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Zorluk: KolayParallel and Perpendicular Lines

In the standard (x,y)(x, y) coordinate plane, line pp is perpendicular to the line represented by the equation y=−0.2x+9y = -0.2x + 9. What is the slope of line pp?

Cevap: 5

Cevap

The slope of line pp is 55.
The given line is in slope-intercept form y=mx+by = mx + b with a slope of −0.2-0.2, which can be written as −15-\frac{1}{5}. The slope of any line perpendicular to this line is the negative reciprocal of −15-\frac{1}{5}, which is 55.

Adım Adım Çözüm

1
Identify the slope of the given line from its equation.
The slope of the line y=−0.2x+9y = -0.2x + 9 is −0.2-0.2 (or −15-\frac{1}{5}).
The equation is in slope-intercept form y=mx+by = mx + b, where the coefficient of xx represents the slope mm.
2
Calculate the slope of the perpendicular line.
The negative reciprocal of −15-\frac{1}{5} is 55.
Perpendicular lines have slopes that are negative reciprocals of each other (m1⋅m2=−1m_1 \cdot m_2 = -1).

Anahtar Kavram

Perpendicular lines in the coordinate plane have slopes that are negative reciprocals of each other.
Tahmini Süre:45s
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Konular

Parallel and Perpendicular Lines

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