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Zorluk: OrtaOrder of Operations and Number Properties

For all non-zero real numbers aa, bb, and cc, which of the following is equivalent to the expression a(b−c)−b(a−c)c\frac{a(b - c) - b(a - c)}{c}?

  1. b−ab - aCevap
  2. B
    a−ba - b
  3. C
    a+ba + b
  4. D
    ab−a−bab - a - b
  5. E
    2abc−a+b\frac{2ab}{c} - a + b

Cevap

b−ab - a
Applying the distributive property to the numerator yields ab−ac−ba+bcab - ac - ba + bc. Since multiplication is commutative, ba=abba = ab, allowing us to cancel the abab and −ba-ba terms. This leaves bc−acbc - ac in the numerator. Factoring out cc gives c(b−a)c(b - a). Dividing the entire numerator by the denominator cc simplifies the expression to b−ab - a.

Adım Adım Çözüm

1
Apply the distributive property to expand the terms in the numerator.
a(b−c)−b(a−c)=ab−ac−ba+bca(b - c) - b(a - c) = ab - ac - ba + bc
Distribute aa to both bb and −c-c, and distribute −b-b to both aa and −c-c. Remember that multiplying two negative numbers yields a positive result, so −b×−c=bc-b \times -c = bc.
2
Combine like terms in the expanded numerator.
ab−ac−ab+bc=bc−acab - ac - ab + bc = bc - ac
Since multiplication is commutative, ba=abba = ab. Thus, the terms abab and −ab-ab cancel each other out to zero.
3
Factor out the common term cc from the numerator and divide by the denominator cc.
c(b−a)c=b−a\frac{c(b - a)}{c} = b - a
Factoring out cc from bc−acbc - ac gives c(b−a)c(b - a). Dividing by cc cancels the common factor in the numerator and denominator, leaving the simplified expression.

Anahtar Kavram

Order of Operations and Number Properties
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