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Zorluk: OrtaTranslating and Solving Algebraic Word Problems

A local library has two types of books: fiction and non-fiction. The number of fiction books is 120120 more than twice the number of non-fiction books. If the library has a total of 18601\text{}860 books, how many more fiction books than non-fiction books does the library have?

  1. A
    580580
  2. B
    780780
  3. 700700Cevap
  4. D
    870870
  5. E
    12801\text{}280

Cevap

The library has 700700 more fiction books than non-fiction books.
The correct answer is 700700 because defining the non-fiction books as nn gives 2n+1202n + 120 fiction books. Summing these to equal 18601860 yields 3n+120=18603n + 120 = 1860, which solves to n=580n = 580. The number of fiction books is therefore 2(580)+120=12802(580) + 120 = 1280. The difference between the two quantities is 1280580=7001280 - 580 = 700.

Adım Adım Çözüm

1
Define variables for the two categories of books.
Let nn be the number of non-fiction books. Then the number of fiction books, ff, can be written as f=2n+120f = 2n + 120.
This translates the statement 'the number of fiction books is 120120 more than twice the number of non-fiction books' into an algebraic expression.
2
Set up an equation representing the total number of books.
n+f=1860    n+(2n+120)=1860    3n+120=1860n + f = 1860 \implies n + (2n + 120) = 1860 \implies 3n + 120 = 1860.
The sum of the fiction and non-fiction books must equal the total library inventory of 18601860 books.
3
Solve the equation for the number of non-fiction books, nn.
3n=1740    n=5803n = 1740 \implies n = 580.
Subtracting 120120 from both sides and then dividing by 33 isolates the variable nn.
4
Calculate the number of fiction books and find the difference.
Fiction books: f=2(580)+120=1280f = 2(580) + 120 = 1280. Difference: fn=1280580=700f - n = 1280 - 580 = 700.
The question asks for the difference between the number of fiction and non-fiction books.

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Translating and Solving Algebraic Word Problems
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