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Zorluk: OrtaDescriptive Statistics and Data Representations

A weather researcher recorded the daily high temperatures, in degrees Fahrenheit, for 55 consecutive days in a mountain town: 68F68^\circ\text{F}, 74F74^\circ\text{F}, 71F71^\circ\text{F}, 65F65^\circ\text{F}, and 72F72^\circ\text{F}. If the daily high temperature on the 6th day is xFx^\circ\text{F}, and the mean high temperature for all 66 days is 72F72^\circ\text{F}, what is the value of xx?

  1. A
    1010
  2. B
    7272
  3. C
    7474
  4. 8282Cevap
  5. E
    8888

Cevap

8282
To achieve a target mean of 72F72^\circ\text{F} over 66 days, the total sum of all 66 daily high temperatures must be 6×72=432F6 \times 72 = 432^\circ\text{F}. Adding the 55 recorded temperatures gives 68+74+71+65+72=350F68 + 74 + 71 + 65 + 72 = 350^\circ\text{F}. Subtracting 350350 from 432432 yields 82F82^\circ\text{F}, which is the temperature needed on the 6th day.

Adım Adım Çözüm

1
Calculate the total sum of the temperatures for the first 55 days.
68+74+71+65+72=35068 + 74 + 71 + 65 + 72 = 350
To find the missing value, we first need the combined total of the known data points.
2
Determine the required total sum for all 66 days using the target mean.
Total Sum=6×72=432\text{Total Sum} = 6 \times 72 = 432
The mean of 66 values is equal to the sum of all 66 values divided by 66.
3
Subtract the 55-day sum from the total 66-day sum to solve for xx.
x=432350=82x = 432 - 350 = 82
The difference between the required total sum and the existing sum gives the value of the 6th data point.

Anahtar Kavram

Finding a missing data value using a target arithmetic mean
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