Question

Difficulty: MediumNephrology

A 68-year-old man is evaluated in the intensive care unit for decreased urine output. Three days ago, he was admitted with severe community-acquired pneumonia and septic shock, which required aggressive intravenous fluid resuscitation and continuous norepinephrine infusion. Over the past 24 hours, his urine output has decreased to 250 mL. His blood pressure is 105/65 mm Hg, pulse is 98/min, and respirations are 18/min. Physical examination reveals warm extremities and trace bilateral pitting edema. Laboratory studies are obtained:

ParameterValue
Serum sodium140 mEq/L
Serum potassium4.8 mEq/L
Serum chloride102 mEq/L
Serum bicarbonate20 mEq/L
Blood urea nitrogen42 mg/dL
Serum creatinine2.8 mg/dL
Urine sodium50 mEq/L
Urine creatinine25 mg/dL

Based on these findings, what is this patient's calculated fractional excretion of sodium (in percentage)?

Answer: 4 %

Answer

4
The fractional excretion of sodium (FeNa) is calculated using the formula FeNa=UNa×PCrPNa×UCr×100FeNa = \frac{U_{Na} \times P_{Cr}}{P_{Na} \times U_{Cr}} \times 100. By substituting the patient's laboratory values (UNaU_{Na} = 50 mEq/L, PCrP_{Cr} = 2.8 mg/dL, PNaP_{Na} = 140 mEq/L, UCrU_{Cr} = 25 mg/dL) into the equation, the result is 50×2.8140×25×100\frac{50 \times 2.8}{140 \times 25} \times 100, which equals 4%. A FeNa > 2% in the setting of oliguric acute kidney injury strongly suggests intrinsic damage, such as acute tubular necrosis, which aligns with this patient's history of prolonged septic shock and ischemic injury.

Step-by-Step Solution

1
Extract the necessary laboratory values from the clinical vignette.
UNa=50U_{Na} = 50 mEq/L, PCr=2.8P_{Cr} = 2.8 mg/dL, PNa=140P_{Na} = 140 mEq/L, and UCr=25U_{Cr} = 25 mg/dL.
These variables are required to calculate the fractional excretion of sodium (FeNa).
2
Apply the FeNa equation.
FeNa=UNa×PCrPNa×UCr×100FeNa = \frac{U_{Na} \times P_{Cr}}{P_{Na} \times U_{Cr}} \times 100
This formula normalizes sodium excretion to the glomerular filtration rate, helping differentiate prerenal azotemia from intrinsic acute kidney injury.
3
Perform the calculation with the extracted values.
50×2.8140×25×100=1403500×100=0.04×100=4%\frac{50 \times 2.8}{140 \times 25} \times 100 = \frac{140}{3500} \times 100 = 0.04 \times 100 = 4\%
To obtain the final FeNa percentage. A FeNa > 2% strongly indicates acute tubular necrosis (ATN).

Key Concept

Calculation and interpretation of the Fractional Excretion of Sodium (FeNa) in acute kidney injury.
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