (RR), then subtract the number of items strictly between them (MM) and the 2 reference items to correct for double-counting.
3
Substitute the given values and calculate the final count.
Total=28+35122=49\text{Total} = 28 + 35 - 12 - 2 = 49
This yields the exact minimum count of books on the shelf.

Key Concept

Overlapping Minimum Capacity in Ordering and Ranking
Estimated Time:1m 0s
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