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Zorluk: KolayComplex Numbers and Operations

For the imaginary unit ii, what is the simplified form of the expression (2+3i)(1−2i)(2 + 3i)(1 - 2i)?

  1. A
    −4−i-4 - i
  2. B
    8+i8 + i
  3. 8−i8 - iCevap
  4. D
    −4+i-4 + i
  5. E
    8−7i8 - 7i

Cevap

8−i8 - i
The correct answer is 8−i8 - i. To simplify the product of (2+3i)(1−2i)(2 + 3i)(1 - 2i), we distribute the terms to get 2(1)+2(−2i)+3i(1)+3i(−2i)=2−4i+3i−6i22(1) + 2(-2i) + 3i(1) + 3i(-2i) = 2 - 4i + 3i - 6i^2. Since i2=−1i^2 = -1, the last term −6i2-6i^2 simplifies to −6(−1)=6-6(-1) = 6. Combining the real parts (2+6=82 + 6 = 8) and the imaginary parts (−4i+3i=−i-4i + 3i = -i) yields 8−i8 - i.

Adım Adım Çözüm

1
Expand the product of the two binomials (2+3i)(1−2i)(2 + 3i)(1 - 2i) using the distributive property.
2−4i+3i−6i22 - 4i + 3i - 6i^2
Each term of the first binomial must be multiplied by each term of the second binomial.
2
Substitute −1-1 for i2i^2 in the expression.
2−4i+3i−6(−1)=2−4i+3i+62 - 4i + 3i - 6(-1) = 2 - 4i + 3i + 6
By definition, the imaginary unit ii satisfies the equation i2=−1i^2 = -1.
3
Combine the real terms and combine the imaginary terms to obtain the final simplified form.
8−i8 - i
Adding the real parts (2+6=82 + 6 = 8) and the imaginary parts (−4i+3i=−i-4i + 3i = -i) simplifies the expression to a single complex number.

Anahtar Kavram

Multiplying complex binomials and simplifying using the definition of the imaginary unit i2=−1i^2 = -1.
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