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Zorluk: ZorDistance and Midpoint Formulas

In the standard (x,y)(x, y) coordinate plane, the point MM is the midpoint of the line segment with endpoints P(4,2)P(-4, -2) and Q(4,2)Q(4, 2). A second line segment is drawn from MM to a point R(x,y)R(x, y) such that the length of the segment MRMR is 88. If the midpoint of the segment MRMR lies on the line 3x4y+12=03x - 4y + 12 = 0, what is the smallest possible value of xx?

Cevap: -8

Cevap

The smallest possible value of xx is 8-8.
By finding the midpoint M(0,0)M(0,0) of PQPQ and writing the midpoint of MRMR as (x2,y2)\left(\frac{x}{2}, \frac{y}{2}\right), we substitute this into the line equation to find y=34x+6y = \frac{3}{4}x + 6. We then substitute this into the distance formula equation x2+y2=64x^2 + y^2 = 64 to get the quadratic equation 25x2+144x448=025x^2 + 144x - 448 = 0, which yields the solutions x=8x = -8 and x=2.24x = 2.24. The smallest possible value is 8-8.

Adım Adım Çözüm

1
Calculate the coordinates of the midpoint MM of segment PQPQ.
M=(0,0)M = (0, 0)
The midpoint formula states that the midpoint of a segment with endpoints (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is (x1+x22,y1+y22)\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right).
2
Express the midpoint NN of segment MRMR in terms of R(x,y)R(x, y).
N=(x2,y2)N = \left(\frac{x}{2}, \frac{y}{2}\right)
The midpoint of M(0,0)M(0, 0) and R(x,y)R(x, y) is found by averaging their coordinates.
3
Substitute the coordinates of NN into the equation of the line 3x4y+12=03x - 4y + 12 = 0.
y=34x+6y = \frac{3}{4}x + 6
Since the midpoint NN lies on the line, its coordinates must satisfy the line's equation, which gives a linear relationship between xx and yy.
4
Set up the equation for the distance MR=8MR = 8.
x2+y2=64x^2 + y^2 = 64
The distance formula between M(0,0)M(0, 0) and R(x,y)R(x, y) is d=x2+y2d = \sqrt{x^2 + y^2}, and squaring both sides gives x2+y2=d2x^2 + y^2 = d^2.
5
Substitute y=34x+6y = \frac{3}{4}x + 6 into the distance equation and solve the quadratic equation.
x=8x = -8 and x=2.24x = 2.24
Substituting the linear relationship into the quadratic circle equation gives a single quadratic equation in terms of xx, which can be solved using the quadratic formula.
6
Determine the smallest value of xx from the two possible solutions.
8-8
Comparing the two solutions, 8-8 is smaller than 2.242.24.

Anahtar Kavram

Distance and Midpoint Formulas

Alternatif Yöntem

Instead of solving algebraically, one can scale the line 3x4y+12=03x - 4y + 12 = 0 by a factor of 2 centered at the origin M(0,0)M(0,0) to directly obtain the line equation on which RR lies: 3x4y+24=03x - 4y + 24 = 0. Then, find the intersection of this line with the circle x2+y2=64x^2 + y^2 = 64 using substitution.
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