Question

Difficulty: MediumNephrology

Emergency medical services bring a 47-year-old mechanic to the hospital after he was found deeply lethargic in his workshop. His coworkers report that he had been working alone on a vehicle's cooling system and seemed disoriented before collapsing. On presentation, his temperature is 36.8∘C36.8^\circ C (98.2∘F98.2^\circ F), blood pressure is 105/65105/65 mmHg, pulse is 112112/min, and respiratory rate is 2424/min. Physical examination reveals an unarousable patient with deep, rapid breathing. Arterial blood gas analysis on room air shows a pH of 7.21, PaCO2PaCO_2 of 24 mmHg, and PaO2PaO_2 of 95 mmHg.

Laboratory evaluation reveals the following:
ParameterValue
Sodium142142 mEq/L
Potassium4.84.8 mEq/L
Chloride104104 mEq/L
Bicarbonate1010 mEq/L
Blood urea nitrogen1414 mg/dL
Creatinine1.61.6 mg/dL
Glucose9090 mg/dL
Measured serum osmolality334334 mOsm/kg H2OH_2O

Based on the provided laboratory results, what is the patient's calculated serum osmolar gap in mOsm/kg H2OH_2O?

Answer: 40 mOsm/kg H2O

Answer

40
The correct answer is 40. The serum osmolar gap is defined as the difference between the directly measured serum osmolality and the calculated serum osmolality. The formula for calculated serum osmolality in conventional units (mg/dL) is: Calculated Osmolality=2×[Na+]+[Glucose]18+[BUN]2.8Calculated\ Osmolality = 2 \times [Na^+] + \frac{[Glucose]}{18} + \frac{[BUN]}{2.8}. Using the patient's values, this is computed as 2(142)+9018+142.8=284+5+5=2942(142) + \frac{90}{18} + \frac{14}{2.8} = 284 + 5 + 5 = 294 mOsm/kg H2OH_2O. The measured osmolality is 334 mOsm/kg H2OH_2O. Subtracting the calculated value from the measured value yields an osmolar gap of 334−294=40334 - 294 = 40 mOsm/kg H2OH_2O. A normal osmolar gap is typically less than 10 to 15 mOsm/kg H2OH_2O. In a patient with central nervous system depression, high anion gap metabolic acidosis, and exposure to automotive fluids, a markedly elevated osmolar gap strongly suggests intoxication with an unmeasured osmotically active alcohol, such as ethylene glycol (antifreeze).

Step-by-Step Solution

1
Calculate the expected serum osmolality using the standard formula for conventional units.
294294 mOsm/kg H2OH_2O
This establishes the baseline osmolality contributed by the primary endogenous osmoles (sodium, glucose, and urea).
2
Subtract the calculated osmolality from the measured serum osmolality.
334−294=40334 - 294 = 40 mOsm/kg H2OH_2O
An elevated difference (gap >10 mOsm/kg) indicates the presence of unmeasured exogenous osmotically active substances, such as ethylene glycol.

Key Concept

Calculation and interpretation of the serum osmolar gap in toxic alcohol ingestion.
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