Question

Difficulty: Very hardNephrology

Following 22 days of fever, progressive confusion, and abdominal pain, a 5555-year-old man is brought to the emergency department. He has a known history of alcohol-associated cirrhosis and diuretic-refractory ascites, for which he takes furosemide and spironolactone. His temperature is 38.6∘C38.6^\circ\text{C} (101.5∘F101.5^\circ\text{F}), blood pressure is 88/5488/54 mm Hg, pulse is 112112/min, and respirations are 2424/min. Physical examination reveals scleral icterus, a distended abdomen with shifting dullness, and diffuse abdominal tenderness to palpation. Asterixis is present.

Laboratory studies show:
Sodium: 140140 mEq/L
Potassium: 2.92.9 mEq/L
Chloride: 105105 mEq/L
Bicarbonate: 2020 mEq/L
Blood urea nitrogen: 4242 mg/dL
Creatinine: 1.91.9 mg/dL
Albumin: 1.01.0 g/dL
Lactate: 5.25.2 mmol/L

Arterial blood gas on room air:
pH: 7.517.51
PaCO 2_2: 2626 mm Hg
PaO 2_2: 8585 mm Hg

Which of the following best characterizes this patient's primary acid-base disturbances?

  1. A
    Normal anion gap metabolic acidosis and respiratory alkalosis
  2. B
    High anion gap metabolic acidosis and respiratory alkalosis
  3. High anion gap metabolic acidosis, metabolic alkalosis, and respiratory alkalosisAnswer
  4. D
    Normal anion gap metabolic acidosis, metabolic alkalosis, and respiratory alkalosis
  5. E
    High anion gap metabolic acidosis, metabolic alkalosis, and respiratory acidosis

Answer

The correct answer is high anion gap metabolic acidosis, metabolic alkalosis, and respiratory alkalosis.
The correct answer is high anion gap metabolic acidosis, metabolic alkalosis, and respiratory alkalosis. This patient's calculated anion gap is 15 mEq/L, which might appear normal or borderline depending on the laboratory reference range. However, adjusting for his severe hypoalbuminemia (1.0 g/dL) yields a corrected anion gap of 22.5 mEq/L, confirming a high anion gap metabolic acidosis (lactic acidosis due to sepsis from spontaneous bacterial peritonitis). Calculating the delta gap reveals an excess anion gap of 10.5 mEq/L. Subtracting this from a normal bicarbonate of 24 mEq/L gives an expected bicarbonate of 13.5 mEq/L. Since his actual bicarbonate (20 mEq/L) is higher than expected, a concurrent metabolic alkalosis is present (diuretic-induced contraction alkalosis). Finally, Winter's formula predicts an expected PaCO2 of 38 mm Hg. The actual PaCO2 is 26 mm Hg, indicating a concurrent primary respiratory alkalosis.

Step-by-Step Solution

1
Calculate the uncorrected anion gap (AG) using the formula Na+−(Cl−+HCO3−)\text{Na}^+ - (\text{Cl}^- + \text{HCO}_3^-).
140−(105+20)=15140 - (105 + 20) = 15 mEq/L.
To screen for an unmeasured anion accumulation (normal range is approximately 8−128-12 mEq/L).
2
Correct the calculated anion gap for the patient's severe hypoalbuminemia.
Add 2.52.5 mEq/L to the AG for every 1.01.0 g/dL the albumin is below 4.04.0 g/dL. Corrected AG =15+[2.5×(4.0−1.0)]=15+7.5=22.5= 15 + [2.5 \times (4.0 - 1.0)] = 15 + 7.5 = 22.5 mEq/L.
Albumin is a major unmeasured anion; severe hypoalbuminemia falsely lowers the calculated AG, masking a primary high AG metabolic acidosis. The corrected AG of 22.522.5 mEq/L confirms a high anion gap metabolic acidosis (due to lactic acidosis from sepsis).
3
Calculate the delta-delta gap (ΔAG/ΔHCO3−\Delta\text{AG} / \Delta\text{HCO}_3^-) to check for a concurrent metabolic disorder.
Excess AG =22.5−12=10.5= 22.5 - 12 = 10.5 mEq/L. Expected HCO3−=24−10.5=13.5\text{HCO}_3^- = 24 - 10.5 = 13.5 mEq/L. The patient's actual HCO3−\text{HCO}_3^- is 2020 mEq/L.
Since the actual HCO3−\text{HCO}_3^- (2020 mEq/L) is significantly higher than the expected HCO3−\text{HCO}_3^- (13.513.5 mEq/L), there is a secondary process adding bicarbonate to the serum. This confirms a concurrent metabolic alkalosis (likely contraction alkalosis from diuretic use).
4
Assess the respiratory compensation using Winter's formula.
Expected PaCO 2_2 =(1.5×20)+8=38±2= (1.5 \times 20) + 8 = 38 \pm 2 mm Hg. The actual PaCO 2_2 is 2626 mm Hg.
Since the actual PaCO 2_2 (2626 mm Hg) is much lower than the expected PaCO 2_2 (36−4036-40 mm Hg), a primary respiratory alkalosis is also present (driven by hyperventilation from sepsis and hepatic encephalopathy).

Key Concept

Identifying a triple acid-base disorder requires stepwise calculation: correcting the anion gap for albumin, evaluating the delta gap, and applying Winter's formula.
Estimated Time:3m 0s
Rate this question