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Zorluk: KolayComplex Numbers and Operations

For the imaginary unit ii, what is the simplified form of the expression (2+3i)(12i)(2 + 3i)(1 - 2i)?

  1. A
    4i-4 - i
  2. B
    8+i8 + i
  3. 8i8 - iCevap
  4. D
    4+i-4 + i
  5. E
    87i8 - 7i

Cevap

8i8 - i
The correct answer is 8i8 - i. To simplify the product of (2+3i)(12i)(2 + 3i)(1 - 2i), we distribute the terms to get 2(1)+2(2i)+3i(1)+3i(2i)=24i+3i6i22(1) + 2(-2i) + 3i(1) + 3i(-2i) = 2 - 4i + 3i - 6i^2. Since i2=1i^2 = -1, the last term 6i2-6i^2 simplifies to 6(1)=6-6(-1) = 6. Combining the real parts (2+6=82 + 6 = 8) and the imaginary parts (4i+3i=i-4i + 3i = -i) yields 8i8 - i.

Adım Adım Çözüm

1
Expand the product of the two binomials (2+3i)(12i)(2 + 3i)(1 - 2i) using the distributive property.
24i+3i6i22 - 4i + 3i - 6i^2
Each term of the first binomial must be multiplied by each term of the second binomial.
2
Substitute 1-1 for i2i^2 in the expression.
24i+3i6(1)=24i+3i+62 - 4i + 3i - 6(-1) = 2 - 4i + 3i + 6
By definition, the imaginary unit ii satisfies the equation i2=1i^2 = -1.
3
Combine the real terms and combine the imaginary terms to obtain the final simplified form.
8i8 - i
Adding the real parts (2+6=82 + 6 = 8) and the imaginary parts (4i+3i=i-4i + 3i = -i) simplifies the expression to a single complex number.

Anahtar Kavram

Multiplying complex binomials and simplifying using the definition of the imaginary unit i2=1i^2 = -1.
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