Question

Difficulty: MediumNephrology

A 38-year-old mechanic presents to the urgent care clinic complaining of severe flank pain, nausea, and blurry vision that started earlier this morning. He admits to accidentally ingesting a few mouthfuls of a liquid from an unmarked container in his garage while working late last night. His temperature is 36.8°C (98.2°F), blood pressure is 142/88 mm Hg, pulse is 98/min, and respiratory rate is 22/min. Cardiopulmonary examination is unremarkable. Initial laboratory tests reveal the following:

* Serum sodium: 138 mEq/L138 \text{ mEq/L}
* Serum potassium: 4.5 mEq/L4.5 \text{ mEq/L}
* Serum chloride: 104 mEq/L104 \text{ mEq/L}
* Serum bicarbonate: 14 mEq/L14 \text{ mEq/L}
* Blood urea nitrogen (BUN): 28 mg/dL28 \text{ mg/dL}
* Serum glucose: 126 mg/dL126 \text{ mg/dL}
* Measured serum osmolality: 315 mOsm/kg H2O315 \text{ mOsm/kg H}_2\text{O}

Based on these findings, what is the patient's calculated serum osmolar gap?

Answer: 22 mOsm/kg H2O

Answer

22
The calculated serum osmolality is derived using the formula 2×[Na+]+[Glucose]18+[BUN]2.82 \times [\text{Na}^+] + \frac{[\text{Glucose}]}{18} + \frac{[\text{BUN}]}{2.8}. Substituting the patient's values yields 2×138+12618+282.8=276+7+10=293 mOsm/kg H2O2 \times 138 + \frac{126}{18} + \frac{28}{2.8} = 276 + 7 + 10 = 293 \text{ mOsm/kg H}_2\text{O}. The osmolar gap is the measured osmolality minus the calculated osmolality (315−293=22 mOsm/kg H2O315 - 293 = 22 \text{ mOsm/kg H}_2\text{O}). A normal osmolar gap is typically less than 10-12; an elevated gap in this clinical context strongly supports the diagnosis of toxic alcohol ingestion (e.g., methanol or ethylene glycol).

Step-by-Step Solution

1
Determine the formula for calculated serum osmolality.
Calculated Osmolality = 2 × [Na+] + [Glucose]/18 + [BUN]/2.8
This standard formula accounts for the major osmotically active solutes in the extracellular fluid in the United States unit system (mg/dL).
2
Insert the patient's laboratory values into the formula.
Calculated Osmolality = (2 × 138) + (126 / 18) + (28 / 2.8)
To compute the expected osmolality based on native physiological solutes.
3
Perform the arithmetic for each component.
276 + 7 + 10 = 293 mOsm/kg H2O
Resolving the equation yields the total calculated osmolality.
4
Calculate the osmolar gap.
Measured Osmolality (315) - Calculated Osmolality (293) = 22 mOsm/kg H2O
The osmolar gap represents the presence of unmeasured osmotically active substances, such as toxic alcohols (e.g., methanol, ethylene glycol).

Key Concept

Calculation and clinical application of the serum osmolar gap in evaluating suspected toxic alcohol ingestion.
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