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Zorluk: OrtaSimplifying Expressions and Combining Like Terms

Which of the following is equivalent to the expression 2a(3a−b)2−3b(2a2−ab)−a2(18a−15b)2a(3a - b)^2 - 3b(2a^2 - ab) - a^2(18a - 15b) for all real values of aa and bb?

  1. A
    9a2b+5ab29a^2b + 5ab^2
  2. B
    −33a2b+5ab2-33a^2b + 5ab^2
  3. C
    −3a2b−ab2-3a^2b - ab^2
  4. −3a2b+5ab2-3a^2b + 5ab^2Cevap
  5. E
    −3a2b+5ab-3a^2b + 5ab

Cevap

The simplified expression is −3a2b+5ab2-3a^2b + 5ab^2.
The correct expression is −3a2b+5ab2-3a^2b + 5ab^2. Expanding the three parts yields 18a3−12a2b+2ab218a^3 - 12a^2b + 2ab^2, −6a2b+3ab2-6a^2b + 3ab^2, and −18a3+15a2b-18a^3 + 15a^2b. Summing these parts together cancels out the cubic a3a^3 terms (18a3−18a3=018a^3 - 18a^3 = 0), combines the a2ba^2b terms (−12a2b−6a2b+15a2b=−3a2b-12a^2b - 6a^2b + 15a^2b = -3a^2b), and combines the ab2ab^2 terms (2ab2+3ab2=5ab22ab^2 + 3ab^2 = 5ab^2).

Adım Adım Çözüm

1
Expand the first term 2a(3a−b)22a(3a - b)^2
18a3−12a2b+2ab218a^3 - 12a^2b + 2ab^2
First expand the squared binomial (3a−b)2=9a2−6ab+b2(3a - b)^2 = 9a^2 - 6ab + b^2, then distribute the 2a2a to each term.
2
Expand the second term −3b(2a2−ab)-3b(2a^2 - ab)
−6a2b+3ab2-6a^2b + 3ab^2
Distribute −3b-3b to both terms inside the parentheses, ensuring that the negative sign is applied to both terms.
3
Expand the third term −a2(18a−15b)-a^2(18a - 15b)
−18a3+15a2b-18a^3 + 15a^2b
Distribute −a2-a^2 to both terms inside the parentheses, changing the sign of both terms.
4
Combine the expanded expressions and group like terms
(18a3−18a3)+(−12a2b−6a2b+15a2b)+(2ab2+3ab2)(18a^3 - 18a^3) + (-12a^2b - 6a^2b + 15a^2b) + (2ab^2 + 3ab^2)
Grouping terms with identical variable parts allows them to be added or subtracted.
5
Perform the final simplification
−3a2b+5ab2-3a^2b + 5ab^2
The a3a^3 terms cancel out, the a2ba^2b terms combine to −3a2b-3a^2b, and the ab2ab^2 terms combine to 5ab25ab^2.

Anahtar Kavram

Simplifying algebraic expressions by expanding parentheses, applying exponent rules, and combining like terms.
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