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Zorluk: OrtaTriangle Properties and Angle Theorems

In ABC\triangle ABC, the measure of exterior angle ACD\angle ACD is 135135^\circ, where DD lies on the extension of side BCBC past CC. If the measure of interior angle A\angle A is 2525^\circ greater than the measure of interior angle B\angle B, what is the measure, in degrees, of B\angle B?

Cevap: 55 degrees

Cevap

55
According to the Exterior Angle Theorem, the measure of exterior angle ACD\angle ACD is equal to the sum of the measures of its remote interior angles, A\angle A and B\angle B. This gives the equation mA+mB=135\text{m}\angle A + \text{m}\angle B = 135^\circ. Using the information that mA=mB+25\text{m}\angle A = \text{m}\angle B + 25^\circ, we substitute this expression into the equation to get (mB+25)+mB=135(\text{m}\angle B + 25^\circ) + \text{m}\angle B = 135^\circ. Simplifying this equation gives 2mB+25=1352\text{m}\angle B + 25 = 135, which simplifies to 2mB=1102\text{m}\angle B = 110, and dividing by 2 yields mB=55\text{m}\angle B = 55^\circ.

Adım Adım Çözüm

1
Apply the Exterior Angle Theorem to express the relation between the exterior angle and the two remote interior angles.
mA+mB=135\text{m}\angle A + \text{m}\angle B = 135^\circ
The measure of an exterior angle of a triangle is equal to the sum of the measures of its two remote interior angles.
2
Substitute the relationship between the interior angles into the equation.
(mB+25)+mB=135(\text{m}\angle B + 25^\circ) + \text{m}\angle B = 135^\circ
The problem states that the measure of interior angle A\angle A is 2525^\circ greater than the measure of interior angle B\angle B.
3
Solve the algebraic equation for the measure of interior angle B\angle B.
mB=55\text{m}\angle B = 55^\circ
Combining like terms gives 2mB+25=1352\text{m}\angle B + 25 = 135. Subtracting 25 from both sides gives 2mB=1102\text{m}\angle B = 110. Dividing by 2 yields mB=55\text{m}\angle B = 55^\circ.

Anahtar Kavram

Exterior Angle Theorem and remote interior angles relation
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