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Zorluk: OrtaDistance and Midpoint Formulas

In the standard (x,y)(x, y) coordinate plane, the midpoint of a line segment with endpoints A(r,2)A(r, -2) and B(10,s)B(10, s) is M(6,3)M(6, 3). What is the distance between the point AA and the origin (0,0)(0, 0)?

  1. 222\sqrt{2}Cevap
  2. B
    353\sqrt{5}
  3. C
    2172\sqrt{17}
  4. D
    44
  5. E
    2412\sqrt{41}

Cevap

The distance between the point AA and the origin is 222\sqrt{2}.
To find the coordinates of point A(r,2)A(r, -2), we set up the midpoint formula with the coordinates of B(10,s)B(10, s) and the midpoint M(6,3)M(6, 3). For the xx-coordinate, r+102=6    r+10=12    r=2\frac{r + 10}{2} = 6 \implies r + 10 = 12 \implies r = 2. For the yy-coordinate, 2+s2=3    2+s=6    s=8\frac{-2 + s}{2} = 3 \implies -2 + s = 6 \implies s = 8. Thus, point AA is (2,2)(2, -2). The distance from A(2,2)A(2, -2) to the origin (0,0)(0, 0) is (20)2+(20)2=4+4=8=22\sqrt{(2 - 0)^2 + (-2 - 0)^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2}.

Adım Adım Çözüm

1
Use the midpoint formula to set up equations for the coordinates of the midpoint M(6,3)M(6, 3) given the endpoints A(r,2)A(r, -2) and B(10,s)B(10, s).
The equations are r+102=6\frac{r + 10}{2} = 6 and 2+s2=3\frac{-2 + s}{2} = 3.
The midpoint coordinates are the averages of the corresponding coordinates of the endpoints.
2
Solve these equations for rr and ss.
r+10=12    r=2r + 10 = 12 \implies r = 2, and 2+s=6    s=8-2 + s = 6 \implies s = 8.
This determines the coordinates of point AA as (2,2)(2, -2) and point BB as (10,8)(10, 8).
3
Calculate the distance between point A(2,2)A(2, -2) and the origin (0,0)(0, 0) using the distance formula.
d=(20)2+(20)2=4+4=8=22d = \sqrt{(2 - 0)^2 + (-2 - 0)^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2}.
The distance formula is used to find the length of the segment connecting the point to the origin.

Anahtar Kavram

Finding the endpoint of a line segment using the midpoint formula, and then finding the distance between a point and the origin using the distance formula.

Alternatif Yöntem

Instead of solving for the yy-coordinate ss of point BB, we only need the xx-coordinate of AA, which is rr, to find the distance between A(r,2)A(r, -2) and the origin. Since AA's yy-coordinate is already given as 2-2, we only set up the equation for the xx-coordinate of the midpoint: r+102=6\frac{r+10}{2} = 6, which gives r=2r = 2. Thus, AA is (2,2)(2, -2), and the distance is 22+(2)2=22\sqrt{2^2 + (-2)^2} = 2\sqrt{2}. This saves time by not calculating ss.
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