Question

Difficulty: HardInterpreting Laboratory Results

A 75-year-old woman is evaluated in the hospital for acute kidney injury. She was admitted 55 days ago for community-acquired pneumonia and has been treated with intravenous vancomycin and piperacillin-tazobactam. Her blood pressure is 122/76122/76 mm Hg, and heart rate is 8282/min. She appears euvolemic on physical examination. Today, her serum creatinine is noted to be significantly elevated compared to her baseline of 0.90.9 mg/dL.

Laboratory studies today show:
Serum sodium: 140140 mEq/L
Blood urea nitrogen: 5656 mg/dL
Serum creatinine: 4.04.0 mg/dL
Urine sodium: 6363 mEq/L
Urine creatinine: 6060 mg/dL

Urinalysis reveals muddy brown granular casts.

Based on the provided laboratory data, what is the patient's fractional excretion of sodium (FENa) as a percentage?

Answer: 3 %

Answer

3.0
The correct calculation yields 3.0%. FENa is a diagnostic calculation used to differentiate causes of acute kidney injury. It is calculated using the formula FENa=UNa×SCrSNa×UCr×100FENa = \frac{UNa \times SCr}{SNa \times UCr} \times 100. For this patient, who likely has nephrotoxic acute tubular necrosis induced by vancomycin and piperacillin-tazobactam (supported by muddy brown casts), substituting the provided values results in 63×4.0140×60×100=3.0%\frac{63 \times 4.0}{140 \times 60} \times 100 = 3.0\%.

Step-by-Step Solution

1
Recall the diagnostic formula for calculating the fractional excretion of sodium (FENa).
FENa=UNa×SCrSNa×UCr×100FENa = \frac{UNa \times SCr}{SNa \times UCr} \times 100
This calculation is essential to differentiate the etiology of acute kidney injury, specifically distinguishing prerenal azotemia from intrinsic renal disease such as acute tubular necrosis.
2
Extract the necessary laboratory parameters from the clinical vignette.
Urine sodium (UNaUNa) = 6363 mEq/L, Serum creatinine (SCrSCr) = 4.04.0 mg/dL, Serum sodium (SNaSNa) = 140140 mEq/L, and Urine creatinine (UCrUCr) = 6060 mg/dL.
Accurate identification of values is required for the calculation; the blood urea nitrogen (BUN) is provided as a distractor and is not part of the FENa equation.
3
Substitute the values into the formula and perform the calculation.
FENa=63×4.0140×60×100=2528400×100=0.03×100=3.0%FENa = \frac{63 \times 4.0}{140 \times 60} \times 100 = \frac{252}{8400} \times 100 = 0.03 \times 100 = 3.0\%
Arithmetic completion determines the final index, which is consistent with the clinical picture of acute tubular necrosis (FENa > 2%).

Key Concept

The fractional excretion of sodium (FENa) measures the percentage of filtered sodium excreted in the urine. It is calculated as FENa=Urine Na×Serum CrSerum Na×Urine Cr×100FENa = \frac{\text{Urine Na} \times \text{Serum Cr}}{\text{Serum Na} \times \text{Urine Cr}} \times 100. A value > 2% typically indicates intrinsic renal injury, such as acute tubular necrosis.
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